[java] could not extract ResultSet in hibernate

I have a problem with Hibernate. I try to parse to List but It throws an exception: HTTP Status 500 - could not extract ResultSet. When I debug, It fault at line query.list()...

My sample code here

@Entity
@Table(name = "catalog")
public class Catalog implements Serializable {

@Id
@Column(name="ID_CATALOG")
@GeneratedValue 
private Integer idCatalog;

@Column(name="Catalog_Name")
private String catalogName;

@OneToMany(mappedBy="catalog", fetch = FetchType.LAZY)
private Set<Product> products = new HashSet<Product>(0);

//getter & setter & constructor
//...
}


@Entity
@Table(name = "product")
public class Product implements Serializable {

@Id
@Column(name="id_product")
@GeneratedValue 
private Integer idProduct;

@ManyToOne
@JoinColumn(name="ID_CATALOG")
private Catalog catalog;

@Column(name="product_name")
private String productName;

@Column(name="date")
private Date date;

@Column(name="author")
private String author;

@Column(name="price")
private Integer price;

@Column(name="linkimage")
private String linkimage;

//getter & setter & constructor
}



@Repository
@SuppressWarnings({"unchecked", "rawtypes"})
public class ProductDAOImpl implements ProductDAO {
    @Autowired
    private SessionFactory sessionFactory;
public List<Product> searchProductByCatalog(String catalogid, String keyword) {
    String sql = "select p from Product p where 1 = 1";
    Session session = sessionFactory.getCurrentSession();

    if (keyword.trim().equals("") == false) {
        sql += " and p.productName like '%" + keyword + "%'";
    }
    if (catalogid.trim().equals("-1") == false
            && catalogid.trim().equals("") == false) {
        sql += " and p.catalog.idCatalog = " + Integer.parseInt(catalogid);
    }
    Query query = session.createQuery(sql);
    List listProduct = query.list();
    return listProduct;
}

}

My beans

  <!-- Scan classpath for annotations (eg: @Service, @Repository etc) -->
  <context:component-scan base-package="com.shopmvc"/>

  <!-- JDBC Data Source. It is assumed you have MySQL running on localhost port 3306 with 
       username root and blank password. Change below if it's not the case -->
  <bean id="myDataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
    <property name="driverClassName" value="com.mysql.jdbc.Driver"/>
    <property name="url" value="jdbc:mysql://localhost:3306/shoesshopdb?autoReconnect=true"/>
    <property name="username" value="root"/>
    <property name="password" value="12345"/>
    <property name="validationQuery" value="SELECT 1"/>
  </bean>

  <!-- Hibernate Session Factory -->
  <bean id="mySessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
    <property name="dataSource" ref="myDataSource"/>
    <property name="packagesToScan">
      <array>
        <value>com.shopmvc.pojo</value>
      </array>
    </property>
    <property name="hibernateProperties">
      <value>
        hibernate.dialect=org.hibernate.dialect.MySQLDialect
      </value>
    </property>
  </bean>

  <!-- Hibernate Transaction Manager -->
  <bean id="transactionManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager">
    <property name="sessionFactory" ref="mySessionFactory"/>
  </bean>

  <!-- Activates annotation based transaction management -->
  <tx:annotation-driven transaction-manager="transactionManager"/>

Exception:

org.springframework.web.util.NestedServletException: Request processing failed; nested exception is org.hibernate.exception.SQLGrammarException: could not extract ResultSet
    org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:948)
    org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:827)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:621)
    org.springframework.web.servlet.FrameworkServlet.service(FrameworkServlet.java:812)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:728)

root cause 

org.hibernate.exception.SQLGrammarException: could not extract ResultSet
    org.hibernate.exception.internal.SQLExceptionTypeDelegate.convert(SQLExceptionTypeDelegate.java:82)
    org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:49)
    org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:125)
    org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:110)
    org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.extract(ResultSetReturnImpl.java:61)
    org.hibernate.loader.Loader.getResultSet(Loader.java:2036)

root cause 

com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'product0_.ID_CATALOG' in 'field list'
    sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
    sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source)
    sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source)
    java.lang.reflect.Constructor.newInstance(Unknown Source)
    com.mysql.jdbc.Util.handleNewInstance(Util.java:411)
    com.mysql.jdbc.Util.getInstance(Util.java:386)
    com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1054)
    com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:4187)
    com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:4119)
    com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:2570)
    com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2731)
    com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2815)
    com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:2155)
    com.mysql.jdbc.PreparedStatement.executeQuery(PreparedStatement.java:2322)
    org.apache.commons.dbcp.DelegatingPreparedStatement.executeQuery(DelegatingPreparedStatement.java:96)
    org.apache.commons.dbcp.DelegatingPreparedStatement.executeQuery(DelegatingPreparedStatement.java:96)
    org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.extract(ResultSetReturnImpl.java:56)
    org.hibernate.loader.Loader.getResultSet(Loader.java:2036)
    org.hibernate.loader.Loader.executeQueryStatement(Loader.java:1836)
    org.hibernate.loader.Loader.executeQueryStatement(Loader.java:1815)
    org.hibernate.loader.Loader.doQuery(Loader.java:899)
    org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:341)
    org.hibernate.loader.Loader.doList(Loader.java:2522)
    org.hibernate.loader.Loader.doList(Loader.java:2508)
    org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2338)
    org.hibernate.loader.Loader.list(Loader.java:2333)
    org.hibernate.loader.hql.QueryLoader.list(QueryLoader.java:490)

My Database:

CREATE TABLE `catalog` (
  `ID_CATALOG` int(11) NOT NULL AUTO_INCREMENT,
  `Catalog_Name` varchar(45) DEFAULT NULL,
  PRIMARY KEY (`ID_CATALOG`)
)

CREATE TABLE `product` (
  `id_product` int(11) NOT NULL AUTO_INCREMENT,
  `product_name` varchar(45) DEFAULT NULL,
  `date` date DEFAULT NULL,
  `author` varchar(45) DEFAULT NULL,
  `price` int(11) DEFAULT NULL,
  `catalog_id` int(11) DEFAULT NULL,
  `linkimage` varchar(45) DEFAULT NULL,
  PRIMARY KEY (`id_product`),
  KEY `FK_Product_idx` (`catalog_id`),
  CONSTRAINT `FK_Product` FOREIGN KEY (`catalog_id`) REFERENCES `catalog` (`ID_CATALOG`) ON DELETE NO ACTION ON UPDATE NO ACTION
)

I faced the same problem after migrating a database from online server to localhost. The schema changed so I had to define the schema manually for each table:

@Entity
@Table(name = "ESBCORE_DOMAIN", schema = "SYS")

I was using Spring Data JPA with PostgreSql and during UPDATE call it was showing errors-

• 'could not extract ResultSet' and another one.
• org.springframework.dao.InvalidDataAccessApiUsageException: Executing an update/delete query; nested exception is javax.persistence.TransactionRequiredException: Executing an update/delete query. (Showing Transactional required.)

Actually, I was missing two required Annotations.

• @Transactional and
• @Modifying

With-

@Query(vlaue = " UPDATE DB.TABLE SET Col1 = ?1 WHERE id = ?2 ", nativeQuery = true)
void updateCol1(String value, long id);

Another potential cause, for other people coming across the same error message is that this error will occur if you are accessing a table in a different schema from the one you have authenticated with.

In this case you would need to add the schema name to your entity entry:

@Table(name= "catalog", schema = "targetSchemaName")

Another solution is add @JsonIgnore :

@OneToMany(mappedBy="catalog", fetch = FetchType.LAZY)
@JsonIgnore
private Set<Product> products = new HashSet<Product>(0);

For MySql take in mind that it's not a good idea to write camelcase. For example if the schema is like that:

CREATE TABLE IF NOT EXISTS `task`(
    `id` INT NOT NULL AUTO_INCREMENT PRIMARY KEY ,
    `teaching_hours` DECIMAL(5,2) DEFAULT NULL,
    `isActive` BOOLEAN DEFAULT FALSE,
    `is_validated` BOOLEAN DEFAULT FALSE,
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

You must be very careful cause isActive column will translate to isactive. So in your Entity class is should be like this:

 @Basic
 @Column(name = "isactive", nullable = true)
 public boolean isActive() {
     return isActive;
 }
 public void setActive(boolean active) {
     isActive = active;
 }

That was my problem at least that got me your error

This has nothing to do with MySql which is case insensitive, but rather is a naming strategy that spring will use to translate your tables. For more refer to this post

I Used the following properties in my application.properties file and the issue got resolved

spring.jpa.hibernate.naming.implicit-strategy=org.hibernate.boot.model.naming.ImplicitNamingStrategyLegacyJpaImpl

and

spring.jpa.hibernate.naming.physical-strategy=org.hibernate.boot.model.naming.PhysicalNamingStrategyStandardImpl

earlier was getting an error

There was an unexpected error (type=Internal Server Error, status=500).
could not extract ResultSet; SQL [n/a]; nested exception is 
org.hibernate.exception.SQLGrammarException: could not extract ResultSet
org.springframework.dao.InvalidDataAccessResourceUsageException: could not extract ResultSet; SQL [n/a]; nested exception is org.hibernate.exception.SQLGrammarException: could not extract ResultSet
at org.springframework.orm.jpa.vendor.HibernateJpaDialect.convertHibernateAccessException(HibernateJpaDialect.java:280)
at org.springframework.orm.jpa.vendor.HibernateJpaDialect.translateExceptionIfPossible(HibernateJpaDialect.java:254)
at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.translateExceptionIfPossible(AbstractEntityManagerFactoryBean.java:528)
at org.springframework.dao.support.ChainedPersistenceExceptionTranslator.translateExceptionIfPossible(ChainedPersistenceExceptionTranslator.java:61)
at org.springframework.dao.support.DataAccessUtils.translateIfNecessary(DataAccessUtils.java:242)
at org.springframework.dao.support.PersistenceExceptionTranslationInterceptor.invoke(PersistenceExceptionTranslationInterceptor.java:153)
at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:186)

I had similar issue. Try use the HQL editor. It will display you the SQL (as you have a SQL grammar exception). Copy your SQL and execute it separately. In my case the problem was in schema definition. I defined the schema, but I should leave it empty. This raised the same exception as you got. And the error description reflected the actual state, as the schema name was included in SQL statement.

I had the same issue, when I tried to update a row:

@Query(value = "UPDATE data SET value = 'asdf'", nativeQuery = true)
void setValue();

My Problem was that I forgot to add the @Modifying annotation:

@Modifying    
@Query(value = "UPDATE data SET value = 'asdf'", nativeQuery = true)
void setValue();

If you don't have 'HIBERNATE_SEQUENCE' sequence created in database (if use oracle or any sequence based database), you shall get same type of error;

Ensure the sequence is present there;

Try using inner join in your Query

    Query query=session.createQuery("from Product as p INNER JOIN p.catalog as c 
    WHERE c.idCatalog= :id and p.productName like :XXX");
    query.setParameter("id", 7);
    query.setParameter("xxx", "%"+abc+"%");
    List list = query.list();

also in the hibernate config file have

<!--hibernate.cfg.xml -->
<property name="show_sql">true</property>

To display what is being queried on the console.