[java] split string only on first instance - java

I want to split a string by '=' charecter. But I want it to split on first instance only. How can I do that ? Here is a JavaScript example for '_' char but it doesn't work for me split string only on first instance of specified character

Example :

apple=fruit table price=5

When I try String.split('='); it gives

[apple],[fruit table price],[5]

But I need

[apple],[fruit table price=5]

Thanks

This works:

public class Split
{
    public static void main(String...args)
    {
        String a = "%abcdef&Ghijk%xyz";
        String b[] = a.split("%", 2);
        
        System.out.println("Value = "+b[1]);
    }
}

String string = "This is test string on web";
String splitData[] = string.split("\\s", 2);

Result ::
splitData[0] =>  This
splitData[1] =>  is test string  


String string = "This is test string on web";
String splitData[] = string.split("\\s", 3);

Result ::
splitData[0] =>  This
splitData[1] =>  is
splitData[1] =>  test string on web

By default split method create n number's of arrays on the basis of given regex. But if you want to restrict number of arrays to create after a split than pass second argument as an integer argument.

String[] func(String apple){
String[] tmp = new String[2];
for(int i=0;i<apple.length;i++){
   if(apple.charAt(i)=='='){
      tmp[0]=apple.substring(0,i);
      tmp[1]=apple.substring(i+1,apple.length);
      break;
   }
}
return tmp;
}
//returns string_ARRAY_!

i like writing own methods :)

Yes you can, just pass the integer param to the split method

String stSplit = "apple=fruit table price=5"

stSplit.split("=", 2);

Here is a java doc reference : String#split(java.lang.String, int)

As many other answers suggest the limit approach, This can be another way

You can use the indexOf method on String which will returns the first Occurance of the given character, Using that index you can get the desired output

String target = "apple=fruit table price=5" ;
int x= target.indexOf("=");
System.out.println(target.substring(x+1));