[javascript] jQuery: more than one handler for same event

What happens if I bind two event handlers to the same event for the same element?

For example:

var elem = $("...")
elem.click(...);
elem.click(...);

Does the last handler "win", or will both handlers be run?

jQuery's .bind() fires in the order it was bound:

When an event reaches an element, all handlers bound to that event type for the element are fired. If there are multiple handlers registered, they will always execute in the order in which they were bound. After all handlers have executed, the event continues along the normal event propagation path.

Source: http://api.jquery.com/bind/

Because jQuery's other functions (ex. .click()) are shortcuts for .bind('click', handler), I would guess that they are also triggered in the order they are bound.

jquery will execute both handler since it allows multiple event handlers. I have created sample code. You can try it

demo

Both handlers get called.

You may be thinking of inline event binding (eg "onclick=..."), where a big drawback is only one handler may be set for an event.

jQuery conforms to the DOM Level 2 event registration model:

The DOM Event Model allows registration of multiple event listeners on a single EventTarget. To achieve this, event listeners are no longer stored as attribute values

You should be able to use chaining to execute the events in sequence, e.g.:

$('#target')
  .bind('click',function(event) {
    alert('Hello!');
  })
  .bind('click',function(event) {
    alert('Hello again!');
  })
  .bind('click',function(event) {
    alert('Hello yet again!');
  });

I guess the below code is doing the same

$('#target')
      .click(function(event) {
        alert('Hello!');
      })
      .click(function(event) {
        alert('Hello again!');
      })
      .click(function(event) {
        alert('Hello yet again!');
      });

Source: http://www.peachpit.com/articles/article.aspx?p=1371947&seqNum=3

TFM also says:

When an event reaches an element, all handlers bound to that event type for the element are fired. If there are multiple handlers registered, they will always execute in the order in which they were bound. After all handlers have executed, the event continues along the normal event propagation path.

Suppose that you have two handlers, f and g, and want to make sure that they are executed in a known and fixed order, then just encapsulate them:

$("...").click(function(event){
  f(event);
  g(event);
});

In this way there is (from the perspective of jQuery) only one handler, which calls f and g in the specified order.

There is a workaround to guarantee that one handler happens after another: attach the second handler to a containing element and let the event bubble up. In the handler attached to the container, you can look at event.target and do something if it's the one you're interested in.

Crude, maybe, but it definitely should work.

Made it work successfully using the 2 methods: Stephan202's encapsulation and multiple event listeners. I have 3 search tabs, let's define their input text id's in an Array:

var ids = new Array("searchtab1", "searchtab2", "searchtab3");

When the content of searchtab1 changes, I want to update searchtab2 and searchtab3. Did it this way for encapsulation:

for (var i in ids) {
    $("#" + ids[i]).change(function() {
        for (var j in ids) {
            if (this != ids[j]) {
                $("#" + ids[j]).val($(this).val());
            }
        }
    });
}

Multiple event listeners:

for (var i in ids) {
    for (var j in ids) {
        if (ids[i] != ids[j]) {
            $("#" + ids[i]).change(function() {
                $("#" + ids[j]).val($(this).val());
            });
        }
    }
}

I like both methods, but the programmer chose encapsulation, however multiple event listeners worked also. We used Chrome to test it.