[python] Convert string to ASCII value python

How would you convert a string to ASCII values?

For example, "hi" would return 104105.

I can individually do ord('h') and ord('i'), but it's going to be troublesome when there are a lot of letters.

def stringToNumbers(ord(message)):
    return stringToNumbers
    stringToNumbers.append = (ord[0])
    stringToNumbers = ("morocco")

you can actually do it with numpy:

import numpy as np
a = np.fromstring('hi', dtype=np.uint8)
print(a)

your description is rather confusing; directly concatenating the decimal values doesn't seem useful in most contexts. the following code will cast each letter to an 8-bit character, and THEN concatenate. this is how standard ASCII encoding works

def ASCII(s):
    x = 0
    for i in xrange(len(s)):
        x += ord(s[i])*2**(8 * (len(s) - i - 1))
    return x

If you want your result concatenated, as you show in your question, you could try something like:

>>> reduce(lambda x, y: str(x)+str(y), map(ord,"hello world"))
'10410110810811132119111114108100'

It is not at all obvious why one would want to concatenate the (decimal) "ascii values". What is certain is that concatenating them without leading zeroes (or some other padding or a delimiter) is useless -- nothing can be reliably recovered from such an output.

>>> tests = ["hi", "Hi", "HI", '\x0A\x29\x00\x05']
>>> ["".join("%d" % ord(c) for c in s) for s in tests]
['104105', '72105', '7273', '104105']

Note that the first 3 outputs are of different length. Note that the fourth result is the same as the first.

>>> ["".join("%03d" % ord(c) for c in s) for s in tests]
['104105', '072105', '072073', '010041000005']
>>> [" ".join("%d" % ord(c) for c in s) for s in tests]
['104 105', '72 105', '72 73', '10 41 0 5']
>>> ["".join("%02x" % ord(c) for c in s) for s in tests]
['6869', '4869', '4849', '0a290005']
>>>

Note no such problems.

Here is a pretty concise way to perform the concatenation:

>>> s = "hello world"
>>> ''.join(str(ord(c)) for c in s)
'10410110810811132119111114108100'

And a sort of fun alternative:

>>> '%d'*len(s) % tuple(map(ord, s))
'10410110810811132119111114108100'

If you are using python 3 or above,

>>> list(bytes(b'test'))
[116, 101, 115, 116]