Transform char array into String

Question

I have a function that returns a char array and I want that turned into a String so I can better process it  compare to other stored data   I am using this simple for that should work  but it doesn t for some reason  bufferPos is the length of the array  buffer is the array and item is an empty String    for int k 0  k lt bufferPos  k           item    buffer k             The buffer has the right values and so does bufferPos  but when I try to convert  for example 544900010837154  it only holds 54  If I add Serial prints to the for like this   for int k 0  k lt bufferPos  k                       Serial print buffer k                      Serial print   t                      Serial println item                     item    buffer k                       the output is this   5    4   5 4   54 9   54 0   54 0   54 0   54 1   54 0   54 8   54 3   54 7   54 1   54   What am I missing  It feels like such a simple task and I fail to see the solution

User · Answer

I have search it again and search this question in baidu. Then I find 2 ways:

1,

_x000D_

char ch[]={'a','b','c','d','e','f','g','\0'};_x000D_
string s=ch;_x000D_
cout<<s;

_x000D_

Be aware to that '\0' is necessary for char array ch.

2,

_x000D_

#include<iostream>_x000D_
#include<string>_x000D_
#include<strstream>_x000D_
using namespace std;_x000D_
_x000D_
int main()_x000D_
{_x000D_
 char ch[]={'a','b','g','e','d','\0'};_x000D_
 strstream s;_x000D_
 s<<ch;_x000D_
 string str1;_x000D_
 s>>str1;_x000D_
 cout<<str1<<endl;_x000D_
 return 0;_x000D_
}

_x000D_

In this way, you also need to add the '\0' at the end of char array.

Also, strstream.h file will be abandoned and be replaced by stringstream

User · Answer

If you have the char array null terminated  you can assign the char array to the string   char   chArray    some characters   String String chArray     As for your loop code  it looks right  but I will try on my controller to see if I get the same problem

User · Answer

Visit https   www arduino cc en Reference StringConstructor to solve the problem easily   This worked for me   char yyy 6    String xxx   yyy 0   h    yyy 1   e    yyy 2   l    yyy 3   l    yyy 4   o    yyy 5    0    xxx String yyy

User · Answer

Three years later  I ran into the same problem  Here s my solution  everybody feel free to cut-n-paste  The simplest things keep us up all night  Running on an ATMega  and Adafruit Feather M0   void setup          turn on Serial so we can see      Serial begin 9600         the culprit    uint8 t my str 6         an array big enough for a 5 character string       give it something so we can see what it s doing   my str 0     H     my str 1     e     my str 2     l     my str 3     l     my str 4     o     my str 5    0      be sure to set the null terminator          can we see it    Serial println  char  my str         can we do logical operations with it as-is    Serial println  char  my str     Hello          okay  it can t  wrong data type  and no terminator    so let s do this    String str  char  my str         can we see it now    Serial println str         make comparisons   Serial println str     Hello          one more time just because   Serial println str     Hello          one last thing       Serial println sizeof str       void loop          nothing     And we get   Hello       as expected 0           no surprise  wrong data type and no terminator in comparison value Hello       also  as expected 1           YAY  1           YAY  6           as expected   Hope this helps someone

User · Answer

May you should try creating a temp string object and then add to existing item string  Something like this   for int k 0  k lt bufferPos  k           item    String buffer k

[string] Transform char array into String

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