This might be a simple question, but I cannot figure this out. I am trying to get a user by email using:
$user = User::whereEmail($email)->get();
But this is returning an array (of dimension 1) of $users. So If I want to get the name, I have to do $user[0]['first_name']
.
I tried using limit(1)
or take(1)
, or even using ->toArray()
but there was no difference.
What am I doing wrong?
Try with it
$color = \App\Color::take(1)->first();
You can also use this
$user = User::whereEmail($email)->first();
Using Laravel Eloquent you can get one row using first()
method,
it returns first row of table if where()
condition is not found otherwise it gives the first matched row of given criteria.
Syntax:
Model::where('fieldname',$value)->first();
Example:
$user = User::where('email',$email)->first();
//OR
//$user = User::whereEmail($email)->first();
Laravel 5.2
$sql = "SELECT * FROM users WHERE email = $email";
$user = collect(\User::select($sql))->first();
or
$user = User::table('users')->where('email', $email)->pluck();
laravel 5.8
If you don't even need an entire row, you may extract a single value from a record using the value()
method. This method will return the value of the column directly:
$first_name = DB::table('users')->where('email' ,'me@mail,com')->value('first_name');
check docs
You can do this too
Before you use this you must declare the DB facade in the controller Simply put this line for that
use Illuminate\Support\Facades\DB;
Now you can get a row using this
$getUserByEmail = DB::table('users')->where('email', $email)->first();
or by this too
$getUserByEmail = DB::select('SELECT * FROM users WHERE email = ?' , ['[email protected]']);
This one returns an array with only one item in it and while the first one returns an object. Keep that in mind.
Hope this helps.
Source: Stackoverflow.com