How do I pass parameters to a jar file at the time of execution

Question

How do I pass parameters to a JAR file at the time of execution

User · Answer

java   options   -jar file jar   argument         if you need to pass the log4j properties file use the below option  -Dlog4j configurationFile directory file xml   java -Dlog4j configurationFile directory file xml -jar  lt JAR FILE gt   arguments

User · Answer

Incase arguments have spaces in it  you can pass like shown below  java -jar myjar jar  first argument   second argument

User · Answer

To pass arguments to the jar    java -jar myjar jar one two   You can access them in the main   method of  Main-Class   mentioned in the manifest mf file of a JAR     String one   args 0     String two   args 1

User · Answer

To pass arguments to the jar    java -jar myjar jar one two   You can access them in the main   method of  Main-Class   mentioned in the manifest mf file of a JAR     String one   args 0     String two   args 1

User · Answer

The JAVA Documentation says      java   options   -jar file jar     argument         and         Non-option arguments after the   class name or JAR file name are passed   to the main function      Maybe you have to put the arguments in single quotes

User · Answer

The JAVA Documentation says      java   options   -jar file jar     argument         and         Non-option arguments after the   class name or JAR file name are passed   to the main function      Maybe you have to put the arguments in single quotes

User · Answer

Incase arguments have spaces in it  you can pass like shown below  java -jar myjar jar  first argument   second argument

User · Answer

To pass arguments to the jar    java -jar myjar jar one two   You can access them in the main   method of  Main-Class   mentioned in the manifest mf file of a JAR     String one   args 0     String two   args 1

User · Answer

You can do it with something like this  so if no arguments are specified it will continue anyway   public static void main String   args        try           String one   args 0           String two   args 1             catch  ArrayIndexOutOfBoundsException e           System out println  ArrayIndexOutOfBoundsException caught              finally              And then launch the application   java -jar myapp jar arg1 arg2

User · Answer

The JAVA Documentation says      java   options   -jar file jar     argument         and         Non-option arguments after the   class name or JAR file name are passed   to the main function      Maybe you have to put the arguments in single quotes

User · Answer

The JAVA Documentation says      java   options   -jar file jar     argument         and         Non-option arguments after the   class name or JAR file name are passed   to the main function      Maybe you have to put the arguments in single quotes

User · Answer

java   options   -jar file jar   argument         if you need to pass the log4j properties file use the below option  -Dlog4j configurationFile directory file xml   java -Dlog4j configurationFile directory file xml -jar  lt JAR FILE gt   arguments

User · Answer

You can do it with something like this  so if no arguments are specified it will continue anyway   public static void main String   args        try           String one   args 0           String two   args 1             catch  ArrayIndexOutOfBoundsException e           System out println  ArrayIndexOutOfBoundsException caught              finally              And then launch the application   java -jar myapp jar arg1 arg2

User · Answer

To pass arguments to the jar    java -jar myjar jar one two   You can access them in the main   method of  Main-Class   mentioned in the manifest mf file of a JAR     String one   args 0     String two   args 1

[jar] How do I pass parameters to a jar file at the time of execution?

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