[sql] Use '=' or LIKE to compare strings in SQL?

There's the (almost religious) discussion, if you should use LIKE or '=' to compare strings in SQL statements.

  • Are there reasons to use LIKE?
  • Are there reasons to use '='?
  • Performance? Readability?

This question is related to sql comparison

The answer is


Just as a heads up, the '=' operator will pad strings with spaces in Transact-SQL. So 'abc' = 'abc ' will return true; 'abc' LIKE 'abc ' will return false. In most cases '=' will be correct, but in a recent case of mine it was not.

So while '=' is faster, LIKE might more explicitly state your intentions.

http://support.microsoft.com/kb/316626


LIKE is used for pattern matching and = is used for equality test (as defined by the COLLATION in use).

= can use indexes while LIKE queries usually require testing every single record in the result set to filter it out (unless you are using full text search) so = has better performance.


There's a couple of other tricks that Postgres offers for string matching (if that happens to be your DB):

ILIKE, which is a case insensitive LIKE match:

select * from people where name ilike 'JOHN'

Matches:

  • John
  • john
  • JOHN

And if you want to get really mad you can use regular expressions:

select * from people where name ~ 'John.*'

Matches:

  • John
  • Johnathon
  • Johnny

LIKE does matching like wildcards char [*, ?] at the shell
LIKE '%suffix' - give me everything that ends with suffix. You couldn't do that with =
Depends on the case actually.


In my small experience:

"=" for Exact Matches.

"LIKE" for Partial Matches.


LIKE and the equality operator have different purposes, they don't do the same thing:
= is much faster, whereas LIKE can interpret wildcards. Use = wherever you can and LIKE wherever you must.

SELECT * FROM user WHERE login LIKE 'Test%';

Sample matches:

TestUser1
TestUser2
TestU
Test


For pattern matching use LIKE. For exact match =.


There is another reason for using "like" even if the performance is slower: Character values are implicitly converted to integer when compared, so:

declare @transid varchar(15)

if @transid != 0

will give you a "The conversion of the varchar value '123456789012345' overflowed an int column" error.