Remove truncate leading zeros by javascript jquery

Question

Suggest solution for removing or truncating leading zeros from number any string  by javascript jquery

User · Answer

I got this solution for truncating leading zeros number or any string  in javascript    lt script language  JavaScript  type  text javascript  gt   lt  -- function trimNumber s      while  s substr 0 1      0   amp  amp  s length gt 1    s   s substr 1 9999       return s     var s1    00123   var s2    000assa   var s3    assa34300   var s4    ssa   var s5    121212000    alert s1         trimNumber s1    alert s2         trimNumber s2    alert s3         trimNumber s3    alert s4         trimNumber s4    alert s5         trimNumber s5       end hiding contents -- gt   lt  script gt

User · Answer

You can use a regular expression that matches zeroes at the beginning of the string   s   s replace   0

User · Answer

parseInt value  or parseFloat value    This will work nicely

User · Answer

I would use the Number   function   var str    00001   str   Number str  toString       gt  gt   1    Or I would multiply my string by 1  var str    00000000002346301625363   str    str   1  toString       gt  gt   2346301625363

User · Answer

Maybe a little late  but I want to add my 2 cents   if your string ALWAYS represents a number  with possible leading zeros  you can simply cast the string to a number by using the     operator   e g   x   00005   alert typeof x      string  alert x      00005   x    x     or x    00005     do NOT confuse with x  x  which will only concatenate the value alert typeof x     number   voila  alert x      5  as number    if your string doesn t represent a number and you only need to remove the 0 s use the other solutions  but if you only need them as number  this is the shortest way   and FYI you can do the opposite  force numbers to act as strings if you concatenate an empty string to them  like   x   5  alert typeof x     number x   x     alert typeof x     string   hope it helps somebody

User · Answer

One another way without regex   function trimLeadingZerosSubstr str        var xLastChr   str length - 1  xChrIdx   0      while  str xChrIdx       0   amp  amp  xChrIdx  lt  xLastChr            xChrIdx              return xChrIdx  gt  0   str substr xChrIdx    str      With short string it will be more faster than regex  jsperf

User · Answer

You should use the  radix  parameter of the  parseInt  function   https   developer mozilla org en-US docs Web JavaScript Reference Global Objects parseInt redirectlocale en-US amp redirectslug JavaScript 2FReference 2FGlobal Objects 2FparseInt   parseInt  015   10     15  if you don t use it  some javascript engine might use it as an octal parseInt  015      0

User · Answer

If number is int use       parseInt str    If the number is float use       parseFloat str

User · Answer

Simply try to multiply by one as following       00123    1   nbsp  nbsp  nbsp  nbsp  nbsp  nbsp  nbsp  nbsp  nbsp  nbsp  nbsp  nbsp     Get as number       00123    1        nbsp  nbsp  nbsp  nbsp  nbsp     Get as string

User · Answer

const input    0093   const match   input match    0    d       const result   match  amp  amp  match 2     input

User · Answer

Since you said  any string   I m assuming this is a string you want to handle  too    00012  34 0000432    0035    So  regex is the way to go   var trimmed   s replace   b0  g         And this will prevent loss of a  000000  value   var trimmed   s replace   b 0    b    g        You can see a working example here

User · Answer

Try this      function ltrim str  chars            chars   chars       s           return str replace new RegExp        chars          g                    var str  ltrim  01545878   0      More here

[javascript] Remove/ truncate leading zeros by javascript/jquery

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