You can use
x = [1, 2, 3]
disp(sprintf('Answer: (%d, %d, %d)', x))
This results in
Answer: (1, 2, 3)
For vectors of arbitrary size, you can use
disp(strrep(['Answer: (' sprintf(' %d,', x) ')'], ',)', ')'))
An alternative way would be
disp(strrep(['Answer: (' num2str(x, ' %d,') ')'], ',)', ')'))