Hi I just started learning Python but I'm sort of stuck right now.
I have hash.txt file containing thousands of malware hashes in MD5, Sha1 and Sha5 respectively separated by delimiters in each line. Below are 2 examples lines I extracted from the .txt file.
416d76b8811b0ddae2fdad8f4721ddbe|d4f656ee006e248f2f3a8a93a8aec5868788b927|12a5f648928f8e0b5376d2cc07de8e4cbf9f7ccbadb97d898373f85f0a75c47f 56a99a4205a4d6cab2dcae414a5670fd|612aeeeaa8aa432a7b96202847169ecae56b07ee|d17de7ca4c8f24ff49314f0f342dbe9243b10e9f3558c6193e2fd6bccb1be6d2
My intention is to display the first 32 characters (MD5 hash) so the output will look something like this:
416d76b8811b0ddae2fdad8f4721ddbe 56a99a4205a4d6cab2dcae414a5670fd
Any ideas?
This question is related to
python
python-2.7
You can 'slice' a string very easily, just like you'd pull items from a list:
a_string = 'This is a string'
To get the first 4 letters:
first_four_letters = a_string[:4]
>>> 'This'
Or the last 5:
last_five_letters = a_string[-5:]
>>> 'string'
So applying that logic to your problem:
the_string = '416d76b8811b0ddae2fdad8f4721ddbe|d4f656ee006e248f2f3a8a93a8aec5868788b927|12a5f648928f8e0b5376d2cc07de8e4cbf9f7ccbadb97d898373f85f0a75c47f '
first_32_chars = the_string[:32]
>>> 416d76b8811b0ddae2fdad8f4721ddbe
Since there is a delimiter, you should use that instead of worrying about how long the md5 is.
>>> s = "416d76b8811b0ddae2fdad8f4721ddbe|d4f656ee006e248f2f3a8a93a8aec5868788b927|12a5f648928f8e0b5376d2cc07de8e4cbf9f7ccbadb97d898373f85f0a75c47f"
>>> md5sum, delim, rest = s.partition('|')
>>> md5sum
'416d76b8811b0ddae2fdad8f4721ddbe'
Alternatively
>>> md5sum, sha1sum, sha5sum = s.split('|')
>>> md5sum
'416d76b8811b0ddae2fdad8f4721ddbe'
>>> sha1sum
'd4f656ee006e248f2f3a8a93a8aec5868788b927'
>>> sha5sum
'12a5f648928f8e0b5376d2cc07de8e4cbf9f7ccbadb97d898373f85f0a75c47f'
If you want first 2 letters and last 2 letters of a string then you can use the following code:
name = "India"
name[0:2]="In"
names[-2:]="ia"
Source: Stackoverflow.com