[linux] How to get overall CPU usage (e.g. 57%) on Linux

I am wondering how you can get the system CPU usage and present it in percent using bash, for example.

Sample output:

57%

In case there is more than one core, it would be nice if an average percentage could be calculated.

You can try:

top -bn1 | grep "Cpu(s)" | \
           sed "s/.*, *\([0-9.]*\)%* id.*/\1/" | \
           awk '{print 100 - $1"%"}'

EDITED: I noticed that in another user's reply %idle was field 12 instead of field 11. The awk has been updated to account for the %idle field being variable.

This should get you the desired output:

mpstat | awk '$3 ~ /CPU/ { for(i=1;i<=NF;i++) { if ($i ~ /%idle/) field=i } } $3 ~ /all/ { print 100 - $field }'

If you want a simple integer rounding, you can use printf:

mpstat | awk '$3 ~ /CPU/ { for(i=1;i<=NF;i++) { if ($i ~ /%idle/) field=i } } $3 ~ /all/ { printf("%d%%",100 - $field) }'

Try mpstat from the sysstat package

> sudo apt-get install sysstat
Linux 3.0.0-13-generic (ws025)  02/10/2012  _x86_64_    (2 CPU)  

03:33:26 PM  CPU    %usr   %nice    %sys %iowait    %irq   %soft  %steal  %guest   %idle
03:33:26 PM  all    2.39    0.04    0.19    0.34    0.00    0.01    0.00    0.00   97.03

Then some cutor grepto parse the info you need:

mpstat | grep -A 5 "%idle" | tail -n 1 | awk -F " " '{print 100 -  $ 12}'a

Take a look at cat /proc/stat

grep 'cpu ' /proc/stat | awk '{usage=($2+$4)*100/($2+$4+$5)} END {print usage "%"}'

EDIT please read comments before copy-paste this or using this for any serious work. This was not tested nor used, it's an idea for people who do not want to install a utility or for something that works in any distribution. Some people think you can "apt-get install" anything.

NOTE: this is not the current CPU usage, but the overall CPU usage in all the cores since the system bootup. This could be very different from the current CPU usage. To get the current value top (or similar tool) must be used.

Current CPU usage can be potentially calculated with:

awk '{u=$2+$4; t=$2+$4+$5; if (NR==1){u1=u; t1=t;} else print ($2+$4-u1) * 100 / (t-t1) "%"; }' \
<(grep 'cpu ' /proc/stat) <(sleep 1;grep 'cpu ' /proc/stat)

Might as well throw up an actual response with my solution, which was inspired by Peter Liljenberg's:

$ mpstat | awk '$12 ~ /[0-9.]+/ { print 100 - $12"%" }'
0.75%

This will use awk to print out 100 minus the 12th field (idle), with a percentage sign after it. awk will only do this for a line where the 12th field has numbers and dots only ($12 ~ /[0-9]+/).

You can also average five samples, one second apart:

$ mpstat 1 5 | awk 'END{print 100-$NF"%"}'

Test it like this:

$ mpstat 1 5 | tee /dev/tty | awk 'END{print 100-$NF"%"}'