How do I calculate the inverse of the cumulative distribution function (CDF) of the normal distribution in Python?
Which library should I use? Possibly scipy?
This question is related to
python
scipy
normal-distribution
NORMSINV (mentioned in a comment) is the inverse of the CDF of the standard normal distribution. Using scipy, you can compute this with the ppf method of the scipy.stats.norm object. The acronym ppf stands for percent point function, which is another name for the quantile function.
In [20]: from scipy.stats import norm
In [21]: norm.ppf(0.95)
Out[21]: 1.6448536269514722
Check that it is the inverse of the CDF:
In [34]: norm.cdf(norm.ppf(0.95))
Out[34]: 0.94999999999999996
By default, norm.ppf uses mean=0 and stddev=1, which is the "standard" normal distribution. You can use a different mean and standard deviation by specifying the loc and scale arguments, respectively.
In [35]: norm.ppf(0.95, loc=10, scale=2)
Out[35]: 13.289707253902945
If you look at the source code for scipy.stats.norm, you'll find that the ppf method ultimately calls scipy.special.ndtri. So to compute the inverse of the CDF of the standard normal distribution, you could use that function directly:
In [43]: from scipy.special import ndtri
In [44]: ndtri(0.95)
Out[44]: 1.6448536269514722
Starting Python 3.8, the standard library provides the NormalDist object as part of the statistics module.
It can be used to get the inverse cumulative distribution function (inv_cdf - inverse of the cdf), also known as the quantile function or the percent-point function for a given mean (mu) and standard deviation (sigma):
from statistics import NormalDist
NormalDist(mu=10, sigma=2).inv_cdf(0.95)
# 13.289707253902943
Which can be simplified for the standard normal distribution (mu = 0 and sigma = 1):
NormalDist().inv_cdf(0.95)
# 1.6448536269514715
# given random variable X (house price) with population muy = 60, sigma = 40
import scipy as sc
import scipy.stats as sct
sc.version.full_version # 0.15.1
#a. Find P(X<50)
sct.norm.cdf(x=50,loc=60,scale=40) # 0.4012936743170763
#b. Find P(X>=50)
sct.norm.sf(x=50,loc=60,scale=40) # 0.5987063256829237
#c. Find P(60<=X<=80)
sct.norm.cdf(x=80,loc=60,scale=40) - sct.norm.cdf(x=60,loc=60,scale=40)
#d. how much top most 5% expensive house cost at least? or find x where P(X>=x) = 0.05
sct.norm.isf(q=0.05,loc=60,scale=40)
#e. how much top most 5% cheapest house cost at least? or find x where P(X<=x) = 0.05
sct.norm.ppf(q=0.05,loc=60,scale=40)
Source: Stackoverflow.com