There are lots of posts about regexs to match a potentially empty string, but I couldn't readily find any which provided a regex which only matched an empty string.
I know that ^ will match the beginning of any line and $ will match the end of any line as well as the end of the string. As such, /^$/ matches far more than the empty string such as "\n", "foobar\n\n", etc.
I would have thought, though, that /\A\Z/ would match just the empty string, since \A matches the beginning of the string and \Z matches the end of the string. However, my testing shows that /\A\Z/ will also match "\n". Why is that?
As @Bohemian and @mbomb007 mentioned before, this works AND has the additional advantage of being more readable:
console.log(/^(?!.)/s.test("")); //true
Based on the most-approved answer, here is yet another way:
var result = !/[\d\D]/.test(string); //[\d\D] will match any character
Try looking here: https://docs.python.org/2/library/re.html
I ran into the same problem you had though. I could only build a regex that would match only the empty string and also "\n". Try trimming/replacing the newline characters in the string with another character first.
I was using http://pythex.org/ and trying weird regexes like these:
()
(?:)
^$
^(?:^\n){0}$
and so on.
Wow, ya'll are overthinking it. It's as simple as the following. Besides, many of those answers aren't understood by the RE2 dialect used by C and golang.
^$
I believe Python is the only widely used language that doesn't support \z in this way (yet). There are Python bindings for Russ Cox / Google's super fast re2 C++ library that can be "dropped in" as a replacement for the bundled re.
There's an excellent discussion (with workarounds) for this at Perl Compatible Regular Expression (PCRE) in Python, here on SO.
python
Python 2.7.11 (default, Jan 16 2016, 01:14:05)
[GCC 4.2.1 Compatible FreeBSD Clang 3.4.1 on freebsd10
Type "help", "copyright", "credits" or "license" for more information.
>>> import re2 as re
>>>
>>> re.match(r'\A\z', "")
<re2.Match object at 0x805d97170>
@tchrist's answer is worth the read.
Another possible answer considering also the case that an empty string might contain several whitespace characters for example spaces,tabs,line break characters can be the folllowing pattern.
pattern = r"^(\s*)$"
This pattern matches if the string starts and ends with zero or more whitespace characters.
It was tested in Python 3
I would use a negative lookahead for any character:
^(?![\s\S])
This can only match if the input is totally empty, because the character class will match any character, including any of the various newline characters.
The answer may be language dependent, but since you don't mention one, here is what I just came up with in js:
var a = ['1','','2','','3'].join('\n');
console.log(a.match(/^.{0}$/gm)); // ["", ""]
// the "." is for readability. it doesn't really matter
a.match(/^[you can put whatever the hell you want and this will also work just the same]{0}$/gm)
You could also do a.match(/^(.{10,}|.{0})$/gm) to match empty lines OR lines that meet a criteria. (This is what I was looking for to end up here.)
I know that ^ will match the beginning of any line and $ will match the end of any line
This is only true if you have the multiline flag turned on, otherwise it will only match the beginning/end of the string. I'm assuming you know this and are implying that, but wanted to note it here for learners.
^$ -- regex to accept empty string.And it wont match "/n" or "foobar/n" as you mentioned. You could test this regex on https://www.regextester.com/1924.
If you have your existing regex use or(|) in your regex to match empty string. For example /^[A-Za-z0-9&._ ]+$|^$/
Source: Stackoverflow.com