How to split a string and assign it to variables

Question

In Python it is possible to split a string and assign it to variables   ip  port    127 0 0 1 5432  split        but in Go it does not seem to work   ip  port    strings Split  127 0 0 1 5432           assignment count mismatch  2   1   Question  How to split a string and assign values in one step

User · Answer

What you are doing is  you are accepting split response in two different variables  and strings Split   is returning only one response and that is an array of string  you need to store it to single variable and then you can extract the part of string by fetching the index value of an array   example      var hostAndPort string     hostAndPort    127 0 0 1 8080      sArray    strings Split hostAndPort           fmt Println  host       sArray 0       fmt Println  port       sArray 1

User · Answer

package main  import        fmt       strings     func main         strs    strings Split  127 0 0 1 5432            ip    strs 0      port    strs 1      fmt Println ip  port      Here is the definition for strings Split     Split slices s into all substrings separated by sep and returns a slice of    the substrings between those separators        If s does not contain sep and sep is not empty  Split returns a    slice of length 1 whose only element is s        If sep is empty  Split splits after each UTF-8 sequence  If both s    and sep are empty  Split returns an empty slice        It is equivalent to SplitN with a count of -1  func Split s  sep string    string   return genSplit s  sep  0  -1

User · Answer

Since go is flexible an you can create your own python style split       package main  import        fmt       strings       errors     type PyString string  func main         var py PyString     py    127 0 0 1 5432      ip  port   err    py Split               Python Style     fmt Println ip  port  err     func  py PyString  Split str string    string  string   error         s    strings Split string py   str      if len s   lt  2           return          errors New  Minimum match not found             return s 0    s 1    nil

User · Answer

Two steps  for example   package main  import        fmt       strings     func main         s    strings Split  127 0 0 1 5432            ip  port    s 0   s 1      fmt Println ip  port      Output   127 0 0 1 5432   One step  for example   package main  import        fmt       net     func main         host  port  err    net SplitHostPort  127 0 0 1 5432       fmt Println host  port  err      Output   127 0 0 1 5432  lt nil gt

User · Answer

In this function you can able to split the function by golang using array of strings    func SplitCmdArguments args   string  map string string       m    make map string string      for    v    range args           strs    strings Split v   quot   quot           if len strs     2               m strs 0     strs 1            else               log Println  quot not proper arguments quot   strs                      return m

User · Answer

As a side note  you can include the separators while splitting the string in Go  To do so  use strings SplitAfter as in the example below   package main  import        fmt       strings     func main         fmt Printf   q n   strings SplitAfter  z o r r o

User · Answer

There s are multiple ways to split a string     If you want to make it temporary then split like this       import net package  host  port  err    net SplitHostPort  0 0 0 1 8080   if err    nil   fmt Println  Error is splitting     err error       do you code here   fmt Println host  port     Split based on struct     Create a struct and split like this       type ServerDetail struct       Host       string     Port       string     err        error    ServerDetail   net SplitHostPort  0 0 0 1 8080     Specific for Host and Port   Now use in you code like ServerDetail Host and ServerDetail Port  If you don t want to split specific string do it like this   type ServerDetail struct       Host       string     Port       string    ServerDetail   strings Split  Your String           Common split method   and use like ServerDetail Host and ServerDetail Port   That s All

User · Answer

The IPv6 addresses for fields like RemoteAddr from http Request are formatted as     1  53343   So net SplitHostPort works great   package main      import            fmt           net             func main             host1  port  err    net SplitHostPort  127 0 0 1 5432           fmt Println host1  port  err           host2  port  err    net SplitHostPort     1  2345           fmt Println host2  port  err           host3  port  err    net SplitHostPort  localhost 1234           fmt Println host3  port  err          Output is   127 0 0 1 5432  lt nil gt    1 2345  lt nil gt  localhost 1234  lt nil gt

User · Answer

Golang does not support implicit unpacking of an slice  unlike python  and that is the reason this would not work  Like the examples given above  we would need to workaround it    One side note   The  implicit unpacking happens for variadic functions in go   func varParamFunc params    int        varParamFunc slice1

[string] How to split a string and assign it to variables

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