Check if string ends with certain pattern

Question

If I have a string like   This is a great place too work    or   This is a great place too work    than my program should give me that the sentence is valid and it has  work     If I Have    This is a great place too work hahahha   or   This is a great place too work hahahah   then my program should not give me that there is a  work  in the sentence    So I am looking at java strings to find a word at the end of the sentence having   or   or   before it  How can I achieve this

User · Answer

You can use the substring method             String aString    This is a great place too work       String aSubstring    work      String endString   aString substring aString length   -           aSubstring length     1  aString length   - 1      if   endString equals aSubstring           System out println  Equal     aString         aSubstring      else        System out println  NOT equal     aString         aSubstring

User · Answer

I tried all the different things mentioned here to get the index of the   character in a filename that ends with   0-9  0-9    e g  srcfile 1  srcfile 12  etc  Nothing worked  Finally  the following worked   int dotIndex   inputfilename lastIndexOf        Weird  This is with java -version   openjdk version  1 8 0 131  OpenJDK Runtime Environment  build 1 8 0 131-8u131-b11-0ubuntu1 16 10 2-b11  OpenJDK 64-Bit Server VM  build 25 131-b11  mixed mode    Also  the official Java doc page for regex  from which there is a quote in one of the answers above  does not seem to specify how to look for the   character  Because          and     did not work for me  and I don t see any other options specified apart from these

User · Answer

You can test if a string ends with work followed by one character like this   theString matches    work        If the trailing character is optional you can use this   theString matches    work         To make sure the last character is a period   or a slash   you can use this   theString matches    work           To test for work followed by an optional period or slash you can use this   theString matches    work            To test for work surrounded by periods or slashes  you could do this   theString matches        work           If the tokens before and after work must match each other  you could do this   theString matches          work  1         Your exact requirement isn t precisely defined  but I think it would be something like this   theString matches    work             In other words    zero or more characters followed by work followed by zero or one     OR   followed by the end of the input     Explanation of various regex items                   --  any character                 --  zero or more of the preceeding expression                 --  the end of the line input                 --  zero or one of the preceeding expression                 --  either a period or a slash or a comma  abc            --  matches a  b  or c  abc            --  zero or more of  a  b  or c   abc            --  zero or one of  a  b  or c   enclosing a pattern in parentheses is called  grouping     abc  blah  1  --  a  b  or c followed by blah followed by  the first group      Here s a test harness to play with   class TestStuff        public static void main  String   args             String   testStrings                       work                     work-                    workp                     foo work                      bar work                    baz work                     baz funk work                     funk work                    jazz junk foo work                     funk punk work                      funk foo bar work                     funk foo bar work                      funk foo bar work                      funk foo bar work                    goo balls work                     goo balls work funk                      for  String t   testStrings                print  word      t      --- gt       matchesIt t                         public static boolean matchesIt String s            return s matches           work  1                 public static void print Object o            String s    o    null     null    o toString            System out println o

User · Answer

This is really simple  the String object has an endsWith method   From your question it seems like you want either      or   as the delimiter set    So   String str    This is a great place to work     if  str endsWith   work       str endsWith   work       str endsWith   work                    You can also do this with the matches method and a fairly simple regex   if  str matches           work  1       Using the character class       specifying either a period  a slash  or a comma  and a backreference   1 that matches whichever of the alternates were found  if any

User · Answer

String input1    quot This is a great place too work  quot       String input2    quot This is a great place too work  quot       String input3    quot This is a great place too work  quot       String input4    quot This is a great place too work hahahah quot       String input5    quot This is a great place too work hahaha quot       String input6    quot This is a great place too work hahahha quot            String regEx    quot   work      quot            System out println input1 matches regEx       true     System out println input2 matches regEx       true     System out println input3 matches regEx       true     System out println input4 matches regEx       false     System out println input5 matches regEx       false     System out println input6 matches regEx       false

User · Answer

Of course you can use the StringTokenizer class to split the String with     or      and check if the last word is  work

[java] Check if string ends with certain pattern

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