Completing remark to Jimmy Pena's accepted answer
As SeanC points out, this must be a 1-D array.
The following example call demonstrates that the IsInArray()
function cannot be called only for 1-dim arrays,
but also for "flat" 2-dim arrays:
Sub TestIsInArray()
Const SearchItem As String = "ghi"
Debug.Print "SearchItem = '" & SearchItem & "'"
'----
'a) Test 1-dim array
Dim Arr As Variant
Arr = Split("abc,def,ghi,jkl", ",")
Debug.Print "a) 1-dim array " & vbNewLine & " " & Join(Arr, "|") & " ~~> " & IsInArray(SearchItem, Arr)
'----
'//quick tool to create a 2-dim 1-based array
Dim v As Variant, vals As Variant
v = Array(Array("abc", "def", "dummy", "jkl", 5), _
Array("mno", "pqr", "stu", "ghi", "vwx"))
v = Application.Index(v, 0, 0) ' create 2-dim array (2 rows, 5 cols)
'b) Test "flat" 2-dim arrays
Debug.Print "b) ""flat"" 2-dim arrays "
Dim i As Long
For i = LBound(v) To UBound(v)
'slice "flat" 2-dim arrays of one row each
vals = Application.Index(v, i, 0)
'check for findings
Debug.Print Format(i, " 0"), Join(vals, "|") & " ~~> " & IsInArray(SearchItem, vals)
Next i
End Sub
Function IsInArray(stringToBeFound As String, Arr As Variant) As Boolean
'Site: https://stackoverflow.com/questions/10951687/how-to-search-for-string-in-an-array/10952705
'Note: needs a "flat" array, not necessarily a 1-dimensioned array
IsInArray = (UBound(Filter(Arr, stringToBeFound)) > -1)
End Function
Results in VB Editor's immediate window
SearchItem = 'ghi'
a) 1-dim array
abc|def|ghi|jkl ~~> Wahr
b) "flat" 2-dim arrays
1 abc|def|dummy|jkl|5 False
2 mno|pqr|stu|ghi|vwx True