[regex] Regex number between 1 and 100

I searched a lot and can't find the solution for this RegExp (I have to say I'm not very experienced in Reg. Expressions).

Regex = ^[1-9]?[0-9]{1}$|^100$

I would like to test a number between 1 and 100, excluding 0

This seems a better solution to use if statement :

num = 55
if num <= 100 and num >= 1:
    print("OK")
else:
    print("NOPE")

I use for this angular 6

try this.

^([0-9]\.[0-9]{1}|[0-9]\.[0-9]{2}|\.[0-9]{2}|[1-9][0-9]\.[0-9]{1}|[1-9][0-9]\.[0-9]{2}|[0-9][0-9]|[1-9][0-9]\.[0-9]{2})$|^([0-9]|[0-9][0-9]|[0-99])$|^100$

it's validate 0.00 - 100. with two decimal places.

hope this will help

<input matInput [(ngModel)]="commission" type="number" max="100" min="0" name="rateInput" pattern="^(\.[0-9]{2}|[0-9]\.[0-9]{2}|[0-9][0-9]|[1-9][0-9]\.[0-9]{2})$|^([0-9]|[0-9][0-9]|[0-99])$|^100$" required #rateInput2="ngModel"><span>%</span><br>

Number should be between 0 and 100

If one assumes he really needs regexp - which is perfectly reasonable in many contexts - the problem is that the specific regexp variety needs to be specified. For example:

egrep '^(100|[1-9]|[1-9][0-9])$'
grep -E '^(100|[1-9]|[1-9][0-9])$'

work fine if the (...|...) alternative syntax is available. In other contexts, they'd be backslashed like \(...\|...\)

Just for the sake of delivering the shortest solution, here is mine:

^([1-9]\d?|100)$

working fiddle

Regular Expression for 0 to 100 with the decimal point.

^100(\.[0]{1,2})?|([0-9]|[1-9][0-9])(\.[0-9]{1,2})?$

This is very simple logic, So no need of regx.

Instead go for using ternary operator

var num = 89;
var isValid = (num <=  100 && num > 0 ) ? true : false;

It will do the magic for you!!

For integers from 1 to 100 with no preceding 0 try:

^[1-9]$|^[1-9][0-9]$|^(100)$

For integers from 0 to 100 with no preceding 0 try:

^[0-9]$|^[1-9][0-9]$|^(100)$

Regards

Try it, This will work more efficiently.. 1. For number ranging 00 - 99.99 (decimal inclusive)

^([0-9]{1,2}){1}(\.[0-9]{1,2})?$ 

Working fiddle link

https://regex101.com/r/d1Kdw5/1/

2.For number ranging 1-100(inclusive) with no preceding 0.

(?:\b|-)([1-9]{1,2}[0]?|100)\b

Working Fiddle link

http://regex101.com/r/mN1iT5/6

1 - 1000 with leading 0's

/^0*(?:[1-9][0-9][0-9]?|[1-9]|1000)$/;

it should not accept 0, 00, 000, 0000.

it should accept 1, 01, 001, 0001

Here are simple regex to understand (verified, and no preceding 0)

Between 0 to 100 (Try it here):

^(0|[1-9][0-9]?|100)$

Between 1 to 100 (Try it here):

^([1-9][0-9]?|100)$

There are many options how to write a regex pattern for that

• ^(?:(?!0)\d{1,2}|100)$
• ^(?:[1-9]\d?|100)$
• ^(?!0)(?=100$|..$|.$)\d+$

between 0 and 100

/^(\d{1,2}|100)$/

or between 1 and 100

/^([1-9]{1,2}|100)$/