Run Executable from Powershell script with parameters

Question

So I have a powershell script that is supposed to run an executable with an argument to pass to set which method I want to run  and I need to pass a parameter  which is a directory to a config file  So this is what I have  Start-Process -FilePath  C  Program Files MSBuild test exe  -ArgumentList  genmsi f  MySourceDirectory src Deployment Installations xml    f is the shortname and file is the long name for my attribute    I get an error in powershell telling me that a positional parameter cannot be found for  f or  file   Any thoughts

User · Answer

Just adding an example that worked fine for me    sqldb    string   sqldir      bin MySQLInstanceConfig exe   myarg    -i ConnectionUsage DSS Port 3311 ServiceName MySQL RootPassword       rootpw Start-Process  sqldb -ArgumentList  myarg

User · Answer

Try quoting the argument list   Start-Process -FilePath  C  Program Files MSBuild test exe  -ArgumentList   genmsi f  MySourceDirectory src Deployment Installations xml    You can also provide the argument list as an array  comma separated args  but using a string is usually easier

User · Answer

Here is an alternative method for doing multiple args   I use it when the arguments are too long for a one liner     app    C  Program Files MSBuild test exe   arg1     genmsi   arg2     f   arg3     MySourceDirectory src Deployment Installations xml    amp   app  arg1  arg2  arg3

User · Answer

I was able to get this to work by using the Invoke-Expression cmdlet   Invoke-Expression   amp     scriptPath   test -r  number -b  testNumber -f  FileVersion -a  ApplicationID

[powershell] Run Executable from Powershell script with parameters

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