As per the HTML:
<html>
<body>
<p class="content">Link1.</p>
</body>
<html>
<html>
<body>
<p class="content">Link2.</p>
</body>
<html>
Two(2) <p> elements are having the same class content.
So to filter the elements having the same class i.e. content and create a list you can use either of the following Locator Strategies:
Using class_name:
elements = driver.find_elements_by_class_name("content")
Using css_selector:
elements = driver.find_elements_by_css_selector(".content")
Using xpath:
elements = driver.find_elements_by_xpath("//*[@class='content']")
Ideally, to click on the element you need to induce WebDriverWait for the visibility_of_all_elements_located() and you can use either of the following Locator Strategies:
Using CLASS_NAME:
elements = WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.CLASS_NAME, "content")))
Using CSS_SELECTOR:
elements = WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.CSS_SELECTOR, ".content")))
Using XPATH:
elements = WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//*[@class='content']")))
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
You can find a couple of relevant discussions in: