I am trying to construct a std::thread
with a member function that takes no arguments and returns void
. I can't figure out any syntax that works - the compiler complains no matter what. What is the correct way to implement spawn()
so that it returns a std::thread
that executes test()
?
#include <thread>
class blub {
void test() {
}
public:
std::thread spawn() {
return { test };
}
};
This question is related to
c++
multithreading
c++11
Some users have already given their answer and explained it very well.
I would like to add few more things related to thread.
How to work with functor and thread. Please refer to below example.
The thread will make its own copy of the object while passing the object.
#include<thread>
#include<Windows.h>
#include<iostream>
using namespace std;
class CB
{
public:
CB()
{
cout << "this=" << this << endl;
}
void operator()();
};
void CB::operator()()
{
cout << "this=" << this << endl;
for (int i = 0; i < 5; i++)
{
cout << "CB()=" << i << endl;
Sleep(1000);
}
}
void main()
{
CB obj; // please note the address of obj.
thread t(obj); // here obj will be passed by value
//i.e. thread will make it own local copy of it.
// we can confirm it by matching the address of
//object printed in the constructor
// and address of the obj printed in the function
t.join();
}
Another way of achieving the same thing is like:
void main()
{
thread t((CB()));
t.join();
}
But if you want to pass the object by reference then use the below syntax:
void main()
{
CB obj;
//thread t(obj);
thread t(std::ref(obj));
t.join();
}
@hop5 and @RnMss suggested to use C++11 lambdas, but if you deal with pointers, you can use them directly:
#include <thread>
#include <iostream>
class CFoo {
public:
int m_i = 0;
void bar() {
++m_i;
}
};
int main() {
CFoo foo;
std::thread t1(&CFoo::bar, &foo);
t1.join();
std::thread t2(&CFoo::bar, &foo);
t2.join();
std::cout << foo.m_i << std::endl;
return 0;
}
outputs
2
Rewritten sample from this answer would be then:
#include <thread>
#include <iostream>
class Wrapper {
public:
void member1() {
std::cout << "i am member1" << std::endl;
}
void member2(const char *arg1, unsigned arg2) {
std::cout << "i am member2 and my first arg is (" << arg1 << ") and second arg is (" << arg2 << ")" << std::endl;
}
std::thread member1Thread() {
return std::thread(&Wrapper::member1, this);
}
std::thread member2Thread(const char *arg1, unsigned arg2) {
return std::thread(&Wrapper::member2, this, arg1, arg2);
}
};
int main() {
Wrapper *w = new Wrapper();
std::thread tw1 = w->member1Thread();
tw1.join();
std::thread tw2 = w->member2Thread("hello", 100);
tw2.join();
return 0;
}
Since you are using C++11, lambda-expression is a nice&clean solution.
class blub {
void test() {}
public:
std::thread spawn() {
return std::thread( [this] { this->test(); } );
}
};
since this->
can be omitted, it could be shorten to:
std::thread( [this] { test(); } )
or just (deprecated)
std::thread( [=] { test(); } )
Here is a complete example
#include <thread>
#include <iostream>
class Wrapper {
public:
void member1() {
std::cout << "i am member1" << std::endl;
}
void member2(const char *arg1, unsigned arg2) {
std::cout << "i am member2 and my first arg is (" << arg1 << ") and second arg is (" << arg2 << ")" << std::endl;
}
std::thread member1Thread() {
return std::thread([=] { member1(); });
}
std::thread member2Thread(const char *arg1, unsigned arg2) {
return std::thread([=] { member2(arg1, arg2); });
}
};
int main(int argc, char **argv) {
Wrapper *w = new Wrapper();
std::thread tw1 = w->member1Thread();
std::thread tw2 = w->member2Thread("hello", 100);
tw1.join();
tw2.join();
return 0;
}
Compiling with g++ produces the following result
g++ -Wall -std=c++11 hello.cc -o hello -pthread
i am member1
i am member2 and my first arg is (hello) and second arg is (100)
Source: Stackoverflow.com