I prefer to use this:
final protected static char[] hexArray = "0123456789ABCDEF".toCharArray();
public static String bytesToHex(byte[] bytes, int offset, int count) {
char[] hexChars = new char[count * 2];
for ( int j = 0; j < count; j++ ) {
int v = bytes[j+offset] & 0xFF;
hexChars[j * 2] = hexArray[v >>> 4];
hexChars[j * 2 + 1] = hexArray[v & 0x0F];
}
return new String(hexChars);
}
It is slightly more flexible adaptation of the accepted answer. Personally, I keep both the accepted answer and this overload along with it, usable in more contexts.