Replace new line return with space using regex

Question

Pretty basic question for someone who knows   Instead of getting from     This is my text    And here is a new line    To    This is my text  And here is a new line    I get    This is my text And here is a new line    Any idea why   L replaceAll      t    n    r       s      I think I found the culprit   On the next line I do the following   L replaceAll     a-zA-Z0-9             s           And this seems to be causing my issue   Any idea why   I am obviously trying to do the following  remove all non-chars  and remove all new lines

User · Answer

The new line separator is different for different OS-es - '\r\n' for Windows and '\n' for Linux.

To be safe, you can use regex pattern \R - the linebreak matcher introduced with Java 8:

String inlinedText = text.replaceAll("\\R", " ");

User · Answer

Try  L replaceAll     t   r   n             Depending on the system a linefeed is either  r n or just  n

User · Answer

I found this   String newString   string replaceAll   n           Although  as you have a double line  you will get a double space  I guess you could then do another replace all to replace double spaces with a single one   If that doesn t work try doing   string replaceAll System getProperty  line separator            If I create lines in  string  by using   n  I had to use   n  in the regex  If I used System getProperty   I had to use that

User · Answer

This should take care of space  tab and newline  data   data replaceAll  quot    t n r   quot    quot   quot

User · Answer

s is a shortcut for whitespace characters in regex  It has no meaning in a string      You can t use it in your replacement string  There you need to put exactly the character s  that you want to insert  If this is a space just use     as replacement   The other thing is  Why do you use 3 backslashes as escape sequence  Two are enough in Java  And you don t need a    alternation operator  in a character class   L replaceAll     t  n  r            Remark  L is not changed  If you want to have a result you need to do  String result       L replaceAll     t  n  r            Test code   String in    This is my text  n nAnd here is a new line   System out println in    String out   in replaceAll     t  n  r          System out println out

User · Answer

You May use first split and rejoin it using white space  it will work sure   String   Larray   L split     n      L       for int i   0  i lt Larray lengh  i        L   L     Larray i

User · Answer

Your regex is good altough I would replace it with the empty string  String resultString   subjectString replaceAll    t n r           You expect a space between  text   and  And  right   I get that space when I try the regex by copying your sample   This is my text      So all is well here  Maybe if you just replace it with the empty string it will work  I don t know why you replace it with  s  And the alternation   is not necessary in a character class

[java] Replace new line/return with space using regex

Examples related to java

Examples related to regex