Java Replace all in a string with

Question

I need to escape all quotes     in a string  so it becomes     I ve tried using replaceAll  but it doesn t do anything  For some reason I can t get the regex to work   I m trying with  String s    You ll be totally awesome  I m really terrible   String shouldBecome    You  ll be totally awesome  I  m really terrible   s   s replaceAll                Doesn t do anything s   s replaceAll                 Doesn t do anything s   s replaceAll                  Doesn t do anything   I m really stuck here  hope somebody can help me here   Thanks   Iwan

User · Answer

This doesn t say how to  fix  the problem - that s already been done in other answers  it exists to draw out the details and applicable documentation references     When using String replaceAll or any of the applicable Matcher replacers  pay attention to the replacement string and how it is handled      Note that backslashes     and dollar signs     in the replacement string may cause the results to be different than if it were being treated as a literal replacement string  Dollar signs may be treated as references to captured subsequences as described above  and backslashes are used to escape literal characters in the replacement string    As pointed out by isnot2bad in a comment  Matcher quoteReplacement may be useful here      Returns a literal replacement String for the specified String     The String produced will match the sequence of characters in s treated as a literal sequence  Slashes     and dollar signs     will be given no special meaning

User · Answer

You can use apache s commons-text library  instead of commons-lang    Example code   org apache commons text StringEscapeUtils escapeJava escapedString     Dependency   compile  org apache commons commons-text 1 8   OR   lt dependency gt      lt groupId gt org apache commons lt  groupId gt      lt artifactId gt commons-text lt  artifactId gt      lt version gt 1 8 lt  version gt   lt  dependency gt

User · Answer

Use replace     s   s replace                 output      You  ll be totally awesome  I  m really terrible

User · Answer

You could also try using something like StringEscapeUtils to make your life even easier  http   commons apache org proper commons-lang javadocs api-2 6 org apache commons lang StringEscapeUtils html  s   StringEscapeUtils escapeJava s

User · Answer

Let s take a tour of String repalceAll String regex  String replacement    You will see that      An invocation of this method of the form str replaceAll regex  repl  yields exactly the same result as the expression      Pattern compile regex  matcher str  replaceAll repl    So lets take a look at Matcher html replaceAll java lang String  documentation     Note that backslashes     and dollar signs     in the replacement string may cause the results to be different than if it were being treated as a literal replacement string  Dollar signs may be treated as references to captured subsequences as described above  and backslashes are used to escape literal characters in the replacement string    You can see that in replacement we have special character   which can be used as reference to captured group like   System out println  aHellob aWorldb  replaceAll  a   w   b     1        result Hello World   But sometimes we don t want   to be such special because we want to use it as simple dollar character  so we need a way to escape it  And here comes    because since it is used to escape metacharacters in regex  Strings and probably in other places it is good convention to use it here to escape      So now   is also metacharacter in replacing part  so if you want to make it simple   literal in replacement you need to escape it somehow  And guess what  You escape it the same way as you escape it in regex or String  You just need to place another   before one you escaping   So if you want to create   in replacement part you need to add another   before it  But remember that to write   literal in String you need to write it as      so to create two    in replacement you need to write it as             So try   s   s replaceAll                  Or even better  to reduce explicit escaping in replacement part  and also in regex part - forgot to mentioned that earlier  just use replace instead replaceAll which adds regex escaping for us  s   s replace

User · Answer

You have to first escape the backslash because it s a literal  yielding      and then escape it again because of the regular expression  yielding        So  Try       s replaceAll                  output   You  ll be totally awesome  I  m really terrible

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