[python] Python + Django page redirect

How do I accomplish a simple redirect (e.g. cflocation in ColdFusion, or header(location:http://) for PHP) in Django?

page_path = define in urls.py

def deletePolls(request):
    pollId = deletePool(request.GET['id'])
    return HttpResponseRedirect("/page_path/")

There's actually a simpler way than having a view for each redirect - you can do it directly in urls.py:

from django.http import HttpResponsePermanentRedirect

urlpatterns = patterns(
    '',
    # ...normal patterns here...
    (r'^bad-old-link\.php',
     lambda request: HttpResponsePermanentRedirect('/nice-link')),
)

A target can be a callable as well as a string, which is what I'm using here.

You can do this in the Admin section. It's explained in the documentation.

https://docs.djangoproject.com/en/dev/ref/contrib/redirects/

If you want to redirect a whole subfolder, the url argument in RedirectView is actually interpolated, so you can do something like this in urls.py:

from django.conf.urls.defaults import url
from django.views.generic import RedirectView

urlpatterns = [
    url(r'^old/(?P<path>.*)$', RedirectView.as_view(url='/new_path/%(path)s')),
]

The ?P<path> you capture will be fed into RedirectView. This captured variable will then be replaced in the url argument you gave, giving us /new_path/yay/mypath if your original path was /old/yay/mypath.

You can also do ….as_view(url='…', query_string=True) if you want to copy the query string over as well.

Since Django 1.1, you can also use the simpler redirect shortcut:

from django.shortcuts import redirect

def myview(request):
    return redirect('/path')

It also takes an optional permanent=True keyword argument.

With Django version 1.3, the class based approach is:

from django.conf.urls.defaults import patterns, url
from django.views.generic import RedirectView

urlpatterns = patterns('',
    url(r'^some-url/$', RedirectView.as_view(url='/redirect-url/'), name='some_redirect'),
)

This example lives in in urls.py

This should work in most versions of django, I am using it in 1.6.5:

from django.core.urlresolvers import reverse
from django.http import HttpResponseRedirect
urlpatterns = patterns('',
    ....
    url(r'^(?P<location_id>\d+)/$', lambda x, location_id: HttpResponseRedirect(reverse('dailyreport_location', args=[location_id])), name='location_stats_redirect'),
    ....
)

You can still use the name of the url pattern instead of a hard coded url with this solution. The location_id parameter from the url is passed down to the lambda function.

Depending on what you want (i.e. if you do not want to do any additional pre-processing), it is simpler to just use Django's redirect_to generic view:

from django.views.generic.simple import redirect_to

urlpatterns = patterns('',
    (r'^one/$', redirect_to, {'url': '/another/'}),

    #etc...
)

See documentation for more advanced examples.

For Django 1.3+ use:

from django.views.generic import RedirectView

urlpatterns = patterns('',
    (r'^one/$', RedirectView.as_view(url='/another/')),
)

Beware. I did this on a development server and wanted to change it later.

• Firefox 5 'caching' 301 redirects

I had to clear my caches to change it. In order to avoid this head-scratching in the future, I was able to make it temporary like so:

from django.views.generic import RedirectView

url(r'^source$', RedirectView.as_view(permanent=False, 
                                      url='/dest/')),