[asp.net-mvc] How do I redirect to the previous action in ASP.NET MVC?

For ASP.NET Core You can use asp-route-* attribute:

<form asp-action="Login" asp-route-previous="@Model.ReturnUrl">

Other in details example: Imagine that you have a Vehicle Controller with actions

Index

Details

Edit

and you can edit any vehicle from Index or from Details, so if you clicked edit from index you must return to index after edit and if you clicked edit from details you must return to details after edit.

//In your viewmodel add the ReturnUrl Property
public class VehicleViewModel
{
     ..............
     ..............
     public string ReturnUrl {get;set;}
}



Details.cshtml
<a asp-action="Edit" asp-route-previous="Details" asp-route-id="@Model.CarId">Edit</a>

Index.cshtml
<a asp-action="Edit" asp-route-previous="Index" asp-route-id="@item.CarId">Edit</a>

Edit.cshtml
<form asp-action="Edit" asp-route-previous="@Model.ReturnUrl" class="form-horizontal">
        <div class="box-footer">
            <a asp-action="@Model.ReturnUrl" class="btn btn-default">Back to List</a>
            <button type="submit" value="Save" class="btn btn-warning pull-right">Save</button>
        </div>
    </form>

In your controller:

// GET: Vehicle/Edit/5
    public ActionResult Edit(int id,string previous)
    {
            var model = this.UnitOfWork.CarsRepository.GetAllByCarId(id).FirstOrDefault();
            var viewModel = this.Mapper.Map<VehicleViewModel>(model);//if you using automapper
    //or by this code if you are not use automapper
    var viewModel = new VehicleViewModel();

    if (!string.IsNullOrWhiteSpace(previous)
                viewModel.ReturnUrl = previous;
            else
                viewModel.ReturnUrl = "Index";
            return View(viewModel);
        }



[HttpPost]
    public IActionResult Edit(VehicleViewModel model, string previous)
    {
            if (!string.IsNullOrWhiteSpace(previous))
                model.ReturnUrl = previous;
            else
                model.ReturnUrl = "Index";
            ............. 
            .............
            return RedirectToAction(model.ReturnUrl);
    }

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