[c++] Pass by Reference / Value in C++

When passing by value:

void func(Object o);

and then calling

func(a);

you will construct an Object on the stack, and within the implementation of func it will be referenced by o. This might still be a shallow copy (the internals of a and o might point to the same data), so a might be changed. However if o is a deep copy of a, then a will not change.

When passing by reference:

void func2(Object& o);

and then calling

func2(a);

you will only be giving a new way to reference a. "a" and "o" are two names for the same object. Changing o inside func2 will make those changes visible to the caller, who knows the object by the name "a".

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