[javascript] Setting background-image using jQuery CSS property

I have an image URL in a imageUrl variable and I am trying to set it as CSS style, using jQuery:

$('myObject').css('background-image', imageUrl);

This seems to be not working, as:

console.log($('myObject').css('background-image'));

returns none.

Any idea, what I am doing wrong?

Here is my code:

$('body').css('background-image', 'url("/apo/1.jpg")');

Enjoy, friend

String interpolation to the rescue.

let imageUrl = 'imageurl.png';
$('myOjbect').css('background-image', `url(${imageUrl})`);

The problem I was having, is that I kept adding a semi-colon ; at the end of the url() value, which prevented the code from working.

? NOT WORKING CODE:

$('#image_element').css('background-image', 'url(http://example.com/img.jpg);');

? WORKING CODE:

$('#image_element').css('background-image', 'url(http://example.com/img.jpg)');

Notice the omitted semi-colon ; at the end in the working code. I simply didn't know the correct syntax, and it's really hard to notice it. Hopefully this helps someone else in the same boat.

Further to the other answers, you can also use "background". This is particularly useful when you want to set other properties relating to the way the image is used by the background, such as:

$("myObject").css("background", "transparent url('"+imageURL+"') no-repeat right top");

Don't forget that the jQuery css function allows objects to be passed which allows you to set multiple items at the same time. The answered code would then look like this:

$(this).css({'background-image':'url(' + imageUrl + ')'})

You'll want to include double quotes (") before and after the imageUrl like this:

$('myOjbect').css('background-image', 'url("' + imageUrl + '")');

This way, if the image has spaces it will still be set as a property.

For those using an actual URL and not a variable:

$('myObject').css('background-image', 'url(../../example/url.html)');

Further to the other answers, you can also use "background". This is particularly useful when you want to set other properties relating to the way the image is used by the background, such as:

$("myObject").css("background", "transparent url('"+imageURL+"') no-repeat right top");

Alternatively to what the others are correctly suggesting, I find it easier usually to toggle CSS classes, instead of individual CSS settings (especially background image URLs). For example:

// in CSS 
.bg1 
{
  background-image: url(/some/image/url/here.jpg);
}

.bg2 
{
  background-image: url(/another/image/url/there.jpg);
}

// in JS
// based on value of imageUrl, determine what class to remove and what class to add.
$('myOjbect').removeClass('bg1').addClass('bg2');

Try modifying the "style" attribute:

$('myObject').attr('style', 'background-image: url("' + imageUrl +'")');

Here is my code:

$('body').css('background-image', 'url("/apo/1.jpg")');

Enjoy, friend

Alternatively to what the others are correctly suggesting, I find it easier usually to toggle CSS classes, instead of individual CSS settings (especially background image URLs). For example:

// in CSS 
.bg1 
{
  background-image: url(/some/image/url/here.jpg);
}

.bg2 
{
  background-image: url(/another/image/url/there.jpg);
}

// in JS
// based on value of imageUrl, determine what class to remove and what class to add.
$('myOjbect').removeClass('bg1').addClass('bg2');

For those using an actual URL and not a variable:

$('myObject').css('background-image', 'url(../../example/url.html)');

Try modifying the "style" attribute:

$('myObject').attr('style', 'background-image: url("' + imageUrl +'")');

Don't forget that the jQuery css function allows objects to be passed which allows you to set multiple items at the same time. The answered code would then look like this:

$(this).css({'background-image':'url(' + imageUrl + ')'})

$('myObject').css({'background-image': 'url(imgUrl)',});

You'll want to include double quotes (") before and after the imageUrl like this:

$('myOjbect').css('background-image', 'url("' + imageUrl + '")');

This way, if the image has spaces it will still be set as a property.