Is it possible to convert char to char in C

Question

I m doing an assignment where we have to read a series of strings from a file into an array  I have to call a cipher algorithm on the array  cipher transposes 2D arrays   So  at first I put all the information from the file into a 2D array  but I had a lot of trouble with conflicting types in the rest of my code  specifically trying to set char   to char    So  I decided to switch to an array of pointers  which made everything a lot easier in most of my code   But now I need to convert char  to char   and back again  but I can t figure it out  I haven t been able to find anything on google  I m starting to wonder if it s even possible

User · Answer

Well  I m not sure to understand your question     In C  Char   and Char  are the same thing   Edit   thanks for this interesting link

User · Answer

If you have  char   c then you can do char  d    amp c 0  and access element c 1  by doing   d 1   etc

User · Answer

You don t need to declare them as arrays if you want to use use them as pointers  You can simply reference pointers as if they were multi-dimensional arrays  Just create it as a pointer to a pointer and use malloc   int i  int M 30  N 25  int    buf  buf    int    malloc M   sizeof int     for i 0 i lt M i        buf i     int   malloc N   sizeof int      and then you can reference buf 3  5  or whatever

User · Answer

It sounds like you re confused between pointers and arrays  Pointers and arrays  in this case char   and char     are not the same thing     An array char a SIZE  says that the value at the location of a is an array of length SIZE A pointer char  a  says that the value at the location of a is a pointer to a char  This can be combined with pointer arithmetic to behave like an array  eg  a 10  is 10 entries past wherever a points    In memory  it looks like this  example taken from the FAQ     char a      hello       array      --- --- --- --- --- ---  a    h   e   l   l   o   0       --- --- --- --- --- ---    char  p    world      pointer      -----       --- --- --- --- --- ---  p             gt    w   o   r   l   d   0       -----       --- --- --- --- --- ---    It s easy to be confused about the difference between pointers and arrays  because in many cases  an array reference  decays  to a pointer to it s first element  This means that in many cases  such as when passed to a function call  arrays become pointers  If you d like to know more  this section of the C FAQ describes the differences in detail   One major practical difference is that the compiler knows how long an array is  Using the examples above   char a      hello     char  p     world      sizeof a      6 - one byte for each character in the string                one for the   0  terminator sizeof p      whatever the size of the pointer is               probably 4 or 8 on most machines  depending on whether it s a                32 or 64 bit machine    Without seeing your code  it s hard to recommend the best course of action  but I suspect changing to use pointers everywhere will solve the problems you re currently having  Take note that now    You will need to initialise memory wherever the arrays used to be  Eg  char a 10   will become char  a   malloc 10   sizeof char     followed by a check that a    NULL  Note that you don t actually need to say sizeof char  in this case  because sizeof char  is defined to be 1  I left it in for completeness  Anywhere you previously had sizeof a  for array length will need to be replaced by the length of the memory you allocated  if you re using strings  you could use strlen    which counts up to the   0    You will need a make a corresponding call to free   for each call to malloc    This tells the computer you are done using the memory you asked for with malloc    If your pointer is a  just write free a   at a point in the code where you know you no longer need whatever a points to    As another answer pointed out  if you want to get the address of the start of an array  you can use   char  p    amp a 0     You can read this as  char pointer p becomes the address of element  0  of a

[c] Is it possible to convert char[] to char* in C?

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