[sql] oracle SQL how to remove time from date

I have a column named StartDate containing a date in this format: 03-03-2012 15:22

What I need is to convert it to date. It should be looking like this: DD/MM/YYYY

What I have tried without success is:

select 
p1.PA_VALUE as StartDate,
p2.PA_VALUE as EndDate
from WP_Work p 
LEFT JOIN PARAMETER p1 on p1.WP_ID=p.WP_ID AND p1.NAME = 'StartDate'
LEFT JOIN PARAMETER p2 on p2.WP_ID=p.WP_ID AND p2.NAME = 'Date_To'
WHERE p.TYPE = 'EventManagement2'
AND TO_DATE(p1.PA_VALUE, 'DD/MM/YYYY') >= TO_DATE('25/10/2012', 'DD/MM/YYYY')
AND TO_DATE(p2.PA_VALUE, 'DD/MM/YYYY') <= TO_DATE('26/10/2012', 'DD/MM/YYYY')

Is there a way to do this?

EDIT1: the PA_VALUE column is: VARCHAR2

You can use TRUNC on DateTime to remove Time part of the DateTime. So your where clause can be:

AND TRUNC(p1.PA_VALUE) >= TO_DATE('25/10/2012', 'DD/MM/YYYY')

The TRUNCATE (datetime) function returns date with the time portion of the day truncated to the unit specified by the format model.

If your column with DATE datatype has value like below : -

value in column : 10-NOV-2005 06:31:00

Then, You can Use TRUNC function in select query to convert your date-time value to only date like - DD/MM/YYYY or DD-MON-YYYY

select TRUNC(column_1) from table1;

result : 10-NOV-2005

You will see above result - Provided that NLS_DATE_FORMAT is set as like below :-

Alter session NLS_DATE_FORMAT = 'DD-MON-YYYY HH24:MI:SS';

Try

SELECT to_char(p1.PA_VALUE,'DD/MM/YYYY') as StartDate,
       to_char(p2.PA_VALUE,'DD/MM/YYYY') as EndDate
   ...

We can use TRUNC function in Oracle DB. Here is an example.

SELECT TRUNC(TO_DATE('01 Jan 2018 08:00:00','DD-MON-YYYY HH24:MI:SS')) FROM DUAL

Output: 1/1/2018