[batch-file] How to print the current time in a Batch-File?

I need to print time in a batch file but command prompt tells me that the syntax is incorrect. Here is the code i have so far:

@echo %time%
ping -n 1 -w 1 127.0.0.1 1>nul
@echo %time%
pause
cls

I don't know why it isn't working, Please help Me.

set time1=%time%
call timeout 10
set time2=%time%
echo. time1
echo. time2
echo.
pause

This works with Windows 10, 8.x, 7, and possibly further back:

@echo Started: %date% %time%
.
.
.
@echo Completed: %date% %time%

You can use the command time /t for the time and date /t for the date, here is an example:

@echo off
time /t >%tmp%\time.tmp
date /t >%tmp%\date.tmp
set ttime=<%tmp%\time.tmp
set tdate=<%tmp%\date.tmp
del /f /q %tmp%\time.tmp
del /f /q %tmp%\date.tmp
echo Time: %ttime%
echo Date: %tdate%
pause >nul

You can also use the built in variables %time% and %date%, here is another example:

@echo off
echo Time: %time:~0,5%
echo Date: %date%
pause >nul

we can easily print the current time and date using echo and system variables as below.

echo %DATE% %TIME%

output example: 13-Sep-19 15:53:05.62

Not sure if your question was answered.

This will write the time & date every 20 seconds in the file ping_ip.txt. The second to last line just says run the same batch file again, and agan, and again,..........etc.

Does not seem to create multiple instances, so that's a good thing.

@echo %time% %date% >>ping_ip.txt
ping -n 20 -w 3 127.0.0.1 >>ping_ip.txt
This_Batch_FileName.bat
cls