Java is not call by reference it is call by value only
But all variables of object type are actually pointers.
So if you use a Mutable Object you will see the behavior you want
public class XYZ {
public static void main(String[] arg) {
StringBuilder toyNumber = new StringBuilder("5");
play(toyNumber);
System.out.println("Toy number in main " + toyNumber);
}
private static void play(StringBuilder toyNumber) {
System.out.println("Toy number in play " + toyNumber);
toyNumber.append(" + 1");
System.out.println("Toy number in play after increement " + toyNumber);
}
}
Output of this code:
run:
Toy number in play 5
Toy number in play after increement 5 + 1
Toy number in main 5 + 1
BUILD SUCCESSFUL (total time: 0 seconds)
You can see this behavior in Standard libraries too. For example Collections.sort(); Collections.shuffle(); These methods does not return a new list but modifies it's argument object.
List<Integer> mutableList = new ArrayList<Integer>();
mutableList.add(1);
mutableList.add(2);
mutableList.add(3);
mutableList.add(4);
mutableList.add(5);
System.out.println(mutableList);
Collections.shuffle(mutableList);
System.out.println(mutableList);
Collections.sort(mutableList);
System.out.println(mutableList);
Output of this code:
run:
[1, 2, 3, 4, 5]
[3, 4, 1, 5, 2]
[1, 2, 3, 4, 5]
BUILD SUCCESSFUL (total time: 0 seconds)