Return outside function error in Python

Question

This is the problem   Given the following program in Python  suppose that the user enters the number 4 from the keyboard  What will be the value returned   N   int input  enter a positive integer     counter   1 while  N  gt  0       counter   counter   N     N   N - 1     return counter   Yet I keep getting a outside function error when I run the system  what am I doing wrong  Thanks

User · Answer

You can only return from inside a function and not from a loop.

It seems like your return should be outside the while loop, and your complete code should be inside a function.

def func():
    N = int(input("enter a positive integer:"))
    counter = 1
    while (N > 0):
        counter = counter * N
        N -= 1
    return counter  # de-indent this 4 spaces to the left.

print func()

And if those codes are not inside a function, then you don't need a return at all. Just print the value of counter outside the while loop.

User · Answer

You are not writing your code inside any function  you can return from functions only  Remove return statement and just print the value you want

User · Answer

It basically occours when you return from a loop you can only return from function

User · Answer

As already explained by the other contributers  you could print out the counter and then replace the return with a break statement   N   int input  enter a positive integer     counter   1 while  N  gt  0       counter   counter   N     N   N - 1     print counter      break

User · Answer

You have a return statement that isn t in a function   Functions are started by the def keyword   def function argument       return  something   print function  foo     prints  something    return has no meaning outside of a function  and so python raises an error

[python] Return outside function error in Python

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