While generating the private key using this command
genrsa -out my-prvkey.pem 1024
It throws the error like below
Loadind 'screen' into random state -done Generating RSA private key,1024 bit long modulus .........................................+++++++ ...........................+++++++++ unable to write 'random state' e is 65537 (0*10001)
This makes any problem while creating a public certificate. I'm running this command in windows. Can anyone help me for the fix?
just enter this line in the command line :
set RANDFILE=.rnd
Or this in windows powershell
$env:RANDFILE=".rnd"
It may also be that you need to run the console as an administrator. On windows 7, hold ctrl+shift when you launch the console window.
Download openssl for windows from https://code.google.com/archive/p/openssl-for-windows/downloads
Set Environment variable to the path variable as path="C:\your_folder\openssl-0.9.8k_X64\bin"
I did not find where the .rnd file is so I ran the cmd as administrator and it worked like a charm.
The quickest solution is: set environment variable RANDFILE to path where the 'random state' file can be written (of course check the file access permissions), eg. in your command prompt:
set RANDFILE=C:\MyDir\.rnd
openssl genrsa -out my-prvkey.pem 1024
More explanations: OpenSSL on Windows tries to save the 'random state' file in the following order:
I'm pretty sure that in your case it ends up trying to save it in C:\.rnd (and it fails because lack of sufficient access rights). Unfortunately OpenSSL does not print the path that is actually tries to use in any error messages.
Source: Stackoverflow.com