Amazon S3 upload file and get URL

Question

Is it possible to upload a txt pdf png file to Amazon S3 in a single action  and get the uploaded file URL as the response  If so  is AWS Java SDK the right library that I need to add in my java struts2 web application  Please suggest me a solution for this

User · Answer

You can work it out for yourself given the bucket and the file name you specify in the upload request.

e.g. if your bucket is mybucket and your file is named myfilename:

https://mybucket.s3.amazonaws.com/myfilename

The s3 bit will be different depending on which region your bucket is in. For example, I use the south-east asia region so my urls are like:

https://mybucket.s3-ap-southeast-1.amazonaws.com/myfilename

User · Answer

No you cannot get the URL in single action but two     First of all  you may have to make the file public before uploading because it makes no sense to get the URL that no one can access  You can do so by setting ACL as Michael Astreiko suggested  You can get the resource URL either by calling getResourceUrl or getUrl   AmazonS3Client s3Client    AmazonS3Client AmazonS3ClientBuilder defaultClient    s3Client putObject new PutObjectRequest  your-bucket    some-path some-key jpg   new File  somePath someKey jpg    withCannedAcl CannedAccessControlList PublicRead   s3Client getResourceUrl  your-bucket    some-path some-key jpg      Note1  The different between getResourceUrl and getUrl is that getResourceUrl will return null when exception occurs   Note2  getUrl method is not defined in the AmazonS3 interface  You have to cast the object to AmazonS3Client if you use the standard builder

User · Answer

For AWS SDK 2  String key    quot filePath quot   String bucketName    quot bucketName quot   PutObjectResponse response   s3Client              putObject PutObjectRequest builder   bucket bucketName   key key  build    RequestBody fromFile file     GetUrlRequest request   GetUrlRequest builder   bucket bucketName   key key  build     String url   s3Client utilities   getUrl request  toExternalForm

User · Answer

Similarly if you want link through s3Client you can use below   System out println  filelink      s3Client getUrl  your bucket name    your file key

User · Answer

System out println  Link       s3Object getObjectContent   getHttpRequest   getURI       with this you can retrieve the link of already uploaded file to S3 bucket

User · Answer

a bit old but still for anyone stumbling upon this in the future   you can do it with one line assuming you already wrote the CredentialProvider and the AmazonS3Client    it will look like this    String ImageURL   String valueOf s3 getUrl                                    ConstantsAWS3 BUCKET NAME    The S3 Bucket To Upload To                                   file getName        The key for the uploaded object   and if you didn t wrote the CredentialProvider and the AmazonS3Client then just add them before getting the URL like this     CognitoCachingCredentialsProvider credentialsProvider   new CognitoCachingCredentialsProvider          getApplicationContext             POOL ID      Identity pool ID         Regions US EAST 1    Region

User · Answer

To make the file public before uploading you can use the  withCannedAcl method of PutObjectRequest   myAmazonS3Client putObject new PutObjectRequest  some-grails-bucket     somePath someKey jpg   new    File   Users ben Desktop photo jpg    withCannedAcl CannedAccessControlList PublicRead

User · Answer

hussachai and  Jeffrey Kemp answers are pretty good  But they have something in common is the url returned is of virtual-host-style  not in path style  For more info regarding to the s3 url style  can refer to AWS S3 URL Styles  In case of some people want to have path style s3 url generated  Here s the step  Basically everything will be the same as  hussachai and  Jeffrey Kemp answers  only with one line setting change as below   AmazonS3Client s3Client    AmazonS3Client  AmazonS3ClientBuilder standard                        withRegion  us-west-2                        withCredentials DefaultAWSCredentialsProviderChain getInstance                         withPathStyleAccessEnabled true                       build        Upload a file as a new object with ContentType and title specified  PutObjectRequest request   new PutObjectRequest bucketName  stringObjKeyName  fileToUpload   s3Client putObject request   URL s3Url   s3Client getUrl bucketName  stringObjKeyName   logger info  S3 url is     s3Url toExternalForm       This will generate url like      https   s3 us-west-2 amazonaws com mybucket myfilename

User · Answer

Below method uploads file in a particular folder in a bucket and return the generated url of the file uploaded  private String uploadFileToS3Bucket final String bucketName  final File file        final String uniqueFileName   uploadFolder    quot   quot    file getName        LOGGER info  quot Uploading file with name   quot    uniqueFileName       final PutObjectRequest putObjectRequest   new PutObjectRequest bucketName  uniqueFileName  file       amazonS3 putObject putObjectRequest       return   AmazonS3Client  amazonS3  getResourceUrl bucketName  uniqueFileName

[java] Amazon S3 upload file and get URL

Examples related to java

Examples related to amazon-s3

Examples related to amazon-web-services