How to get the filename without the extension in Java

Question

Can anyone tell me how to get the filename without the extension  Example   fileNameWithExt    test xml   fileNameWithOutExt    test

User · Answer

Simplest way to get name from relative path or full path is using   import org apache commons io FilenameUtils  FilenameUtils getBaseName definitionFilePath

User · Answer

If your project uses Guava  14 0 or newer   you can go with Files getNameWithoutExtension      Essentially the same as FilenameUtils removeExtension   from Apache Commons IO  as the highest-voted answer suggests  Just wanted to point out Guava does this too  Personally I didn t want to add dependency to Commons   which I feel is a bit of a relic   just because of this

User · Answer

The easiest way is to use a regular expression   fileNameWithOutExt    test xml  replaceFirst                     The above expression will remove the last dot followed by one or more characters   Here s a basic unit test   public void testRegex         assertEquals  test    test xml  replaceFirst                        assertEquals  test 2    test 2 xml  replaceFirst

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The fluent way   public static String fileNameWithOutExt  String fileName        return Optional of fileName lastIndexOf       filter i- gt  i  gt   0               map i- gt  fileName substring 0  i   orElse fileName

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If you  like me  would rather use some library code where they probably have thought of all special cases  such as what happens if you pass in null or dots in the path but not in the filename  you can use the following   import org apache commons io FilenameUtils  String fileNameWithOutExt   FilenameUtils removeExtension fileNameWithExt

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If you don t like to import the full apache commons  I ve extracted the same functionality   public class StringUtils       public static String getBaseName String filename            return removeExtension getName filename               public static int indexOfLastSeparator String filename            if filename    null                return -1            else               int lastUnixPos   filename lastIndexOf 47               int lastWindowsPos   filename lastIndexOf 92               return Math max lastUnixPos  lastWindowsPos                        public static String getName String filename            if filename    null                return null            else               int index   indexOfLastSeparator filename               return filename substring index   1                        public static String removeExtension String filename            if filename    null                return null            else               int index   indexOfExtension filename               return index    -1 filename filename substring 0  index                        public static int indexOfExtension String filename            if filename    null                return -1            else               int extensionPos   filename lastIndexOf 46               int lastSeparator   indexOfLastSeparator filename               return lastSeparator  gt  extensionPos -1 extensionPos

User · Answer

Keeping it simple  use Java s String replaceAll   method as follows   String fileNameWithExt    test xml   String fileNameWithoutExt      fileNameWithExt replaceAll                                       1       This also works when fileNameWithExt includes the fully qualified path

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You can use java split function to split the filename from the extension  if you are sure there is only one dot in the filename which for extension    File filename   new File  test txt     File getName   split           so the split 0  will return  test  and split 1  will return  txt

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My solution needs the following import  import java io File   The following method should return the desired output string  private static String getFilenameWithoutExtension File file  throws IOException       String filename   file getCanonicalPath        String filenameWithoutExtension      if  filename contains  quot   quot            filenameWithoutExtension   filename substring filename lastIndexOf System getProperty  quot file separator quot    1  filename lastIndexOf            else         filenameWithoutExtension   filename substring filename lastIndexOf System getProperty  quot file separator quot    1        return filenameWithoutExtension

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For Kotlin it s now simple as  val fileNameStr   file nameWithoutExtension

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public static String getFileExtension String fileName            if  TextUtils isEmpty fileName      fileName contains         fileName endsWith       return null          return fileName substring fileName lastIndexOf        1              public static String getBaseFileName String fileName            if  TextUtils isEmpty fileName      fileName contains         fileName endsWith       return null          return fileName substring 0 fileName lastIndexOf

User · Answer

Try the code below  Using core Java basic functions  It takes care of Strings with extension  and without extension  without the     character   The case of multiple     is also covered   String str    filename xml   if   str contains            System out println  File Name     str    else       str   str substring 0  str lastIndexOf               Because extension is always after the last         System out println  File Name     str       You can adapt it to work with null strings

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While I am a big believer in reusing libraries  the org apache commons io JAR is 174KB  which is noticably large for a mobile app     If you download the source code and take a look at their FilenameUtils class  you can see there are a lot of extra utilities  and it does cope with Windows and Unix paths  which is all lovely   However  if you just want a couple of static utility methods for use with Unix style paths  with a     separator   you may find the code below useful     The removeExtension method preserves the rest of the path along with the filename   There is also a similar getExtension          Remove the file extension from a filename  that may include a path         e g   path to myfile jpg - gt   path to myfile      public static String removeExtension String filename        if  filename    null            return null             int index   indexOfExtension filename        if  index    -1            return filename        else           return filename substring 0  index                   Return the file extension from a filename  including the            e g   path to myfile jpg - gt   jpg     public static String getExtension String filename        if  filename    null            return null             int index   indexOfExtension filename        if  index    -1            return filename        else           return filename substring index            private static final char EXTENSION SEPARATOR        private static final char DIRECTORY SEPARATOR         public static int indexOfExtension String filename         if  filename    null            return -1                Check that no directory separator appears after the         EXTENSION SEPARATOR     int extensionPos   filename lastIndexOf EXTENSION SEPARATOR        int lastDirSeparator   filename lastIndexOf DIRECTORY SEPARATOR        if  lastDirSeparator  gt  extensionPos            LogIt w FileSystemUtil class   A directory separator appears after the file extension  assuming there is no file extension            return -1             return extensionPos

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Here is the consolidated list order by my preference  Using apache commons import org apache commons io FilenameUtils   String fileNameWithoutExt   FilenameUtils getBaseName fileName                                                         OR  String fileNameWithOutExt   FilenameUtils removeExtension fileName    Using Google Guava  If u already using it  import com google common io Files  String fileNameWithOutExt   Files getNameWithoutExtension fileName    Files getNameWithoutExtension Or using Core Java 1  String fileName   file getName    int pos   fileName lastIndexOf  quot   quot    if  pos  gt  0  amp  amp  pos  lt   fileName length   - 1        If     is not the first or last character      fileName   fileName substring 0  pos         if  fileName indexOf  quot   quot    gt  0       return fileName substring 0  fileName lastIndexOf  quot   quot       else      return fileName        private static final Pattern ext   Pattern compile  quot    lt              quot     public static String getFileNameWithoutExtension File file        return ext matcher file getName    replaceAll  quot  quot       Liferay API import com liferay portal kernel util FileUtil   String fileName   FileUtil stripExtension file getName

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Below is reference from https   android googlesource com platform tools tradefederation   master src com android tradefed util FileUtil java         Gets the base name  without extension  of given file name      lt p  gt     e g  getBaseName  file txt   will return  file         param fileName     return the base name     public static String getBaseName String fileName        int index   fileName lastIndexOf           if  index    -1            return fileName        else           return fileName substring 0  index

User · Answer

Use FilenameUtils removeExtension from Apache Commons IO  Example   You can provide full path name or only the file name   String myString1   FilenameUtils removeExtension  helloworld exe       returns  helloworld  String myString2   FilenameUtils removeExtension   home abc yey xls       returns  yey    Hope this helps

User · Answer

You can split it by     and on index 0 is file name and on 1 is extension  but I would incline for the best solution with FileNameUtils from apache commons-io like it was mentioned in the first article  It does not have to be removed  but sufficent is   String fileName   FilenameUtils getBaseName  test xml

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See the following test program   public class javatemp       static String stripExtension  String str               Handle null case specially           if  str    null  return null              Get position of last               int pos   str lastIndexOf                   If there wasn t any     just return the string as is           if  pos    -1  return str              Otherwise return the string  up to the dot           return str substring 0  pos              public static void main String   args            System out println   test xml   - gt      stripExtension   test xml             System out println   test 2 xml - gt      stripExtension   test 2 xml             System out println   test       - gt      stripExtension   test             System out println   test       - gt      stripExtension   test                which outputs   test xml   - gt  test test 2 xml - gt  test 2 test       - gt  test test       - gt  test

[java] How to get the filename without the extension in Java?

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