[python] Python function global variables?

I know I should avoid using global variables in the first place due to confusion like this, but if I were to use them, is the following a valid way to go about using them? (I am trying to call the global copy of a variable created in a separate function.)

x = "somevalue"

def func_A ():
   global x
   # Do things to x
   return x

def func_B():
   x = func_A()
   # Do things
   return x

func_A()
func_B()

Does the x that the second function uses have the same value of the global copy of x that func_a uses and modifies? When calling the functions after definition, does order matter?

You can directly access a global variable inside a function. If you want to change the value of that global variable, use "global variable_name". See the following example:

var = 1
def global_var_change():
      global var
      var = "value changed"
global_var_change() #call the function for changes
print var

Generally speaking, this is not a good programming practice. By breaking namespace logic, code can become difficult to understand and debug.

Here is one case that caught me out, using a global as a default value of a parameter.

globVar = None    # initialize value of global variable

def func(param = globVar):   # use globVar as default value for param
    print 'param =', param, 'globVar =', globVar  # display values

def test():
    global globVar
    globVar = 42  # change value of global
    func()

test()
=========
output: param = None, globVar = 42

I had expected param to have a value of 42. Surprise. Python 2.7 evaluated the value of globVar when it first parsed the function func. Changing the value of globVar did not affect the default value assigned to param. Delaying the evaluation, as in the following, worked as I needed it to.

def func(param = eval('globVar')):       # this seems to work
    print 'param =', param, 'globVar =', globVar  # display values

Or, if you want to be safe,

def func(param = None)):
    if param == None:
        param = globVar
    print 'param =', param, 'globVar =', globVar  # display values

Within a Python scope, any assignment to a variable not already declared within that scope creates a new local variable unless that variable is declared earlier in the function as referring to a globally scoped variable with the keyword global.

Let's look at a modified version of your pseudocode to see what happens:

# Here, we're creating a variable 'x', in the __main__ scope.
x = 'None!'

def func_A():
  # The below declaration lets the function know that we
  #  mean the global 'x' when we refer to that variable, not
  #  any local one

  global x
  x = 'A'
  return x

def func_B():
  # Here, we are somewhat mislead.  We're actually involving two different
  #  variables named 'x'.  One is local to func_B, the other is global.

  # By calling func_A(), we do two things: we're reassigning the value
  #  of the GLOBAL x as part of func_A, and then taking that same value
  #  since it's returned by func_A, and assigning it to a LOCAL variable
  #  named 'x'.     
  x = func_A() # look at this as: x_local = func_A()

  # Here, we're assigning the value of 'B' to the LOCAL x.
  x = 'B' # look at this as: x_local = 'B'

  return x # look at this as: return x_local

In fact, you could rewrite all of func_B with the variable named x_local and it would work identically.

The order matters only as far as the order in which your functions do operations that change the value of the global x. Thus in our example, order doesn't matter, since func_B calls func_A. In this example, order does matter:

def a():
  global foo
  foo = 'A'

def b():
  global foo
  foo = 'B'

b()
a()
print foo
# prints 'A' because a() was the last function to modify 'foo'.

Note that global is only required to modify global objects. You can still access them from within a function without declaring global. Thus, we have:

x = 5

def access_only():
  return x
  # This returns whatever the global value of 'x' is

def modify():
  global x
  x = 'modified'
  return x
  # This function makes the global 'x' equal to 'modified', and then returns that value

def create_locally():
  x = 'local!'
  return x
  # This function creates a new local variable named 'x', and sets it as 'local',
  #  and returns that.  The global 'x' is untouched.

Note the difference between create_locally and access_only -- access_only is accessing the global x despite not calling global, and even though create_locally doesn't use global either, it creates a local copy since it's assigning a value.

The confusion here is why you shouldn't use global variables.

You must use the global declaration when you wish to alter the value assigned to a global variable.

You do not need it to read from a global variable. Note that calling a method on an object (even if it alters the data within that object) does not alter the value of the variable holding that object (absent reflective magic).

As others have noted, you need to declare a variable global in a function when you want that function to be able to modify the global variable. If you only want to access it, then you don't need global.

To go into a bit more detail on that, what "modify" means is this: if you want to re-bind the global name so it points to a different object, the name must be declared global in the function.

Many operations that modify (mutate) an object do not re-bind the global name to point to a different object, and so they are all valid without declaring the name global in the function.

d = {}
l = []
o = type("object", (object,), {})()

def valid():     # these are all valid without declaring any names global!
   d[0] = 1      # changes what's in d, but d still points to the same object
   d[0] += 1     # ditto
   d.clear()     # ditto! d is now empty but it`s still the same object!
   l.append(0)   # l is still the same list but has an additional member
   o.test = 1    # creating new attribute on o, but o is still the same object