C printf a float value

Question

I want to print a float value which has 2 integer digits and 6 decimal digits after the comma  If I just use printf   f   myFloat  I m getting a truncated value   I don t know if this always happens in C  or it s just because I m using C for microcontrollers  CCS to be exact   but at the reference it tells that  f get just that  a truncated float   If my float is 44 556677  I m printing out  44 55   only the first two decimal digits   So the question is    how can I print my 6 digits  and just the six of them  just in case I m having zeros after that or something

User · Accepted Answer

You can do it like this   printf    6f   myFloat     6 represents the number of digits after the decimal separator

User · Answer

Try these to clarify the issue of right alignment in float point printing printf  quot  4  4 1lf n quot   8 9   printf  quot 04  04 1lf n quot   8 9    the output is  4  8 9 04 08 9

User · Answer

You need to use  2 6f instead of  f in your printf statement

User · Answer

printf   9 6f   myFloat  specifies a format with 9 total characters  2 digits before the dot  the dot itself  and six digits after the dot

User · Answer

Use   6f  This will print 6 decimals

User · Answer

printf   0k yf  float variable name    Here k is the total number of characters you want to get printed  k   x   1   y    1 for the dot  and float variable name is the float variable that you want to get printed   Suppose you want to print x digits before the decimal point and y digits after it  Now  if the number of digits before float variable name is less than x  then it will automatically prepend that many zeroes before it

User · Answer

printf     lt number gt f   myFloat    where  lt number gt  - digit after comma   http   www cplusplus com reference clibrary cstdio printf

[c] C: printf a float value

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