lista = list.sort(lista)
This should be
lista.sort()
The .sort() method is in-place, and returns None. If you want something not in-place, which returns a value, you could use
sorted_list = sorted(lista)
Aside #1: please don't call your lists list. That clobbers the builtin list type.
Aside #2: I'm not sure what this line is meant to do:
print str("value 1a")+str(" + ")+str("value 2")+str(" = ")+str("value 3a ")+str("value 4")+str("\n")
is it simply
print "value 1a + value 2 = value 3a value 4"
? In other words, I don't know why you're calling str on things which are already str.
Aside #3: sometimes you use print("something") (Python 3 syntax) and sometimes you use print "something" (Python 2). The latter would give you a SyntaxError in py3, so you must be running 2.*, in which case you probably don't want to get in the habit or you'll wind up printing tuples, with extra parentheses. I admit that it'll work well enough here, because if there's only one element in the parentheses it's not interpreted as a tuple, but it looks strange to the pythonic eye..
The exception TypeError: 'NoneType' object is not subscriptable happens because the value of lista is actually None. You can reproduce TypeError that you get in your code if you try this at the Python command line:
None[0]
The reason that lista gets set to None is because the return value of list.sort() is None... it does not return a sorted copy of the original list. Instead, as the documentation points out, the list gets sorted in-place instead of a copy being made (this is for efficiency reasons).
If you do not want to alter the original version you can use
other_list = sorted(lista)