[python] How to lowercase a pandas dataframe string column if it has missing values?

The following code does not work.

import pandas as pd
import numpy as np
df=pd.DataFrame(['ONE','Two', np.nan],columns=['x']) 
xLower = df["x"].map(lambda x: x.lower())

How should I tweak it to get xLower = ['one','two',np.nan] ? Efficiency is important since the real data frame is huge.

A possible solution:

import pandas as pd
import numpy as np

df=pd.DataFrame(['ONE','Two', np.nan],columns=['x']) 
xLower = df["x"].map(lambda x: x if type(x)!=str else x.lower())
print (xLower)

And a result:

0    one
1    two
2    NaN
Name: x, dtype: object

Not sure about the efficiency though.

Apply lambda function

df['original_category'] = df['original_category'].apply(lambda x:x.lower())

you can try this one also,

df= df.applymap(lambda s:s.lower() if type(s) == str else s)

May be using List comprehension

import pandas as pd
import numpy as np
df=pd.DataFrame(['ONE','Two', np.nan],columns=['Name']})
df['Name'] = [str(i).lower() for i in df['Name']] 

print(df)

Pandas >= 0.25: Remove Case Distinctions with str.casefold

Starting from v0.25, I recommend using the "vectorized" string method str.casefold if you're dealing with unicode data (it works regardless of string or unicodes):

s = pd.Series(['lower', 'CAPITALS', np.nan, 'SwApCaSe'])
s.str.casefold()

0       lower
1    capitals
2         NaN
3    swapcase
dtype: object

Also see related GitHub issue GH25405.

casefold lends itself to more aggressive case-folding comparison. It also handles NaNs gracefully (just as str.lower does).

But why is this better?

The difference is seen with unicodes. Taking the example in the python str.casefold docs,

Casefolding is similar to lowercasing but more aggressive because it is intended to remove all case distinctions in a string. For example, the German lowercase letter 'ß' is equivalent to "ss". Since it is already lowercase, lower() would do nothing to 'ß'; casefold() converts it to "ss".

Compare the output of lower for,

s = pd.Series(["der Fluß"])
s.str.lower()

0    der fluß
dtype: object

Versus casefold,

s.str.casefold()

0    der fluss
dtype: object

Also see Python: lower() vs. casefold() in string matching and converting to lowercase.

copy your Dataframe column and simply apply

df=data['x']
newdf=df.str.lower()

Another possible solution, in case the column has not only strings but numbers too, is to use astype(str).str.lower() or to_string(na_rep='') because otherwise, given that a number is not a string, when lowered it will return NaN, therefore:

import pandas as pd
import numpy as np
df=pd.DataFrame(['ONE','Two', np.nan,2],columns=['x']) 
xSecureLower = df['x'].to_string(na_rep='').lower()
xLower = df['x'].str.lower()

then we have:

>>> xSecureLower
0    one
1    two
2   
3      2
Name: x, dtype: object

and not

>>> xLower
0    one
1    two
2    NaN
3    NaN
Name: x, dtype: object

edit:

if you don't want to lose the NaNs, then using map will be better, (from @wojciech-walczak, and @cs95 comment) it will look something like this

xSecureLower = df['x'].map(lambda x: x.lower() if isinstance(x,str) else x)

Use apply function,

Xlower = df['x'].apply(lambda x: x.upper()).head(10)