I am having trouble understanding how to pass in a struct (by reference) to a function so that the struct's member functions can be populated. So far I have written:
bool data(struct *sampleData)
{
}
int main(int argc, char *argv[]) {
struct sampleData {
int N;
int M;
string sample_name;
string speaker;
};
data(sampleData);
}
The error I get is:
C++ requires a type specifier for all declarations bool data(const &testStruct)
I have tried some examples explained here: Simple way to pass temporary struct by value in C++?
Hope someone can Help me.
bool data(sampleData *data)
{
}
You need to tell the method which type of struct you are using. In this case, sampleData.
Note: In this case, you will need to define the struct prior to the method for it to be recognized.
Example:
struct sampleData
{
int N;
int M;
// ...
};
bool data(struct *sampleData)
{
}
int main(int argc, char *argv[]) {
sampleData sd;
data(&sd);
}
Note 2: I'm a C guy. There may be a more c++ish way to do this.
Passing structs to functions by reference: simply :)
#define maxn 1000
struct solotion
{
int sol[maxn];
int arry_h[maxn];
int cat[maxn];
int scor[maxn];
};
void inser(solotion &come){
come.sol[0]=2;
}
void initial(solotion &come){
for(int i=0;i<maxn;i++)
come.sol[i]=0;
}
int main()
{
solotion sol1;
inser(sol1);
solotion sol2;
initial(sol2);
}
It is possible to construct a struct inside the function arguments:
function({ .variable = PUT_DATA_HERE });
Source: Stackoverflow.com