Regex pattern including all special characters

Question

I want to write a simple regular expression to check if in given string exist any special character  My regex works but I don t know why it also includes all numbers  so when I put some number it returns an error   My code     pattern to find if there is any special character in string Pattern regex   Pattern compile     amp            lt  gt  -             matcher to find if there is any special character in string Matcher matcher   regex matcher searchQuery getSearchFor      if matcher find          errors rejectValue  searchFor    wrong pattern SearchQuery searchForSpecialCharacters   Special characters are not allowed

User · Answer

If you only rely on ASCII characters  you can rely on using the hex ranges on the ASCII table  Here is a regex that will grab all special characters in the range of 33-47  58-64  91-96  123-126    x21- x2F x3A- x40 x5B- x60 x7B- x7E    However you can think of special characters as not normal characters  If we take that approach  you can simply do this    A-Za-z0-9 s     Hower this will not catch     and probably others

User · Answer

For people  like me  looking for an answer for special characters like    etc  just use this pattern     Only text  or a space     A-Za-z  -     Text and numbers    A-Za-z  - 0-9    Text  numbers and some special chars    A-Za-z  - 0-9   -         Regex just starts at the ascii index and checks if a character of the string is in within both indexes  startindex-endindex    So you can add any range    Eventually you can play around with a handy tool  https   regexr com   Good luck

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Try using this for the same things - StringUtils isAlphanumeric value

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Please use this   it is simplest       p Punct  Punctuation  One of       amp       -     lt                 https   docs oracle com javase 7 docs api java util regex Pattern html      StringBuilder builder   new StringBuilder checkstring       String regex      p Punct      Special character            amp    -                  gt  lt        change your all special characters to         Pattern  pattern   Pattern compile regex       Matcher matcher   pattern matcher builder toString         checkstring matcher replaceAll

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I have defined one pattern to look for any of the ASCII Special Characters ranging between 032 to 126 except the alpha-numeric  You may use something like the one below      To find any Special Character     -   -   -   -         To find minimum of 1 and maximum of any count          -   -   -   -   1       These patterns have Special Characters ranging between 032 to 047  058 to 064  091 to 096  and 123 to 126

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Here is my regular expression  that I used for removing all the special characters from any string    String regex           s                          0-9         lt    gt        amp       -

User · Answer

Try this  It works on C  it should work on java also  If you want to exclude spaces just add  s in there       p L  p Nd

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We can achieve this using Pattern and Matcher as follows   Pattern pattern   Pattern compile    A-Za-z0-9      Matcher matcher   pattern matcher trString   boolean hasSpecialChars   matcher find

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You have a dash in the middle of the character class  which will mean a character range  Put the dash at the end of the class like so      amp            lt  gt        -

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Use this regular expression pattern     a-zA-Z0-9       It validates alphanumeric string excluding the special characters

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SInce you don t have white-space and underscore in your character class I think following regex will be better for you   Pattern regex   Pattern compile     w s       Which means match everything other than  A-Za-z0-9 s    Unicode version   Pattern regex   Pattern compile     p L  d s

User · Answer

To find any number of special characters use the following regex pattern      A-Za-z0-9    1       A-Za-z0-9    this means any character except the alphabets  numbers  and space   1 0  this means one or more characters of the previous block

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W      - start of the string   W - match any non-word character   a-zA-Z0-9      - end of the string

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Try     i     a-z   a-z0-9  s                                            lt    gt   -                   i   A    indicates that the regular expression A is case insensitive    a-z   represents any alphabetic character from a to z     a-z0-9  s                                            lt    gt   -            represents any alphabetic character except a to z  digits  and special characters i e  accented characters     a-z   a-z0-9  s                                            lt    gt   -             represents any alphabetic accented or unaccented  character only characters      one or more occurrence of the regex that precedes it

User · Answer

You can use a negative match   Pattern regex   Pattern compile    a-zA-Z0-9        For zero or more characters   or  Pattern regex   Pattern compile    a-zA-Z0-9        For one or more characters

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That s because your pattern contains a  -  which is all characters between and including   and    which included digits and several other characters as shown below     If by special characters  you mean punctuation and symbols use     p P  p S     which contains all unicode punctuation and symbols

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Please don t do that    little Unicode BABY ANGELs like this one  are dying         these are not images   nor is the arrow      And you are killing 20 years of DOS  -   the last smiley is called WHITE SMILING FACE    Now it s at 263A    But in ancient times it was ALT-1  and his friend   BLACK SMILING FACE    Now it s at 263B    But in ancient times it was ALT-2 Try a negative match  Pattern regex   Pattern compile  quot   A-Za-z0-9  quot      this will ok only A-Z  quot standard quot  letters and  quot standard quot  0-9 digits

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Here is my regex variant of a special character   String regExp        lt  gt                     amp                                             0-9           Java code

[java] Regex pattern including all special characters

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