[git] Is there a "theirs" version of "git merge -s ours"?

When merging topic branch "B" into "A" using git merge, I get some conflicts. I know all the conflicts can be solved using the version in "B".

I am aware of git merge -s ours. But what I want is something like git merge -s theirs.

Why doesn't it exist? How can I achieve the same result after the conflicting merge with existing git commands? (git checkout every unmerged file from B)

UPDATE: The "solution" of just discarding anything from branch A (the merge commit point to B version of the tree) is not what I am looking for.

This question is related to git git-merge

The answer is


The equivalent(which keep parent order) to 'git merge -s theirs branchB'

Before merge:enter image description here

!!! Make sure you are in clean state !!!

Do the merge:

git commit-tree -m "take theirs" -p HEAD -p branchB 'branchB^{tree}'
git reset --hard 36daf519952 # is the output of the prev command

What we did ? We created a new commit which two parents ours and theirs and the contnet of the commit is branchB - theirs

After merge:enter image description here

More precisely:

git commit-tree -m "take theirs" -p HEAD -p 'SOURCE^{commit}' 'SOURCE^{tree}'

It is not entirely clear what your desired outcome is, so there is some confusion about the "correct" way of doing it in the answers and their comments. I try to give an overview and see the following three options:

Try merge and use B for conflicts

This is not the "theirs version for git merge -s ours" but the "theirs version for git merge -X ours" (which is short for git merge -s recursive -X ours):

git checkout branchA
# also uses -s recursive implicitly
git merge -X theirs branchB

This is what e.g. Alan W. Smith's answer does.

Use content from B only

This creates a merge commit for both branches but discards all changes from branchA and only keeps the contents from branchB.

# Get the content you want to keep.
# If you want to keep branchB at the current commit, you can add --detached,
# else it will be advanced to the merge commit in the next step.
git checkout branchB

# Do the merge an keep current (our) content from branchB we just checked out.
git merge -s ours branchA

# Set branchA to current commit and check it out.
git checkout -B branchA

Note that the merge commits first parent now is that from branchB and only the second is from branchA. This is what e.g. Gandalf458's answer does.

Use content from B only and keep correct parent order

This is the real "theirs version for git merge -s ours". It has the same content as in the option before (i.e. only that from branchB) but the order of parents is correct, i.e. the first parent comes from branchA and the second from branchB.

git checkout branchA

# Do a merge commit. The content of this commit does not matter,
# so use a strategy that never fails.
# Note: This advances branchA.
git merge -s ours branchB

# Change working tree and index to desired content.
# --detach ensures branchB will not move when doing the reset in the next step.
git checkout --detach branchB

# Move HEAD to branchA without changing contents of working tree and index.
git reset --soft branchA

# 'attach' HEAD to branchA.
# This ensures branchA will move when doing 'commit --amend'.
git checkout branchA

# Change content of merge commit to current index (i.e. content of branchB).
git commit --amend -C HEAD

This is what Paul Pladijs's answer does (without requiring a temporary branch).


I solved my problem using

git checkout -m old
git checkout -b new B
git merge -s ours old

I used the answer from Paul Pladijs since now. I found out, you can do a "normal" merge, conflicts occur, so you do

git checkout --theirs <file>

to resolve the conflict by using the revision from the other branch. If you do this for each file, you have the same behaviour as you would expect from

git merge <branch> -s theirs

Anyway, the effort is more than it would be with the merge-strategy! (This was tested with git version 1.8.0)


See Junio Hamano's widely cited answer: if you're going to discard committed content, just discard the commits, or at any rate keep it out of the main history. Why bother everyone in the future reading commit messages from commits that have nothing to offer?

But sometimes there are administrative requirements, or perhaps some other reason. For those situations where you really have to record commits that contribute nothing, you want:

(edit: wow, did I manage to get this wrong before. This one works.)

git update-ref HEAD $(
        git commit-tree -m 'completely superseding with branchB content' \
                        -p HEAD -p branchB    branchB:
)
git reset --hard

This will merge your newBranch in existing baseBranch

git checkout <baseBranch> // this will checkout baseBranch
git merge -s ours <newBranch> // this will simple merge newBranch in baseBranch
git rm -rf . // this will remove all non references files from baseBranch (deleted in newBranch)
git checkout newBranch -- . //this will replace all conflicted files in baseBranch

I solved my problem using

git checkout -m old
git checkout -b new B
git merge -s ours old

I just recently needed to do this for two separate repositories that share a common history. I started with:

  • Org/repository1 master
  • Org/repository2 master

I wanted all the changes from repository2 master to be applied to repository1 master, accepting all changes that repository2 would make. In git's terms, this should be a strategy called -s theirs BUT it does not exist. Be careful because -X theirs is named like it would be what you want, but it is NOT the same (it even says so in the man page).

The way I solved this was to go to repository2 and make a new branch repo1-merge. In that branch, I ran git pull [email protected]:Org/repository1 -s ours and it merges fine with no issues. I then push it to the remote.

Then I go back to repository1 and make a new branch repo2-merge. In that branch, I run git pull [email protected]:Org/repository2 repo1-merge which will complete with issues.

Finally, you would either need to issue a merge request in repository1 to make it the new master, or just keep it as a branch.


I just recently needed to do this for two separate repositories that share a common history. I started with:

  • Org/repository1 master
  • Org/repository2 master

I wanted all the changes from repository2 master to be applied to repository1 master, accepting all changes that repository2 would make. In git's terms, this should be a strategy called -s theirs BUT it does not exist. Be careful because -X theirs is named like it would be what you want, but it is NOT the same (it even says so in the man page).

The way I solved this was to go to repository2 and make a new branch repo1-merge. In that branch, I ran git pull [email protected]:Org/repository1 -s ours and it merges fine with no issues. I then push it to the remote.

Then I go back to repository1 and make a new branch repo2-merge. In that branch, I run git pull [email protected]:Org/repository2 repo1-merge which will complete with issues.

Finally, you would either need to issue a merge request in repository1 to make it the new master, or just keep it as a branch.


A possible and tested solution for merging branchB into our checked-out branchA:

# in case branchA is not our current branch
git checkout branchA

# make merge commit but without conflicts!!
# the contents of 'ours' will be discarded later
git merge -s ours branchB    

# make temporary branch to merged commit
git branch branchTEMP         

# get contents of working tree and index to the one of branchB
git reset --hard branchB

# reset to our merged commit but 
# keep contents of working tree and index
git reset --soft branchTEMP

# change the contents of the merged commit
# with the contents of branchB
git commit --amend

# get rid off our temporary branch
git branch -D branchTEMP

# verify that the merge commit contains only contents of branchB
git diff HEAD branchB

To automate it you can wrap it into a script using branchA and branchB as arguments.

This solution preserves the first and second parent of the merge commit, just as you would expect of git merge -s theirs branchB.


I used the answer from Paul Pladijs since now. I found out, you can do a "normal" merge, conflicts occur, so you do

git checkout --theirs <file>

to resolve the conflict by using the revision from the other branch. If you do this for each file, you have the same behaviour as you would expect from

git merge <branch> -s theirs

Anyway, the effort is more than it would be with the merge-strategy! (This was tested with git version 1.8.0)


I think what you actually want is:

git checkout -B mergeBranch branchB
git merge -s ours branchA
git checkout branchA
git merge mergeBranch
git branch -D mergeBranch

This seems clumsy, but it should work. The only think I really dislike about this solution is the git history will be confusing... But at least the history will be completely preserved and you won't need to do something special for deleted files.


A simple and intuitive (in my opinion) two-step way of doing it is

git checkout branchB .
git commit -m "Picked up the content from branchB"

followed by

git merge -s ours branchB

(which marks the two branches as merged)

The only disadvantage is that it does not remove files which have been deleted in branchB from your current branch. A simple diff between the two branches afterwards will show if there are any such files.

This approach also makes it clear from the revision log afterwards what was done - and what was intended.


Older versions of git allowed you to use the "theirs" merge strategy:

git pull --strategy=theirs remote_branch

But this has since been removed, as explained in this message by Junio Hamano (the Git maintainer). As noted in the link, instead you would do this:

git fetch origin
git reset --hard origin

Beware, though, that this is different than an actual merge. Your solution is probably the option you're really looking for.


This one uses a git plumbing command read-tree, but makes for a shorter overall workflow.

git checkout <base-branch>

git merge --no-commit -s ours <their-branch>
git read-tree -u --reset <their-branch>
git commit

# Check your work!
git diff <their-branch>

A possible and tested solution for merging branchB into our checked-out branchA:

# in case branchA is not our current branch
git checkout branchA

# make merge commit but without conflicts!!
# the contents of 'ours' will be discarded later
git merge -s ours branchB    

# make temporary branch to merged commit
git branch branchTEMP         

# get contents of working tree and index to the one of branchB
git reset --hard branchB

# reset to our merged commit but 
# keep contents of working tree and index
git reset --soft branchTEMP

# change the contents of the merged commit
# with the contents of branchB
git commit --amend

# get rid off our temporary branch
git branch -D branchTEMP

# verify that the merge commit contains only contents of branchB
git diff HEAD branchB

To automate it you can wrap it into a script using branchA and branchB as arguments.

This solution preserves the first and second parent of the merge commit, just as you would expect of git merge -s theirs branchB.


I think what you actually want is:

git checkout -B mergeBranch branchB
git merge -s ours branchA
git checkout branchA
git merge mergeBranch
git branch -D mergeBranch

This seems clumsy, but it should work. The only think I really dislike about this solution is the git history will be confusing... But at least the history will be completely preserved and you won't need to do something special for deleted files.


This will merge your newBranch in existing baseBranch

git checkout <baseBranch> // this will checkout baseBranch
git merge -s ours <newBranch> // this will simple merge newBranch in baseBranch
git rm -rf . // this will remove all non references files from baseBranch (deleted in newBranch)
git checkout newBranch -- . //this will replace all conflicted files in baseBranch

See Junio Hamano's widely cited answer: if you're going to discard committed content, just discard the commits, or at any rate keep it out of the main history. Why bother everyone in the future reading commit messages from commits that have nothing to offer?

But sometimes there are administrative requirements, or perhaps some other reason. For those situations where you really have to record commits that contribute nothing, you want:

(edit: wow, did I manage to get this wrong before. This one works.)

git update-ref HEAD $(
        git commit-tree -m 'completely superseding with branchB content' \
                        -p HEAD -p branchB    branchB:
)
git reset --hard

Older versions of git allowed you to use the "theirs" merge strategy:

git pull --strategy=theirs remote_branch

But this has since been removed, as explained in this message by Junio Hamano (the Git maintainer). As noted in the link, instead you would do this:

git fetch origin
git reset --hard origin

Beware, though, that this is different than an actual merge. Your solution is probably the option you're really looking for.


This one uses a git plumbing command read-tree, but makes for a shorter overall workflow.

git checkout <base-branch>

git merge --no-commit -s ours <their-branch>
git read-tree -u --reset <their-branch>
git commit

# Check your work!
git diff <their-branch>

If you are on branch A do:

git merge -s recursive -X theirs B

Tested on git version 1.7.8


Older versions of git allowed you to use the "theirs" merge strategy:

git pull --strategy=theirs remote_branch

But this has since been removed, as explained in this message by Junio Hamano (the Git maintainer). As noted in the link, instead you would do this:

git fetch origin
git reset --hard origin

Beware, though, that this is different than an actual merge. Your solution is probably the option you're really looking for.


To really properly do a merge which takes only input from the branch you are merging you can do

git merge --strategy=ours ref-to-be-merged

git diff --binary ref-to-be-merged | git apply --reverse --index

git commit --amend

There will be no conflicts in any scenario I know of, you don't have to make additional branches, and it acts like a normal merge commit.

This doesn't play nice with submodules however.


This answer was given by Paul Pladijs. I just took his commands and made a git alias for convenience.

Edit your .gitconfig and add the following:

[alias]
    mergetheirs = "!git merge -s ours \"$1\" && git branch temp_THEIRS && git reset --hard \"$1\" && git reset --soft temp_THEIRS && git commit --amend && git branch -D temp_THEIRS"

Then you can "git merge -s theirs A" by running:

git checkout B (optional, just making sure we're on branch B)
git mergetheirs A

It is not entirely clear what your desired outcome is, so there is some confusion about the "correct" way of doing it in the answers and their comments. I try to give an overview and see the following three options:

Try merge and use B for conflicts

This is not the "theirs version for git merge -s ours" but the "theirs version for git merge -X ours" (which is short for git merge -s recursive -X ours):

git checkout branchA
# also uses -s recursive implicitly
git merge -X theirs branchB

This is what e.g. Alan W. Smith's answer does.

Use content from B only

This creates a merge commit for both branches but discards all changes from branchA and only keeps the contents from branchB.

# Get the content you want to keep.
# If you want to keep branchB at the current commit, you can add --detached,
# else it will be advanced to the merge commit in the next step.
git checkout branchB

# Do the merge an keep current (our) content from branchB we just checked out.
git merge -s ours branchA

# Set branchA to current commit and check it out.
git checkout -B branchA

Note that the merge commits first parent now is that from branchB and only the second is from branchA. This is what e.g. Gandalf458's answer does.

Use content from B only and keep correct parent order

This is the real "theirs version for git merge -s ours". It has the same content as in the option before (i.e. only that from branchB) but the order of parents is correct, i.e. the first parent comes from branchA and the second from branchB.

git checkout branchA

# Do a merge commit. The content of this commit does not matter,
# so use a strategy that never fails.
# Note: This advances branchA.
git merge -s ours branchB

# Change working tree and index to desired content.
# --detach ensures branchB will not move when doing the reset in the next step.
git checkout --detach branchB

# Move HEAD to branchA without changing contents of working tree and index.
git reset --soft branchA

# 'attach' HEAD to branchA.
# This ensures branchA will move when doing 'commit --amend'.
git checkout branchA

# Change content of merge commit to current index (i.e. content of branchB).
git commit --amend -C HEAD

This is what Paul Pladijs's answer does (without requiring a temporary branch).


The equivalent(which keep parent order) to 'git merge -s theirs branchB'

Before merge:enter image description here

!!! Make sure you are in clean state !!!

Do the merge:

git commit-tree -m "take theirs" -p HEAD -p branchB 'branchB^{tree}'
git reset --hard 36daf519952 # is the output of the prev command

What we did ? We created a new commit which two parents ours and theirs and the contnet of the commit is branchB - theirs

After merge:enter image description here

More precisely:

git commit-tree -m "take theirs" -p HEAD -p 'SOURCE^{commit}' 'SOURCE^{tree}'

I solved my problem using

git checkout -m old
git checkout -b new B
git merge -s ours old

To really properly do a merge which takes only input from the branch you are merging you can do

git merge --strategy=ours ref-to-be-merged

git diff --binary ref-to-be-merged | git apply --reverse --index

git commit --amend

There will be no conflicts in any scenario I know of, you don't have to make additional branches, and it acts like a normal merge commit.

This doesn't play nice with submodules however.


When merging topic branch "B" in "A" using git merge, I get some conflicts. I >know all the conflicts can be solved using the version in "B".

I am aware of git merge -s ours. But what I want is something like git merge >-s their.

I'm assuming that you created a branch off of master and now want to merge back into master, overriding any of the old stuff in master. That's exactly what I wanted to do when I came across this post.

Do exactly what it is you want to do, Except merge the one branch into the other first. I just did this, and it worked great.

git checkout Branch
git merge master -s ours

Then, checkout master and merge your branch in it (it will go smoothly now):

git checkout master
git merge Branch

Older versions of git allowed you to use the "theirs" merge strategy:

git pull --strategy=theirs remote_branch

But this has since been removed, as explained in this message by Junio Hamano (the Git maintainer). As noted in the link, instead you would do this:

git fetch origin
git reset --hard origin

Beware, though, that this is different than an actual merge. Your solution is probably the option you're really looking for.


Why doesn't it exist?

While I mention in "git command for making one branch like another" how to simulate git merge -s theirs, note that Git 2.15 (Q4 2017) is now clearer:

The documentation for '-X<option>' for merges was misleadingly written to suggest that "-s theirs" exists, which is not the case.

See commit c25d98b (25 Sep 2017) by Junio C Hamano (gitster).
(Merged by Junio C Hamano -- gitster -- in commit 4da3e23, 28 Sep 2017)

merge-strategies: avoid implying that "-s theirs" exists

The description of -Xours merge option has a parenthetical note that tells the readers that it is very different from -s ours, which is correct, but the description of -Xtheirs that follows it carelessly says "this is the opposite of ours", giving a false impression that the readers also need to be warned that it is very different from -s theirs, which in reality does not even exist.

-Xtheirs is a strategy option applied to recursive strategy. This means that recursive strategy will still merge anything it can, and will only fall back to "theirs" logic in case of conflicts.

That debate for the pertinence or not of a theirs merge strategy was brought back recently in this Sept. 2017 thread.
It acknowledges older (2008) threads

In short, the previous discussion can be summarized to "we don't want '-s theirs' as it encourages the wrong workflow".

It mentions the alias:

mtheirs = !sh -c 'git merge -s ours --no-commit $1 && git read-tree -m -u $1' -

Yaroslav Halchenko tries to advocate once more for that strategy, but Junio C. Hamano adds:

The reason why ours and theirs are not symmetric is because you are you and not them---the control and ownership of our history and their history is not symmetric.

Once you decide that their history is the mainline, you'd rather want to treat your line of development as a side branch and make a merge in that direction, i.e. the first parent of the resulting merge is a commit on their history and the second parent is the last bad one of your history. So you would end up using "checkout their-history && merge -s ours your-history" to keep the first-parenthood sensible.

And at that point, use of "-s ours" is no longer a workaround for lack of "-s theirs".
It is a proper part of the desired semantics, i.e. from the point of view of the surviving canonical history line, you want to preserve what it did, nullifying what the other line of history did.

Junio adds, as commented by Mike Beaton:

git merge -s ours <their-ref> effectively says 'mark commits made up to <their-ref> on their branch as commits to be permanently ignored';
and this matters because, if you subsequently merge from later states of their branch, their later changes will be brought in without the ignored changes ever being brought in.


A simple and intuitive (in my opinion) two-step way of doing it is

git checkout branchB .
git commit -m "Picked up the content from branchB"

followed by

git merge -s ours branchB

(which marks the two branches as merged)

The only disadvantage is that it does not remove files which have been deleted in branchB from your current branch. A simple diff between the two branches afterwards will show if there are any such files.

This approach also makes it clear from the revision log afterwards what was done - and what was intended.


When merging topic branch "B" in "A" using git merge, I get some conflicts. I >know all the conflicts can be solved using the version in "B".

I am aware of git merge -s ours. But what I want is something like git merge >-s their.

I'm assuming that you created a branch off of master and now want to merge back into master, overriding any of the old stuff in master. That's exactly what I wanted to do when I came across this post.

Do exactly what it is you want to do, Except merge the one branch into the other first. I just did this, and it worked great.

git checkout Branch
git merge master -s ours

Then, checkout master and merge your branch in it (it will go smoothly now):

git checkout master
git merge Branch

I solved my problem using

git checkout -m old
git checkout -b new B
git merge -s ours old

Why doesn't it exist?

While I mention in "git command for making one branch like another" how to simulate git merge -s theirs, note that Git 2.15 (Q4 2017) is now clearer:

The documentation for '-X<option>' for merges was misleadingly written to suggest that "-s theirs" exists, which is not the case.

See commit c25d98b (25 Sep 2017) by Junio C Hamano (gitster).
(Merged by Junio C Hamano -- gitster -- in commit 4da3e23, 28 Sep 2017)

merge-strategies: avoid implying that "-s theirs" exists

The description of -Xours merge option has a parenthetical note that tells the readers that it is very different from -s ours, which is correct, but the description of -Xtheirs that follows it carelessly says "this is the opposite of ours", giving a false impression that the readers also need to be warned that it is very different from -s theirs, which in reality does not even exist.

-Xtheirs is a strategy option applied to recursive strategy. This means that recursive strategy will still merge anything it can, and will only fall back to "theirs" logic in case of conflicts.

That debate for the pertinence or not of a theirs merge strategy was brought back recently in this Sept. 2017 thread.
It acknowledges older (2008) threads

In short, the previous discussion can be summarized to "we don't want '-s theirs' as it encourages the wrong workflow".

It mentions the alias:

mtheirs = !sh -c 'git merge -s ours --no-commit $1 && git read-tree -m -u $1' -

Yaroslav Halchenko tries to advocate once more for that strategy, but Junio C. Hamano adds:

The reason why ours and theirs are not symmetric is because you are you and not them---the control and ownership of our history and their history is not symmetric.

Once you decide that their history is the mainline, you'd rather want to treat your line of development as a side branch and make a merge in that direction, i.e. the first parent of the resulting merge is a commit on their history and the second parent is the last bad one of your history. So you would end up using "checkout their-history && merge -s ours your-history" to keep the first-parenthood sensible.

And at that point, use of "-s ours" is no longer a workaround for lack of "-s theirs".
It is a proper part of the desired semantics, i.e. from the point of view of the surviving canonical history line, you want to preserve what it did, nullifying what the other line of history did.

Junio adds, as commented by Mike Beaton:

git merge -s ours <their-ref> effectively says 'mark commits made up to <their-ref> on their branch as commits to be permanently ignored';
and this matters because, if you subsequently merge from later states of their branch, their later changes will be brought in without the ignored changes ever being brought in.


If you are on branch A do:

git merge -s recursive -X theirs B

Tested on git version 1.7.8


This answer was given by Paul Pladijs. I just took his commands and made a git alias for convenience.

Edit your .gitconfig and add the following:

[alias]
    mergetheirs = "!git merge -s ours \"$1\" && git branch temp_THEIRS && git reset --hard \"$1\" && git reset --soft temp_THEIRS && git commit --amend && git branch -D temp_THEIRS"

Then you can "git merge -s theirs A" by running:

git checkout B (optional, just making sure we're on branch B)
git mergetheirs A