How to get the path of src test resources directory in JUnit

Question

I know I can load a file from src test resources with   getClass   getResource  somefile   getFile     But how can I get the full path to the src test resources directory  i e  I don t want to load a file  I just want to know the path of the directory

User · Answer

I would simply use Path from Java 7  Path resourceDirectory   Paths get  src   test   resources      Neat and clean

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There are differences and constraints in options offered by  Steve C and  ashosborne1  They must be specified  I believe  When can we can use  File resourcesDirectory   new File  quot src test resources quot      1 When tests are going to be run via maven only but not via IDE  2 1 When tests are going to be run via maven or 2 2 via IDE and only one project is imported into IDE   I use    imported    term  cause it is used in IntelliJ IDEA  I think users of eclipse also import their maven project   This will work  cause working directory when you run tests via IDE is the same as your project  3 1 When tests are going to be run via maven or 3 2 via IDE  and more than one projects are imported into IDE  when you are not a student  you usually import several projects   AND before you run tests via IDE  you manually configure working directory for your tests  That working directory should refer to your imported project that contains the tests  By default  working directory of all projects imported into IDE is only one   Probably it is a restriction of IntelliJ IDEA only  but I think all IDEs work like this  And this configuration that must be done manually  is not good at all  Working with several tests existing in different maven projects  but imported into one big    IDE    project  force us to remember this and don   t allow to relax and get pleasure from your work   Solution offered by  ashosborne1  personally I prefer this one  requires 2 additional requirements that must be done before you run tests  Here is a list of steps to use this solution   Create a test folder     teva     and file     readme     inside of     src test resources      src test resources teva readme File must be created in the test folder  otherwise  it will not work  Maven ignores empty folders   At least once build project via mvn clean install  It will run tests also  It may be enough to run only your test class method via maven without building  a whole project  As a result your test resources will be copied into test-classes  here is a path  target test-classes teva readme  After that  you can access the folder using code  already offered by  ashosborne1  I m sorry  that I could not edit this code inside of this list  of items correctly      public static final String TEVA FOLDER    quot teva quot        URL tevaUrl   YourTest class getClassLoader   getResource TEVA FOLDER    String tevaTestFolder   new File tevaUrl toURI    getAbsolutePath      Now you can run your test via IDE as many times as you want  Until you run mvn clean  It will drop the target folder  Creating file inside a test folder and running maven first time  before you run tests via IDE are needed steps  Without these steps  if you just in your IDE create test resources  then write test and run it via IDE only  you ll get an error  Running tests via mvn copies test resources into target test-classes teva readme and they become accessible for a classloader  You may ask  why do I need import more than one maven project in IDE and why so many complicated things  For me  one of the main motivation  keeping IDA-related files far from code  I first create a new project in my IDE  It is a fake project  that is just a holder of IDE-related files  Then  I import already existing maven projects  I force these imported projects to keep IDEA files in my original fake project only  As a result I don t see IDE-related files among the code  SVN should not see them  don t offer to configure svn git to ignore such files  please   Also it is just very convenient

User · Answer

Try working with the ClassLoader class              ClassLoader classLoader   getClass   getClassLoader    File file   new File classLoader getResource  somefile   getFile     System out println file getAbsolutePath       A ClassLoader is responsible for loading in classes  Every class has a reference to a ClassLoader  This code returns a File from the resource directory  Calling getAbsolutePath   on it returns its absolute Path   Javadoc for ClassLoader  http   docs oracle com javase 7 docs api java lang ClassLoader html

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You don t need to mess with class loaders  In fact it s a bad habit to get into because class loader resources are not java io File objects when they are in a jar archive   Maven automatically sets the current working directory before running tests  so you can just use       File resourcesDirectory   new File  src test resources      resourcesDirectory getAbsolutePath   will return the correct value if that is what you really need   I recommend creating a src test data directory if you want your tests to access data via the file system  This makes it clear what you re doing

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With Spring you could easily read it from the resources folder  either main resources or test resources    For example create a file  test resources subfolder sample json   Test public void testReadFile         String json   this readFile  classpath subfolder sample json        System out println json      public String readFile String path        try           File file   ResourceUtils getFile path           return new String Files readAllBytes file toPath            catch  IOException e            e printStackTrace               return null

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I have a Maven3 project using JUnit 4 12 and Java8  In order to get the path of a file called myxml xml under src test resources  I do this from within the test case    Test public void testApp         File inputXmlFile   new File this getClass   getResource   myxml xml   getFile         System out println inputXmlFile getAbsolutePath                 Tested on Ubuntu 14 04 with IntelliJ IDE  Reference here

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The simplest and clean solution I uses  suppose the name of the test class is TestQuery1 and there is a resources directory in your test folder as follows    -- java         -- TestQuery1 java  -- resources      -- TestQuery1          -- query json          -- query rq   To get the URI of TestQuery1 do   URL currentTestResourceFolder   getClass   getResource     getClass   getSimpleName       To get the URI of one of the file TestQuery1  do   File exampleDir   new File currentTestResourceFolder toURI     URI queryJSONFileURI   exampleDir toURI   resolve  query json

User · Answer

Use  getAbsolutePath   on your File object   getClass   getResource  somefile   getFile   getAbsolutePath

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With Spring  you can use this  import org springframework core io ClassPathResource      Don t worry when use a not existed directory or a empty directory    It can be used in  before String dir   new ClassPathResource  quot   quot   getFile   getAbsolutePath    quot   quot   quot Your Path quot

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List lt String gt  lines   Files readAllLines Paths get  src test resources foo txt     lines forEach System out  println

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You can t use a file from a resource folder for tests in a common case  The reason is that  resource files in the resource folder are stored inside a jar  So they don t have a real path in the file system   The most simple solution can be    Copy a file from resources to the temporary folder and get a path to that temporary file  Do tests using a temporary path  Delete the temporary file    TemporaryFolder from JUnit can be used to create temporary files and delete it after test is complited  Classes from guava library are used to copy a file form resource folder    Please  notice that if we use a subfolder in the resources folder  like good one  we don t have to add leading   to the resource path   public class SomeTest         Rule     public TemporaryFolder tmpFolder   new TemporaryFolder           Test     public void doSomethinge   throws IOException           File file   createTmpFileFromResource tmpFolder   file txt            File goodFile   createTmpFileFromResource tmpFolder   good file txt                do testing here            private static File createTmpFileFromResource TemporaryFolder folder                                                    String classLoaderResource  throws IOException           URL resource   Resources getResource classLoaderResource            File tmpFile   folder newFile            Resources asByteSource resource  copyTo Files asByteSink tmpFile            return tmpFile

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All content in src test resources is copied into target test-classes folder  So to get file from test resources during maven build you have to load it from test-classes folder  like that   Paths get      getClass   getProtectionDomain   getCodeSource   getLocation   toURI     resolve      Paths get  somefile     toFile     Break down    getClass   getProtectionDomain   getCodeSource   getLocation   toURI   - give you URI to target test-classes  resolve Paths get  somefile    - resolves someFile to target test-classes folder    Original anwser is taken from this

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You can get where you are through new File  quot   quot   getAbsolutePath    then you can derive path to src test resources usually it is just new File  quot src test resources quot

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If it s a spring project  we can use the below code to get files from src test resource folder   File file   ResourceUtils getFile this getClass   getResource   some file txt

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Use the following to inject Hibernate with Spring in your unit tests    Bean public LocalSessionFactoryBean getLocalSessionFactoryBean         LocalSessionFactoryBean localSessionFactoryBean   new LocalSessionFactoryBean        localSessionFactoryBean setConfigLocation new ClassPathResource  hibernate cfg xml         localSessionFactoryBean setPackagesToScan  com example yourpackage model        return localSessionFactoryBean      If you don t have the hibernate cfg xml present in your src test resources folder it will automatically fall back to the one in your src main resources folder

[java] How to get the path of src/test/resources directory in JUnit?

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