Python Remove last 3 characters of a string

Question

I m trying to remove the last 3 characters from a string in python  I don t know what these characters are so I can t use rstrip  I also need to remove any white space and convert to upper-case  an example would be   foo    Bs12 3ab  foo replace          rstrip foo -3    upper     This works and gives me BS12 which is what I want  however if the last 4th  amp  3rd characters are the same I loose both eg if foo    BS11 1AA  I just get  BS   examples of foo could be   BS1 1AB bs11ab BS111ab   The string could be 6 or 7 characters and I need to drop the last 3  assuming no white space   Any tips

User · Answer

split  slice concentrate   This is a good workout for beginners and it s easy to achieve   Another advanced method is a function like this   def trim s       return trim s slice     And for this question  you just want to remove the last characters  so you can write like this   def trim s       return s    -3     I think you are over to care about what those three characters are  so you lost  You just want to remove last three  nevertheless who they are   If you want to remove some specific characters  you can add some if judgements   def trim s       if  conditions         for some cases  I recommend using isinstance            return trim s slice

User · Answer

You might have misunderstood rstrip slightly  it strips not a string but any character in the string you specify   Like this    gt  gt  gt  text    xxxxcbaabc   gt  gt  gt  text rstrip  abc    xxxx    So instead  just use   text   text  -3      after replacing whitespace with nothing

User · Answer

Aren t you performing the operations in the wrong order  You requirement seems to be foo  -3  replace          upper

User · Answer

It doesn t work as you expect because strip is character based  You need to do this instead   foo   foo replace           -3  upper

User · Answer

It some what depends on your definition of whitespace  I would generally call whitespace to be spaces  tabs  line breaks and carriage returns  If this is your definition you want to use a regex with  s to replace all whitespace charactors   import re  def myCleaner foo       print  dirty     foo     foo   re sub r  s       foo      foo   foo  -3      foo   foo upper       print  clean    foo     print  myCleaner  BS1 1AB   myCleaner  bs11ab   myCleaner  BS111ab

User · Answer

Removing any and all whitespace   foo      join foo split      Removing last three characters   foo   foo  -3    Converting to capital letters   foo   foo upper     All of that code in one line   foo      join foo split     -3  upper

User · Answer

gt  gt  gt  foo    BS1 1AB   gt  gt  gt  foo replace          rstrip    -3  upper    BS1

User · Answer

I try to avoid regular expressions  but this appears to work   string   re sub   s      string lower      -3

User · Answer

What s wrong with this   foo replace           -3  upper

User · Answer

gt  gt  gt  foo    Bs12 3ab   gt  gt  gt  foo  -3   Bs12    gt  gt  gt  foo  -3  strip    Bs12   gt  gt  gt  foo  -3  strip   replace          Bs12   gt  gt  gt  foo  -3  strip   replace         upper    BS12

[python] Python Remove last 3 characters of a string

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