Return HTTP status code 201 in flask

Question

We re using Flask for one of our API s and I was just wondering if anyone knew how to return a HTTP response 201     For errors such as 404 we can call     from flask import abort  abort 404       But for 201 I get        LookupError  no exception for 201      Do I need to create my own exception like this in the docs

User · Answer

As lacks suggested send status code in return statement and if you are storing it in some variable like

notfound = 404
invalid = 403
ok = 200

and using

return xyz, notfound

than time make sure its type is int not str. as I faced this small issue also here is list of status code followed globally http://www.w3.org/Protocols/HTTP/HTRESP.html

Hope it helps.

User · Answer

You can read about it here   return render template  page html    201

User · Answer

In your flask code  you should ideally specify the MIME type as often as possible  as well   return html page str  200    ContentType   text html    return json dumps   success  True    200    ContentType   application json        etc

User · Answer

Dependent on how the API is created  normally with a 201  created  you would return the resource which was created  For example if it was creating a user account you would do something like   return   data     username    test   id   fdsf345     201   Note the postfixed number is the status code returned   Alternatively  you may want to send a message to the client such as   return   msg    Created Successfully    201

User · Answer

Ripping off Luc s comment here  but to return a blank response  like a 201 the simplest option is to use the following return in your route  return  quot  quot   201  So for example       app route   database   methods   quot PUT quot        def database            update database request          return  quot  quot   201

User · Answer

You can use Response to return any http status code    gt  from flask import Response  gt  return Response    a   b     status 201  mimetype  application json

User · Answer

you can also use flask api for sending response  from flask api import status   app route   your-api    def empty view self       content     your content here       return content  status HTTP 201 CREATED   you can find reference here http   www flaskapi org api-guide status-codes

User · Answer

In my case I had to combine the above in order to make it work  return Response json dumps   Error    Error in payload      status 422   mimetype  application json

User · Answer

You can do result     a    b   return jsonify result   201  if you want to return a JSON data in the response along with the error code You can read about responses here and here for make response API details

User · Answer

So  if you are using flask restful Package for API s returning 201 would becomes like  def bla  args    kwargs               return data  201    where data should be any hashable  JsonSerialiable value  like dict  string

[python] Return HTTP status code 201 in flask

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