How do I get the last word in each line with bash

Question

For example i have a file     cat file  i am the first example   i am the second line   i do a question about a file    and i need   example  line  file   i intent with  awk  but the problem is that the words are in different space

User · Answer

You can do it easily with grep   grep -oE          file    -E use extended regex  -o output only the matched text instead of the full line

User · Answer

Try    awk  NF gt 1 print  NF   file example  line  file    To get the result in one line as in your example  try         sub             NF      str   str NF   END   print str     output     awk -f script awk file example  line  file     Pure bash     while read line  do   -z   line     amp  amp  continue  echo   line       done  lt  file example  line  file

User · Answer

Another way of doing this in plain bash is making use of the rev command like this   cat file   rev   cut -d    -f1   rev   tr -d       tr   n        Basically  you reverse the lines of the file  then split them with cut using space as the delimiter  take the first field that cut produces and then you reverse the token again  use tr -d to delete unwanted chars and tr again to replace newline chars with    Also  you can avoid the first cat by doing   rev  lt  file   cut -d    -f1   rev   tr -d       tr   n

User · Answer

You can do something like this in awk   awk    print  NF      Edit  To avoid empty line     awk  NF  print  NF

User · Answer

there are many ways  as awk solutions shows  it s the clean solution  sed solution is to delete anything till the last space  So if there is no space at the end  it should work  sed  s      g   lt file gt   you can avoid sed also and go for a while loop   while read line do   -z   line     amp  amp  continue   echo  line rev cut -f1 -d    rev done  lt  file   it reads a line  reveres it  cuts the first  i e  last in the original  and restores back  the same can be done in a pure bash way  while read line do   -z   line     amp  amp  continue   echo   line      done  lt  file   it is called parameter expansion

User · Answer

tldr     awk   print  NF   file txt   paste -sd    sed  s      g    For a file like this    cat file txt The quick brown fox jumps over the lazy dog    the given command will print  fox  over  dog    How it works    awk   print  NF     prints the last field of every line paste -sd    reads stdin serially  -s  one file at a time  and writes fields comma-delimited  -d   sed  s      g    substitutes     with      globally  for all instances    References    https   linux die net man 1 awk https   linux die net man 1 paste https   linux die net man 1 sed

[linux] How do I get the last word in each line with bash

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