Okay after hours of research and still using DB::select I have to ask this question. Because I am about to trough my computer away ;).
I want to get the last input of a user (base on the timestamp). I can do this with the raw sql
SELECT c.*, p.*
FROM users c INNER JOIN
(
SELECT user_id,
MAX(created_at) MaxDate
FROM `catch-text`
GROUP BY user_id
) MaxDates ON c.id = MaxDates.user_id INNER JOIN
`catch-text` p ON MaxDates.user_id = p.user_id
AND MaxDates.MaxDate = p.created_at
I got this query from another post here on stackoverflow.
I have tried everything to do this with the fluent query builder in Laravel however with no success.
I know the manual says you can do this:
DB::table('users')
->join('contacts', function($join)
{
$join->on('users.id', '=', 'contacts.user_id')->orOn(...);
})
->get();
But that is not helping much because I do not see how I could use a subquery there? Anyone who can light up my day?
Query with sub query in Laravel
$resortData = DB::table('resort')
->leftJoin('country', 'resort.country', '=', 'country.id')
->leftJoin('states', 'resort.state', '=', 'states.id')
->leftJoin('city', 'resort.city', '=', 'city.id')
->select('resort.*', 'country.name as country_name', 'states.name as state_name','city.name as city_name', DB::raw("(SELECT GROUP_CONCAT(amenities.name) from resort_amenities LEFT JOIN amenities on amenities.id= resort_amenities.amenities_id WHERE resort_amenities.resort_id=resort.id) as amenities_name"))->groupBy('resort.id')
->orderBy('resort.id', 'DESC')
->get();
I am on Laravel 7.25 and I don't know if it supports on previous versions or not but Its pretty good.
public function joinSub($query, $as, $first, $operator = null, $second = null, $type = 'inner', $where = false)
Showing/Getting the user ID and the total number of posts by them left joining two tables users and posts.
return DB::table('users')
->joinSub('select user_id,count(id) noOfPosts from posts group by user_id', 'totalPosts', 'users.id', '=', 'totalPosts.user_id', 'left')
->select('users.name', 'totalPosts.noOfPosts')
->get();
If you don't wanna mention 'left' for leftjoin then you can use another prebuilt function
public function leftJoinSub($query, $as, $first, $operator = null, $second = null)
{
return $this->joinSub($query, $as, $first, $operator, $second, 'left');
}
And yeah, it actually calls the same function but it passes the join type itself. You can apply the same logic for other joins i.e. righJoinSub(...) etc.
I can't comment because my reputation is not high enough. @Franklin Rivero if you are using Laravel 5.2 you can set the bindings on the main query instead of the join using the setBindings method.
So the main query in @ph4r05's answer would look something like this:
$q = DnsResult::query()
->from($dnsTable . ' AS s')
->join(
DB::raw('(' . $qqSql. ') AS ss'),
function(JoinClause $join) {
$join->on('s.watch_id', '=', 'ss.watch_id')
->on('s.last_scan_at', '=', 'ss.last_scan');
})
->setBindings($subq->getBindings());
I was looking for a solution to quite a related problem: finding the newest records per group which is a specialization of a typical greatest-n-per-group with N = 1.
The solution involves the problem you are dealing with here (i.e., how to build the query in Eloquent) so I am posting it as it might be helpful for others. It demonstrates a cleaner way of sub-query construction using powerful Eloquent fluent interface with multiple join columns and where
condition inside joined sub-select.
In my example I want to fetch the newest DNS scan results (table scan_dns
) per group identified by watch_id
. I build the sub-query separately.
The SQL I want Eloquent to generate:
SELECT * FROM `scan_dns` AS `s`
INNER JOIN (
SELECT x.watch_id, MAX(x.last_scan_at) as last_scan
FROM `scan_dns` AS `x`
WHERE `x`.`watch_id` IN (1,2,3,4,5,42)
GROUP BY `x`.`watch_id`) AS ss
ON `s`.`watch_id` = `ss`.`watch_id` AND `s`.`last_scan_at` = `ss`.`last_scan`
I did it in the following way:
// table name of the model
$dnsTable = (new DnsResult())->getTable();
// groups to select in sub-query
$ids = collect([1,2,3,4,5,42]);
// sub-select to be joined on
$subq = DnsResult::query()
->select('x.watch_id')
->selectRaw('MAX(x.last_scan_at) as last_scan')
->from($dnsTable . ' AS x')
->whereIn('x.watch_id', $ids)
->groupBy('x.watch_id');
$qqSql = $subq->toSql(); // compiles to SQL
// the main query
$q = DnsResult::query()
->from($dnsTable . ' AS s')
->join(
DB::raw('(' . $qqSql. ') AS ss'),
function(JoinClause $join) use ($subq) {
$join->on('s.watch_id', '=', 'ss.watch_id')
->on('s.last_scan_at', '=', 'ss.last_scan')
->addBinding($subq->getBindings());
// bindings for sub-query WHERE added
});
$results = $q->get();
UPDATE:
Since Laravel 5.6.17 the sub-query joins were added so there is a native way to build the query.
$latestPosts = DB::table('posts')
->select('user_id', DB::raw('MAX(created_at) as last_post_created_at'))
->where('is_published', true)
->groupBy('user_id');
$users = DB::table('users')
->joinSub($latestPosts, 'latest_posts', function ($join) {
$join->on('users.id', '=', 'latest_posts.user_id');
})->get();
You can use following addon to handle all subquery related function from laravel 5.5+
https://github.com/maksimru/eloquent-subquery-magic
User::selectRaw('user_id,comments_by_user.total_count')->leftJoinSubquery(
//subquery
Comment::selectRaw('user_id,count(*) total_count')
->groupBy('user_id'),
//alias
'comments_by_user',
//closure for "on" statement
function ($join) {
$join->on('users.id', '=', 'comments_by_user.user_id');
}
)->get();
I think what you looking for is "joinSub". It's supported from laravel ^5.6. If you using laravel version below 5.6 you can also register it as macro in your app service provider file. like this https://github.com/teamtnt/laravel-scout-tntsearch-driver/issues/171#issuecomment-413062522
$subquery = DB::table('catch-text')
->select(DB::raw("user_id,MAX(created_at) as MaxDate"))
->groupBy('user_id');
$query = User::joinSub($subquery,'MaxDates',function($join){
$join->on('users.id','=','MaxDates.user_id');
})->select(['users.*','MaxDates.*']);
Source: Stackoverflow.com