How to replace all occurrences of a string in Javascript

Question

I have this string in my Javascript code   quot Test abc test test abc test test test abc test test abc quot   Doing  str   str replace  abc         seems to only remove the first occurrence of abc in the string above  How can I replace all occurrences of it

User · Answer

For the sake of completeness  I got to thinking about which method I should use to do this  There are basically two ways to do this as suggested by the other answers on this page   Note  In general  extending the built-in prototypes in JavaScript is generally not recommended  I am providing as extensions on the String prototype simply for purposes of illustration  showing different implementations of a hypothetical standard method on the String built-in prototype     Regular Expression Based Implementation  String prototype replaceAll   function search  replacement        var target   this      return target replace new RegExp search   g    replacement        Split and Join  Functional  Implementation  String prototype replaceAll   function search  replacement        var target   this      return target split search  join replacement          Not knowing too much about how regular expressions work behind the scenes in terms of efficiency  I tended to lean toward the split and join implementation in the past without thinking about performance  When I did wonder which was more efficient  and by what margin  I used it as an excuse to find out   On my Chrome Windows nbsp 8 machine  the regular expression based implementation is the fastest  with the split and join implementation being 53  slower  Meaning the regular expressions are twice as fast for the lorem ipsum input I used   Check out this benchmark running these two implementations against each other     As noted in the comment below by  ThomasLeduc and others  there could be an issue with the regular expression-based implementation if search contains certain characters which are reserved as special characters in regular expressions  The implementation assumes that the caller will escape the string beforehand or will only pass strings that are without the characters in the table in Regular Expressions  MDN    MDN also provides an implementation to escape our strings  It would be nice if this was also standardized as RegExp escape str   but alas  it does not exist   function escapeRegExp str      return str replace                     g       amp          amp  means the whole matched string     We could call escapeRegExp within our String prototype replaceAll implementation  however  I m not sure how much this will affect the performance  potentially even for strings for which the escape is not needed  like all alphanumeric strings

User · Answer

Use Split and Join  x000D   x000D  var str    Test abc test test abc test test test abc test test abc   var replaced str   str split  abc   join      console log replaced str   x000D   x000D   x000D

User · Answer

loop it until number occurrences comes to 0  OR simply copy paste      function replaceAll find  replace  str               while  str indexOf find   gt  -1                  str   str replace find  replace                 return str

User · Answer

The previous answers are way too complicated  Just use the replace function like this   str replace  your regex pattern g  replacement string     Example    x000D   x000D  var str    Test abc test test abc test test test abc test test abc   x000D   x000D  var res   str replace   abc   g       x000D   x000D  console log res   x000D   x000D   x000D

User · Answer

Although people have mentioned the use of regex but there s a better approach if you want to replace the text irrespective of the case of the text  Like uppercase or lowercase  Use below syntax    Consider below example originalString replace  stringToBeReplaced gi          Output will be all the occurrences removed irrespective of casing    You can refer the detailed example here

User · Answer

Try this   String prototype replaceAll   function  sfind  sreplace        var str   this       while  str indexOf sfind   gt  -1            str   str replace sfind  sreplace              return str

User · Answer

Check this  I m sure it will help you    lt  DOCTYPE html gt   lt html gt   lt body gt   lt p gt Click the button to do a global search and replace for  is  in a string  lt  p gt   lt button onclick  myFunction    gt Try it lt  button gt   lt p id  demo  gt  lt  p gt   lt script gt  function myFunction       var str    Is this  3  dris  3       var allvar    3      var patt1   new RegExp  allvar   g       document getElementById  demo   innerHTML   str replace patt1   5        lt  script gt   lt  body gt   lt  html gt    Here is the JSFiddle link

User · Answer

You can simply use below method         Replace all the occerencess of  find by  replace in  originalString     param   originalString  input - Raw string      param   find  input - Target key word or regex that need to be replaced      param   replace  input - Replacement key word     return  String        Output string     function replaceAll originalString  find  replace      return originalString replace new RegExp find   g    replace

User · Answer

You can try like this  Example data  var text    quot heloo hai hei quot   text   text replace       g       or text forEach  value    gt      hasil   hasil replace

User · Answer

As of August 2020 there is a Stage 4 proposal to ECMAScript that adds the replaceAll method to String  It s now supported in Chrome 85   Edge 85   Firefox 77   Safari 13 1   The usage is the same as the replace method  String prototype replaceAll searchValue  replaceValue   Here s an example usage   Test abc test test abc test   replaceAll  abc    foo       - gt   Test foo test test foo test     It s supported in most modern browsers  but there exist polyfills   core-js es-shims  It is supported in the V8 engine behind an experimental flag --harmony-string-replaceall  Read more on the V8 website

User · Answer

This is the fastest version that doesn t use regular expressions   Revised jsperf  replaceAll   function string  omit  place  prevstring      if  prevstring  amp  amp  string     prevstring      return string    prevstring   string replace omit  place     return replaceAll prevstring  omit  place  string      It is almost twice as fast as the split and join method   As pointed out in a comment here  this will not work if your omit variable contains place  as in  replaceAll  string    s    ss    because it will always be able to replace another occurrence of the word   There is another jsperf with variants on my recursive replace that go even faster  http   jsperf com replace-all-vs-split-join 12     Update July 27th 2017  It looks like RegExp now has the fastest performance in the recently released Chrome 59

User · Answer

There is a way to use the new  quot replaceAll quot  function  But you need to use a cutting-edge browser or a javascript run time environment  you can check the browser compatibility in here

User · Answer

For unique replaceable values   x000D   x000D  String prototype replaceAll   function search array  replacement array    x000D       x000D    var target   this  x000D       x000D    search array forEach function substr  index    x000D      if  typeof replacement array index      undefined     x000D        target   target replace new RegExp substr   g    replacement array index   x000D        x000D        x000D       x000D    return target  x000D     x000D   x000D      Use  x000D  var replacedString    This topic commented on  year  Talking  question   replaceAll    year     question      2018    How to replace all occurrences of a string in JavaScript     x000D     x000D  console log replacedString   x000D   x000D   x000D

User · Answer

If using a library is an option for you then you will get the benefits of the testing and community support that goes with a library function  For example  the string js library has a replaceAll   function that does what you re looking for      Include a reference to the string js library and call it  for example  S  str   S str  replaceAll  abc       s

User · Answer

Update  In the latest versions of most popular browsers  you can use replaceAll as shown here  let result    quot 1 abc 2 abc 3 quot  replaceAll  quot abc quot    quot xyz quot        result  is  quot 1 xyz 2 xyz 3 quot   But check Can I use or another compatibility table first to make sure the browsers you re targeting have added support for it first   For Node and compatibility with older non-current browsers  Note  Don t use the following solution in performance critical code  As an alternative to regular expressions for a simple literal string  you could use str    quot Test abc test test abc test    quot  split  quot abc quot   join  quot  quot     The general pattern is str split search  join replacement   This used to be faster in some cases than using replaceAll and a regular expression  but that doesn t seem to be the case anymore in modern browsers  Benchmark  https   jsperf com replace-all-vs-split-join Conclusion  If you have a performance critical use case  e g processing hundreds of strings   use the Regexp method  But for most typical use cases  this is well worth not having to worry about special characters

User · Answer

Replacing single quotes   function JavaScriptEncode text       text   text replace    g   amp apos           More encode here if required      return text

User · Answer

function replaceAll str  find  replace        var  r         while  r  str             r   str          str   str replace find  replace             return str

User · Answer

If the string contain similar pattern like abccc  you can use this   str replace  abc  s    g

User · Answer

If you are trying to ensure that the string you are looking for won t exist even after the replacement  you need to use a loop   For example   var str    test aabcbc   str   str replace  abc g         When complete  you will still have  test abc    The simplest loop to solve this would be   var str    test aabcbc   while  str    str replace  abc g           str replace  abc g           But that runs the replacement twice for each cycle  Perhaps  at risk of being voted down  that can be combined for a slightly more efficient but less readable form   var str    test aabcbc   while  str     str   str replace  abc g             alert str   alerts  test      This can be particularly useful when looking for duplicate strings  For example  if we have  a   b  and we wish to remove all duplicate commas   In that case  one could do  replace     g       but at some point the regex gets complex and slow enough to loop instead

User · Answer

Say you want to replace all the  abc  with  x    let some str    abc def def lom abc abc def  split  abc   join  x   console log some str    x def def lom x x def   I was trying to think about something more simple than modifying the string prototype

User · Answer

Performance Today 27 12 2019 I perform tests on macOS v10 13 6  High Sierra  for the chosen solutions  Conclusions  The str replace  abc g        C  is a good cross-browser fast solution for all strings  Solutions based on split-join  A B  or replace  C D  are fast Solutions based on while  E F G H  are slow - usually  4 times slower for small strings and about  3000 times     slower for long strings The recurrence solutions  RA RB  are slow and do not work for long strings  I also create my own solution  It looks like currently it is the shortest one which does the question job  str split abc  join     x000D   x000D  str    Test abc test test abc test test test abc test test abc   str   str split abc  join    console log str   x000D   x000D   x000D   Details The tests were performed on Chrome 79 0  Safari 13 0 4 and Firefox 71 0  64 bit   The tests RA and RB use recursion  Results  Short string - 55 characters You can run tests on your machine HERE  Results for Chrome   Long string  275 000 characters The recursive solutions RA and RB gives  RangeError  Maximum call stack size exceeded  For 1M characters they even break Chrome  I try to perform tests for 1M characters for other solutions  but E F G H takes so much time that browser ask me to break script so I shrink test string to 275K characters  You can run tests on your machine HERE  Results for Chrome  Code used in tests  x000D   x000D  var t  Test abc test test abc test test test abc test test abc       repeat 5000  var log    version result    gt  console log    version     result       function A str      return str split  abc   join         function B str      return str split abc  join       my proposition     function C str      return str replace  abc g          function D str      return str replace new RegExp  abc    g            function E str      while  str indexOf  abc       -1    str   str replace  abc            return str     function F str      while  str indexOf  abc       -1    str   str replace  abc            return str     function G str      while str includes  abc      str   str replace  abc            return str        src  https   stackoverflow com a 56989553 860099 function H str        let i   -1     let find    abc       let newToken            if   str                if   str    null   amp  amp   find    null   return newToken          return str             while            i   str indexOf              find  i  gt   0   i   newToken length   0                -1                     str   str substring 0  i                newToken               str substring i   find length             return str        src  https   stackoverflow com a 22870785 860099 function RA string  prevstring      var omit    abc     var place         if  prevstring  amp  amp  string     prevstring      return string    prevstring   string replace omit  place     return RA prevstring  string        src  https   stackoverflow com a 26107132 860099 function RB str      var find    abc     var replace         var i   str indexOf find     if  i  gt  -1       str   str replace find  replace       i   i   replace length      var st2   str substring i       if st2 indexOf find   gt  -1         str   str substring 0 i    RB st2  find  replace               return str        log  A    A t    log  B    B t    log  C    C t    log  D    D t    log  E    E t    log  F    F t    log  G    G t    log  H    H t    log  RA   RA t       use reccurence log  RB   RB t       use reccurence x000D   lt p style  color red  gt This snippet only presents codes used in tests  It not perform test itself  lt p gt  x000D   x000D   x000D

User · Answer

I would suggest adding a global method for string class by appending it to prototype chain  String prototype replaceAll   function fromReplace  toReplace   ignoreCasing          return this replace new RegExp fromReplace  ignoreCasing    ig    g    toReplace     and it can be used like  stringwithpattern  replaceAll  pattern   new-pattern

User · Answer

We can use the replace method in JavaScript   var result   yourString replace  regexPattern    replaceString       x000D   x000D  var str    Test abc test test abc test test test abc test test abc   x000D   x000D  var expectedString   str replace  abc  s    g       x000D   x000D  console log expectedString   x000D   x000D   x000D

User · Answer

The following function works for me   String prototype replaceAllOccurence   function str1  str2  ignore        return this replace new RegExp str1 replace                                        lt   gt  -  amp    g      amp     ignore  gi   g     typeof str2    string   str2 replace     g         str2         Now call the functions like this    you could be a Project Manager someday  if you work like this   replaceAllOccurence   you    I      Simply copy and paste this code in your browser console to TEST

User · Answer

If what you want to find is already in a string  and you don t have a regex escaper handy  you can use join split    x000D   x000D      function replaceMulti haystack  needle  replacement  x000D        x000D          return haystack split needle  join replacement   x000D        x000D   x000D      someString    the cat looks like a cat   x000D      console log replaceMulti someString   cat    dog     x000D   x000D   x000D

User · Answer

function replaceAll str  find  replace      var i   str indexOf find     if  i  gt  -1       str   str replace find  replace        i   i   replace length      var st2   str substring i       if st2 indexOf find   gt  -1         str   str substring 0 i    replaceAll st2  find  replace                      return str

User · Answer

In string first element search and replace    x000D   x000D  var str       id  1  name   karthikeyan a   type   developer     x000D  var i   str replace           replace            x000D  console log i    first element search and replace   x000D   x000D   x000D    In string global search and replace    x000D   x000D  var str       id  1  name   karthikeyan a   type   developer     x000D  var j   str replace       g      replace       g       x000D  console log j    global search and replace   x000D   x000D   x000D

User · Answer

I added the function below to this perf test page in the  library  section   https   jsben ch LFfWA  function  replace t  s  r       var i   t indexOf s       if  i    -1  return t      return t slice 0  i    r    replace t slice i   s length  t length   s r         and put this in as the test   var replaced    replace testString   abc   123         and that function performs about 34  faster for me than split or regex  The idea   hope was to end up pasting smaller and smaller pieces of the string onto the stack and then building the entire result by unrolling the stack  thereby minimizing extra string copies and extra searches through the same string data and hopefully optimizing use of the CPU cache   Part of the thought was that if the string isn t too big  it may end up in the CPU cache  passing it and pasting pieces of it puts those bits into the cache  and then the searching can operate entirely using CPU cached data  Now whether or not that s actually what ends up happening I m sure is entirely js implementation dependant   This isn t as fast as possible  but it s as fast as I could manage without mutable strings  Arrays in JavaScript probably have a pointer for each element  so  a solution involving a lot of array elements is not likely to be as CPU cache friendly as this

User · Answer

The simplest solution -   x000D   x000D  let str    Test abc test test abc test test test abc test test abc   x000D   x000D  str   str split       x000D  str   str filter  ele  key   gt  ele    abc   x000D  str   str join      x000D   x000D   x000D    Or simply -   x000D   x000D  str   str split      filter  ele  key    gt  ele     abc   join      x000D   x000D   x000D

User · Answer

var myName    r  i  n  o  l    d     var myValidName   myName replace new RegExp         g          gt     rinold   console log myValidName    var myPetName    manidog   var renameManiToJack   myPetName replace new RegExp  mani    g     jack     gt     jackdog

User · Answer

These are the most common and readable methods   var str    Test abc test test abc test test test abc test test abc    Method 1   str   str replace  abc g   replaced text      Method 2   str   str split  abc   join  replaced text      Method 3   str   str replace new RegExp  abc    g     replaced text      Method 4   while str includes  abc         str   str replace  abc    replaced text        Output   console log str      Test replaced text test test replaced text test test test replaced text test test replaced text

User · Answer

Using a regular expression with the g flag set will replace all   someString    the cat looks like a cat   anotherString   someString replace  cat g   dog       anotherString now contains  the dog looks like a dog    See here also

User · Answer

In November 2019 a new feature is added to the JavaScript string prototype replaceAll     Currently it s only supported with babel JS  but maybe in the future it can be implemented in all the browsers  For more information  read here

User · Answer

Most people are likely doing this to encode a URL  To encode a URL  you shouldn t only consider spaces  but convert the entire string properly with encodeURI   encodeURI  http   www google com a file with spaces html     to get   http   www google com a 20file 20with 20spaces html

User · Answer

This can be achieved using regular expressions  A few combinations that might help someone   var word    this     is a test       and    only        a   test    var stri    This      is    a test         and only a        test     To replace all non alpha characters   console log word replace     a-z   g      replace     g          Result   this is a test and only a test    To replace multiple continuous spaces with one space   console log stri replace      g         Result   This is a test and only a test    To replace all   characters   console log word replace     g        Result   this    isatest       and    only        a  test     To replace question marks      console log word replace     g         Result   this    is a test       and    only        a  test     To replace quotation marks   console log word replace    g          Result   this    is a test       and    only        a  test     To replace all   characters   console log word replace    g        Result   this   is a test      and    only        a  test     To replace a specific word   console log word replace  test g        Result   this    is a        and    only        a       To replace back-slash   console log word replace     g         Result   this   is a test       and    only        a  test     To replace forward slash   console log word replace     g         Result   this    is a test       and   only       a  test     To replace all spaces   console log word replace    g          Result   this    is a test       and    only        a  test     To replace dots   console log word replace     g         Result   this    is a test       and    only        a  test

User · Answer

In my apps  I use a custom function that is the most powerful for this purpose  and even wrapping the split join solution in the simpler case  it is a little bit faster in Chrome 60and Firefox 54   JSBEN CH  than other solutions  My computer runs Windows 7 64 bits   The advantage is that this custom function can handle many substitutions at the same time using strings or characters  which can be a shortcut for some applications   Like a split join above solution  the solution below has no problem with escape characters  differently than regular expression approach     function replaceAll s find repl caseOff byChar     if  arguments length lt 2   return false     var destDel     repl           if destDel delete all keys from target   var isString      byChar       if byChar  replace set of characters    if  typeof find    typeof repl  amp  amp    destDel   return false     if  isString   amp  amp    typeof find    string      return false      if    isString  amp  amp    typeof find    string           return s split find  join destDel    repl          if     isString    amp  amp       Array isArray find                   Array isArray repl   amp  amp    destDel        return false           if destOne replace all strings characters by just one element   var destOne   destDel   false    repl length   1               Generally source and destination should have the same size   if    destOne  amp  amp    destDel  amp  amp  find length   repl length   return false        var prox sUp findUp i done       if  caseOff           case insensitive               Working with uppercase keys and target      sUp   s toUpperCase           if  isString         findUp   find toUpperCase          else        findUp   find map function el    return el toUpperCase                else               case sensitive      sUp   s       findUp  find slice        clone array string          done   new Array find length       size  number of keys   done fill null                    var pos   0           initial position in target s   var r            initial result   var aux  winner    while  pos  lt  s length              Scanning the target      prox    Number MAX SAFE INTEGER       winner   -1      no winner at start      for  i 0 i lt findUp length i         find next occurence for each string        if  done i    -1          key still alive                 Never search for the word char or is over           if  done i    null    done i  lt pos                 aux   sUp indexOf findUp i  pos              done i  aux      Save the next occurrence            else            aux   done i       restore the position of last search          if  aux lt prox  amp  amp  aux   -1         if next occurrence is minimum            winner   i         save it              prox   aux                            not done        if  winner   -1         No matches forward          r    s slice pos               break             no winner           found the character or string key in the target        i   winner      restore the winner       r    s slice pos prox        update piece before the match                 Append the replacement in target        if    destDel  r    repl  destOne 0 i            pos   prox     isString 1 findUp i  length             go after match          loop   return r      return the resulting string     The documentation is below              replaceAll      Syntax                        replaceAll s find   repl  caseOff  byChar         Parameters                          s  is a string target of replacement          find  can be a string or array of strings           repl  should be the same type than  find  or empty         if  find  is a string  it is a simple replacement for           all  find  occurrences in  s  by string  repl         if  find  is an array  it will replaced each string in  find          that occurs in  s  for corresponding string in  repl  array    The replace specs are independent  A replacement part cannot         be replaced again       if  repl  is empty all  find  occurrences in  s  will be deleted       if  repl  has only one character or element            all occurrences in  s  will be replaced for that one         caseOff  is true if replacement is case insensitive              default is FALSE      byChar  is true when replacement is based on set of characters        Default is false       if  byChar   it will be replaced in  s  all characters in  find       set of characters for corresponding character in   repl    set of characters      Return                 the function returns the new string after the replacement       To be fair  I ran the benchmark with no parameter test    Here is my test set  using Node js  function l     return console log apply null  arguments      var k 0  l   k replaceAll  banana is a ripe fruit harvested near the river           ri   nea     do   fa         1 l   k replaceAll  banana is a ripe fruit harvested near the river           ri   nea     do         2 l   k replaceAll  banana is a ripe fruit harvested near the river           ri   nea         3 l   k replaceAll  banana is a ripe fruit harvested near the river         aeiou        true       4 l   k replaceAll  banana is a ripe fruit harvested near the river          aeiou   a     true       5 l   k replaceAll  banana is a ripe fruit harvested near the river          aeiou   uoiea     true       6 l   k replaceAll  banana is a ripe fruit harvested near the river          aeiou   uoi     true       7 l   k replaceAll  banana is a ripe fruit harvested near the river           ri   nea     do   fa   leg         8 l   k replaceAll  BANANA IS A RIPE FRUIT HARVESTED NEAR THE RIVER           ri   nea     do   fa         9 l   k replaceAll  BANANA IS A RIPE FRUIT HARVESTED NEAR THE RIVER           ri   nea     do   fa   true      10 return    And the results      1  banana is a dope fruit harvested far the dover    2  banana is a dope fruit harvested dor the dover    3  banana is a pe fruit harvested r the ver    4  bnn s  rp frt hrvstd nr th rvr    5  banana as a rapa fraat harvastad naar tha ravar    6  bununu is u ripo frait hurvostod nour tho rivor    7 false   8 false   9  BANANA IS A RIPE FRUIT HARVESTED NEAR THE RIVER    10  BANANA IS A doPE FRUIT HARVESTED faR THE doVER

User · Answer

Here s a string prototype function based on the accepted answer   String prototype replaceAll   function  find  replace        var str   this      return str replace new RegExp find   g    replace        EDIT   If your find will contain special characters then you need to escape them   String prototype replaceAll   function  find  replace        var str   this      return str replace new RegExp find replace   -                    g       amp      g    replace        Fiddle  http   jsfiddle net cdbzL

User · Answer

This can be solved using regular expressions and the flag g  which means to not stop after finding the first match  Really  regular expressions are life savers   function replaceAll string  pattern  replacement        return string replace new RegExp pattern   g    replacement         or if you want myString replaceAll  abc         String prototype replaceAll   function pattern  replacement        return this replace new RegExp pattern   g    replacement

User · Answer

For replacing all kind of characters  try this code   Suppose we have need to send   and   in my string  then we will convert it   to    and   to      So this method will solve this issue   String prototype replaceAll   function  find  replace         var str   this       return str replace new RegExp find replace   -                    g       amp      g    replace        var message       message   val                 message   message replaceAll                  it will replace   to                    message   message replaceAll                  it will replace   to         I was using Ajax  and I had the need to send parameters in JSON format  Then my method is looking like this    function sendMessage source  messageID  toProfileID  userProfileID          if  validateTextBox               var message       message   val             message   message replaceAll                         message   message replaceAll                         ajax                type   POST                async   false                contentType   application json  charset utf-8                url   services WebService1 asmx SendMessage                data     source       source       messageID       messageID       toProfileID       toProfileID       userProfileID       userProfileID       message       message                      dataType   json                success  function  data                     loadMessageAfterSend toProfileID  userProfileID                         lt   PanelMessageDelete ClientID  gt    hide                         message   val                           delMessageContainer   show                         msgPanel   show                                 error  function  result                     alert  message sending failed                                            else            alert  Please type message in message box                  message   focus                 String prototype replaceAll   function  find  replace         var str   this       return str replace new RegExp find replace   -                    g       amp      g    replace

User · Answer

For replacing a single time use   var res   str replace  abc          For replacing multiple times use   var res   str replace  abc g

User · Answer

The best solution  in order to replace any character we use the indexOf    includes    and substring   functions to replace the matched string with the provided string in the current string    The String indexOf   function is to find the nth match index position  The String includes   method determines whether one string may be found within another string  returning true or false as appropriate  String substring   function is to get the parts of String preceding exceding   Add the replace String in-between these parts to generate final return String    The following function allows to use any character  where as RegExp will not allow some special character like    and some characters need to be escaped  like     String prototype replaceAllMatches   function obj       Obj format     matchkey     replaceStr        var retStr   this      for  var x in obj              var matchArray   retStr match new RegExp x   ig               for  var i   0  i  lt  matchArray length  i              var prevIndex   retStr indexOf x      matchkey        replaceStr        While loop never ends          while  retStr includes x                 retStr   retStr replaceMatch x  obj x   0               var replaceIndex   retStr indexOf x               if  replaceIndex  lt   prevIndex    obj x   length                    break                else                   prevIndex   replaceIndex                                    return retStr     String prototype replaceMatch   function matchkey  replaceStr  matchIndex        var retStr   this  repeatedIndex   0        var matchArray   retStr match new RegExp matchkey   ig           for  var x   0  x  lt  matchArray length  x          for  var x   0   matchkey    null   amp  amp   retStr indexOf matchkey   gt  -1   x              if  repeatedIndex    0  amp  amp  x    0                repeatedIndex   retStr indexOf matchkey             else      matchIndex  gt  0             repeatedIndex   retStr indexOf matchkey  repeatedIndex   1                     if  x    matchIndex                retStr   retStr substring 0  repeatedIndex    replaceStr   retStr substring repeatedIndex    matchkey length                matchkey   null     To break the loop                      return retStr         We can also use the regular expression object for matching text with a pattern  The following are functions which will use the regular expression object   You will get SyntaxError when you are using an invalid regular expression pattern like         The String replace   function is used to replace the specified String with the given String  The String match   function is to find how many time the string is repeated  The RegExp prototype test method executes a search for a match between a regular expression and a specified string  Returns true or false    String prototype replaceAllRegexMatches   function obj       Obj format     matchkey     replaceStr        var retStr   this      for  var x in obj            retStr   retStr replace new RegExp x   ig    obj x              return retStr          Note that regular expressions are written without quotes      Examples to use the above functions   var str    yash yas  dfdas      console log  String     str       No need to escape any special character console log  Index matched replace     str replaceMatch  as        2    console log  Index Matched replace     str replaceMatch  y        1    console log  All Matched replace     str replaceAllMatches   as          y   Y        -      console log  All Matched replace      str replaceAllMatches                    amp   amp      amp              gt           You need to escape some special Characters console log  REGEX all matched replace     str replaceAllRegexMatches   as           y   Y          -        Result   String   yash yas  dfdas    Index Matched replace   yash yas  dfd     Index Matched replace   yash  as  dfdas     All Matched replace   Y  h Y   -dfd      All Matched replace   yash yas    dfdas  gt  gt   REGEX All Matched replace   Y  h Y   -dfd

User · Answer

Starting from v85  chrome now supports String prototype replaceAll natively  Note this outperform all other proposed solutions and should be used once majorly supported  Feature status  https   chromestatus com feature 6040389083463680  x000D   x000D  var s    hello hello world   s   s replaceAll  hello           s is now  world  console log s  x000D   x000D   x000D

User · Answer

The simplest way to this without using any regex is split and join like the code here   x000D   x000D  var str    Test abc test test abc test test test abc test test abc   console log str split  abc   join       x000D   x000D   x000D

User · Answer

Using RegExp in JavaScript could do the job for you  just simply do something like below code  don t forget the  g after which standout for global   var str   Test abc test test abc test test test abc test test abc   str   str replace  abc g         If you think of reuse  create a function to do that for you  but it s not recommended as it s only one line function  but again if you heavily use this  you can write something like this   String prototype replaceAll   String prototype replaceAll    function string  replaced      return this replace new RegExp string   g    replaced        and simply use it in your code over and over like below   var str   Test abc test test abc test test test abc test test abc   str   str replaceAll  abc          But as I mention earlier  it won t make a huge difference in terms of lines to be written or performance  only caching the function may effect some faster performance on long strings and also a good practice of DRY code if you want to reuse

User · Answer

You can do it without Regex  but you need to be careful if the replacement text contains the search text    e g    replaceAll  nihIaohi    hI    hIcIaO   true    So here is a proper variant of replaceAll  including string-prototype   function replaceAll str  find  newToken  ignoreCase        let i   -1       if   str                   Instead of throwing  act as COALESCE if find    null empty and str    null         if   str    null   amp  amp   find    null               return newToken           return str             if   find     sanity check          return str       ignoreCase   ignoreCase    false      find   ignoreCase   find toLowerCase     find       while            i    ignoreCase   str toLowerCase     str  indexOf              find  i  gt   0   i   newToken length   0                -1                     str   str substring 0  i                newToken               str substring i   find length            Whend       return str      Or  if you want to have a string-prototype function    String prototype replaceAll   function  find  replace        let str   this       let i   -1       if   str                   Instead of throwing  act as COALESCE if find    null empty and str    null         if   str    null   amp  amp   find    null               return newToken           return str             if   find     sanity check          return str       ignoreCase   ignoreCase    false      find   ignoreCase   find toLowerCase     find       while            i    ignoreCase   str toLowerCase     str  indexOf              find  i  gt   0   i   newToken length   0                -1                     str   str substring 0  i                newToken               str substring i   find length            Whend       return str

User · Answer

Here is the working code with prototype   String prototype replaceAll   function find  replace        var str   this      return str replace new RegExp find replace                             g      1     g    replace

User · Answer

str    Test abc test test abc test test test abc test test abc   str split      join   replace  abc g     replace    g

User · Answer

Here s very simple solution  You can assign a new method to String object String prototype replaceAll   function search  replace      return this replace new RegExp search   g    replace     var str    quot Test abc test test abc test test test abc test test abc quot   str   str replaceAll  abc         console log str     - gt  Test  test test  test test test  test test

User · Answer

Use a regular expression   str replace  abc g

User · Answer

while  str indexOf  abc       -1        str   str replace  abc

User · Answer

Match against a global regular expression   anotherString   someString replace  cat g   dog

User · Answer

Method 1  Try to implement a regular expression    Test abc test test abc test test test abc test test abc  replace   abc g         Method 2  Split and join  Split with abc and join with empty space    Test abc test test abc test test test abc test test abc  split  abc   join

User · Answer

I use split and join or this funcion  function replaceAll  text  busca  reemplaza      while  text toString   indexOf busca     -1        text   text toString   replace busca reemplaza     return text

User · Answer

As of August 2020  greenfield browsers have support for the String replaceAll   method defined by the ECMAScript 2021 language specification  For older legacy browser support  the below still applies   str   str replace  abc g        In response to comment  var find    abc   var re   new RegExp find   g     str   str replace re        In response to Click Upvote s comment  you could simplify it even more  function replaceAll str  find  replace      return str replace new RegExp find   g    replace      Note  Regular expressions contain special  meta  characters  and as such it is dangerous to blindly pass an argument in the find function above without pre-processing it to escape those characters   This is covered in the Mozilla Developer Network s JavaScript Guide on Regular Expressions  where they present the following utility function  which has changed at least twice since this answer was originally written  so make sure to check the MDN site for potential updates   function escapeRegExp string      return string replace       -               g       amp          amp  means the whole matched string    So in order to make the replaceAll   function above safer  it could be modified to the following if you also include escapeRegExp  function replaceAll str  find  replace      return str replace new RegExp escapeRegExp find    g    replace

User · Answer

I just want to share my solution  based on some of the functional features of last versions of JavaScript      var str    Test abc test test abc test test test abc test test abc       var result   str split      reduce  a  b    gt          return b     abc    a   a         b          console warn result

User · Answer

In August 2020  No more regular expression stuff   x000D   x000D  const str    Test abc test test abc test test test abc test test abc   const modifiedStr   str replaceAll  abc        console log modifiedStr   x000D   x000D   x000D   https   developer mozilla org en-US docs Web JavaScript Reference Global Objects String replaceAll

User · Answer

I like this method  it looks a little cleaner    text   text replace new RegExp  cat   g     dog

User · Answer

var str    ff ff f f a de def   str   str replace  f g      alert str     http   jsfiddle net ANHR9

User · Answer

There is now a finished proposal for integrating String prototype replaceAll into the official specification  Eventually  developers will not have to come up with their own implementations for replaceAll - instead  modern Javascript engines will support it natively  The proposal is at stage 4  which means that everything is complete  and all that s left is for browsers to start implementing it  It has shipped in the latest versions of Chrome  Firefox  and Safari  Here are the implementation details   Per the current TC39 consensus  String prototype replaceAll behaves identically to String prototype replace in all cases  except for the following two cases   If searchValue is a string  String prototype replace only replaces a single occurrence of the searchValue  whereas String prototype replaceAll replaces all occurrences of the searchValue  as if  split searchValue  join replaceValue  or a global  amp  properly-escaped regular expression had been used   If searchValue is a non-global regular expression  String prototype replace replaces a single match  whereas String prototype replaceAll throws an exception  This is done to avoid the inherent confusion between the lack of a global flag  which implies  quot do NOT replace all quot   and the name of the method being called  which strongly suggests  quot replace all quot     Notably  String prototype replaceAll behaves just like String prototype replace if searchValue is a global regular expression   You can see a spec-compliant polyfill here  In supported environments  the following snippet will log foo-bar-baz  without throwing an error   x000D   x000D  const str    foo bar baz   console log    str replaceAll       -      x000D   x000D   x000D

User · Answer

My implementation  very self explanatory  function replaceAll string  token  newtoken        if token  newtoken      while string indexOf token   gt  -1            string   string replace token  newtoken             return string

User · Answer

This solution combines some previous answers and conforms somewhat better to the proposed August 2020 standard solution  This solution is still viable for me in September 2020  as String replaceAll is not available in the node binary I am using   RegExp escape is a separate issue to deal with  but is important here because the official proposed solution will automatically escape string-based find input  This String replaceAll polyfill would not without the RegExp escape logic  I have added an answer which doesn t polyfill RegExp Escape  in the case that you don t want that   If you pass a RegExp to find  you MUST include g as a flag  This polyfill won t provide a nice TypeError for you and will cause you a major bad time  If you need exact standards conformance  for an application which is rigorously relying on the standard implementation  then I suggest using babel or some other tool to get you the  right answer  every time instead of SO dot com  That way you won t have any surprises   Code  if   Object prototype hasOwnProperty call RegExp   escape        RegExp escape   function string           https   developer mozilla org en-US docs Web JavaScript Guide Regular Expressions Escaping        https   github com benjamingr RegExp escape issues 37     return string replace       -               g       amp          amp  means the whole matched string         if   Object prototype hasOwnProperty call String   replaceAll        String prototype replaceAll   function find  replace           https   developer mozilla org en-US docs Web JavaScript Reference Global Objects String replaceAll        If you pass a RegExp to  find   you  MUST  include  g  as a flag         TypeError   quot replaceAll must be called with a global RegExp quot  not included  will silently cause significant errors   MUST  include  g  as a flag for RegExp         String parameters to  find  do not require special handling         Does not conform to  quot special replacement patterns quot  when  quot Specifying a string as a parameter quot  for replace        Does not conform to  quot Specifying a function as a parameter quot  for replace     return this replace            Object prototype toString call find       object RegExp                 find               new RegExp RegExp escape find    g              replace                   Code  Minified  Object prototype hasOwnProperty call RegExp  quot escape quot     RegExp escape function e  return e replace       -               g  quot     amp  quot     Object prototype hasOwnProperty call String  quot replaceAll quot     String prototype replaceAll function e t  return this replace  quot  object RegExp  quot   Object prototype toString call e  e new RegExp RegExp escape e   quot g quot   t       Example  console log     t  STVAL       replaceAll        new RegExp RegExp escape  T  ST     ig           TEST            console log     t  STVAL       replaceAll         t  ST          TEST              Code without RegExp Escape  if   Object prototype hasOwnProperty call String   replaceAll        String prototype replaceAll   function find  replace           https   developer mozilla org en-US docs Web JavaScript Reference Global Objects String replaceAll        If you pass a RegExp to  find   you  MUST  include  g  as a flag         TypeError   quot replaceAll must be called with a global RegExp quot  not included  will silently cause significant errors   MUST  include  g  as a flag for RegExp         String parameters to  find  do not require special handling         Does not conform to  quot special replacement patterns quot  when  quot Specifying a string as a parameter quot  for replace        Does not conform to  quot Specifying a function as a parameter quot  for replace     return this replace            Object prototype toString call find       object RegExp                 find               new RegExp find replace       -               g       amp      g              replace                   Code without RegExp Escape  Minified  Object prototype hasOwnProperty call String  quot replaceAll quot     String prototype replaceAll function e t  return this replace  quot  object RegExp  quot   Object prototype toString call e  e new RegExp e replace       -               g  quot     amp  quot    quot g quot   t

User · Answer

In terms of performance related to the main answers these are some online tests   While the following are some performance tests using console time    they work best in your own console  the time is very short to be seen in the snippet    x000D   x000D  console time  split and join    x000D   javascript-test-find-and-replace-all  split  -   join       x000D  console timeEnd  split and join   x000D   x000D  console time  regular expression    x000D   javascript-test-find-and-replace-all  replace new RegExp  -    g          x000D  console timeEnd  regular expression    x000D   x000D  console time  while    x000D  let str1    javascript-test-find-and-replace-all   x000D  while  str1 indexOf  -       -1    x000D      str1   str1 replace  -         x000D    x000D  console timeEnd  while    x000D   x000D   x000D    The interesting thing to notice is that if you run them multiple time the results are always different even though the RegExp solution seems the fastest on average and the while loop solution the slowest

User · Answer

str   str replace new RegExp  abc    g           worked better for me than the above answers  so new RegExp  abc    g   creates a RegExp what matches all occurence   g  flag  of the text   abc    The second part is what gets replaced to  in your case empty string       str is the string  and we have to override it  as replace      just returns result  but not overrides  In some cases you might want to use that

User · Answer

This should work   String prototype replaceAll   function  search  replacement        var str1   this replace search  replacement       var str2   this      while str1    str2            str2   str1          str1   str1 replace search  replacement             return str1      Example   Console log  Steve is the best character in Minecraft  replaceAll  Steve    Alex

User · Answer

I know this isnt the best way to do this  but you can try this   var annoyingString    Test abc test test abc test test test abc test test abc    while  annoyingString includes  abc          annoyingString   annoyingString replace  abc

User · Answer

Just add  g   document body innerHTML   document body innerHTML replace  hello    hi      to     Replace  hello  string with  hello g regular expression  document body innerHTML   document body innerHTML replace  hello g   hi       g means global

User · Answer

Check this answer may it will help and I used in my project   function replaceAll searchString  replaceString  str       return str split searchString  join replaceString     replaceAll  abc       Test abc test test abc test test test abc test test abc         Test  test test  test test test  test test

User · Answer

All the answers are accepted  you can do this by many ways  One of the trick to do this is this    x000D   x000D   const str    Test abc test test abc test test test abc test test abc   x000D       x000D      const compare    abc   x000D      arrayStr   str split       x000D      arrayStr forEach  element  index    gt    x000D        if  element    compare    x000D          arrayStr splice index  1   x000D          x000D          x000D      const newString   arrayStr join       x000D      console log newString   x000D   x000D   x000D

User · Answer

str   str replace  abc g         Or try the replaceAll function from here   What are useful JavaScript methods that extends built-in objects   str   str replaceAll  abc        OR  var search    abc   str   str replaceAll search         EDIT  Clarification about replaceAll availability  The  replaceAll  method is added to String s prototype  This means it will be available for all string objects literals   E g   var output    test this  replaceAll  this    that       output is  test that   output   output replaceAll  that    this      output is  test this

User · Answer

I use p to store the result from the previous recursion replacement   function replaceAll s  m  r  p        return s     p    r contains m    s   replaceAll s replace m  r   m  r  s       It will replace all occurrences in the string s until it is possible   replaceAll  abbbbb    ab    a      abbbb     abbb     abb     ab     a    To avoid infinite loop I check if the replacement r contains a match m   replaceAll  abbbbb    a    ab      abbbbb

User · Answer

Update   It s somewhat late for an update  but since I just stumbled on this question  and noticed that my previous answer is not one I m happy with  Since the question involved replaceing a single word  it s incredible nobody thought of using word boundaries   b    a cat is not a caterpillar  replace   bcat b gi  dog       a dog is not a caterpillar    This is a simple regex that avoids replacing parts of words in most cases  However  a dash - is still considered a word boundary  So conditionals can be used in this case to avoid replacing strings like cool-cat    a cat is not a cool-cat  replace   bcat b gi  dog     wrong    a dog is not a cool-dog  -- nips  a cat is not a cool-cat  replace      b   -   cat    b   -    gi   1dog 2       a dog is not a cool-cat      basically  this question is the same as the question here  Javascript replace  quot    39   quot  with  quot    39   39   quot    Mike  check the answer I gave there    regexp isn t the only way to replace multiple occurrences of a subsrting  far from it  Think flexible  think split   var newText    the cat looks like a cat  split  cat   join  dog      Alternatively  to prevent replacing word parts -which the approved answer will do  too  You can get around this issue using regular expressions that are  I admit  somewhat more complex and as an upshot of that  a tad slower  too   var regText    the cat looks like a cat  replace          a-z       a-z      cat cat     a-z   gi   1dog      The output is the same as the accepted answer  however  using the  cat g expression on this string   var oops    the cat looks like a cat  not a caterpillar or coolcat  replace  cat g  dog      returns  the dog looks like a dog  not a dogerpillar or cooldog        Oops indeed  this probably isn t what you want  What is  then  IMHO  a regex that only replaces  cat  conditionally   ie not part of a word   like so   var caterpillar    the cat looks like a cat  not a caterpillar or coolcat  replace          a-z       a-z      cat cat     a-z   gi   1dog      return  the dog looks like a dog  not a caterpillar or coolcat    My guess is  this meets your needs  It s not fullproof  of course  but it should be enough to get you started  I d recommend reading some more on these pages  This ll prove useful in perfecting this expression to meet your specific needs   http   www javascriptkit com jsref regexp shtml  http   www regular-expressions info    Final addition   Given that this question still gets a lot of views  I thought I might add an example of  replace used with a callback function  In this case  it dramatically simplifies the expression and provides even more flexibility  like replacing with correct capitalisation or replacing both cat and cats in one go    Two cats are not 1 Cat  They  re just cool-cats  you caterpillar      replace       b  cat  s  b     gi function all char1 cat char2                 check 1st  capitalize if required        var replacement    cat charAt 0       C     D     d      og          if  char1          amp  amp  char2      s             replace plurals  too            cat   replacement    s                   else           do not replace if dashes are matched            cat   char1      -     char2      -    cat   replacement                  return char1   cat   char2   return replacement string           returns    Two dogs are not 1 Dog  They re just cool-cats  you caterpillar

[javascript] How to replace all occurrences of a string in Javascript?

Regular Expression Based Implementation

Split and Join (Functional) Implementation

Examples related to javascript

Examples related to string

Examples related to replace