finding multiples of a number in Python

Question

I m trying to write a code that lets me find the first few multiples of a number  This is one of my attempts   def printMultiples n  m   for m in  n m       print n  end          I figured out that  by putting for m in  n  m    it would run through the loop for whatever number was m   def printMultiples n  m    takes n and m as integers and finds all first m multiples of n  for m in  n m       if n   2    0          while n  lt  0              print n    After multiple searches  I was only able to find a sample code in java  so I tried to translate that into python  but I didn t get any results  I have a feeling I should be using the range   function somewhere in this  but I have no idea where

User · Answer

If this is what you are looking for -

To find all the multiples between a given number and a limit

def find_multiples(integer, limit):
    return list(range(integer,limit+1, integer))

This should return -

Test.assert_equals(find_multiples(5, 25), [5, 10, 15, 20, 25])

User · Answer

If you re trying to find the first count multiples of m  something like this would work   def multiples m  count       for i in range count           print i m    Alternatively  you could do this with range   def multiples m  count       for i in range 0 count m m           print i    Note that both of these start the multiples at 0 - if you wanted to instead start at m  you d need to offset it by that much   range m  count 1  m m

User · Answer

For the first ten multiples of 5  say   gt  gt  gt   5 n for n in range 1 10 1    5  10  15  20  25  30  35  40  45  50

User · Answer

def multiples n m starting from 1 increment by 1                 Where n is the number 10 and m is the number 2 from your example         In case you want to print the multiples starting from some other number other than 1 then you could use the starting from parameter       In case you want to print every 2nd multiple or every 3rd multiple you could change the increment by              print   n x for x in range starting from m 1 increment by

User · Answer

Does this do what you want   print range 0   m 1  n  n  1     For m 5  n 20   20  40  60  80  100    Or better yet    gt  gt  gt  print range n   m 1  n  n   20  40  60  80  100     For Python3    gt  gt  gt  print list range n   m 1  n  n     20  40  60  80  100

User · Answer

Based on mathematical concepts  I understand that    all natural numbers that  divided by n  having 0 as remainder  are all multiples of n   Therefore  the following calculation also applies as a solution  multiples between 1 and 100     gt  gt  gt  multiples 5    n for n in range 1  101  if n   5    0   gt  gt  gt  multiples 5  5  10  15  20  25  30  35  40  45  50  55  60  65  70  75  80  85  90  95  100    For further reading    https   www mathsisfun com definitions natural-number html https   www mathwizz com arithmetic help help9 htm https   www calculatorsoup com calculators math multiples php

User · Answer

You can do   def mul table n i 1       print n i      if i   10          mul table n i 1  mul table 7

[python] finding multiples of a number in Python

Examples related to python

Examples related to math

Examples related to range