I'm doing an assignment where we have to read a series of strings from a file into an array. I have to call a cipher algorithm on the array (cipher transposes 2D arrays). So, at first I put all the information from the file into a 2D array, but I had a lot of trouble with conflicting types in the rest of my code (specifically trying to set char[] to char*). So, I decided to switch to an array of pointers, which made everything a lot easier in most of my code.
But now I need to convert char* to char[] and back again, but I can't figure it out. I haven't been able to find anything on google. I'm starting to wonder if it's even possible.
Well, I'm not sure to understand your question...
In C, Char[] and Char* are the same thing.
Edit : thanks for this interesting link.
If you have
char[] c
then you can do
char* d = &c[0]
and access element c[1] by doing *(d+1), etc.
You don't need to declare them as arrays if you want to use use them as pointers. You can simply reference pointers as if they were multi-dimensional arrays. Just create it as a pointer to a pointer and use malloc:
int i;
int M=30, N=25;
int ** buf;
buf = (int**) malloc(M * sizeof(int*));
for(i=0;i<M;i++)
buf[i] = (int*) malloc(N * sizeof(int));
and then you can reference buf[3][5] or whatever.
Source: Stackoverflow.com